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TFW 56*26 PM382H19.34 - Level 2Unansyeicdattempts leftWhich statement concerning alkenes is falsedA trans alkene releases less heat upon hydrogenation than cis alke...

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TFW 56*26 PM382H19.34 - Level 2Unansyeicdattempts leftWhich statement concerning alkenes is falsedA trans alkene releases less heat upon hydrogenation than cis alkene.A cumulated diene is less stable than an isolated diene.Multiple products can always form when a conjugated diene is treated with HBr:Conjugated systems arise only between spz ~hybridized atoms.Conjugated double bonds involve unhybridized ~orbitals aligned with each otherSubmit

TFW 5 6*26 PM 382 H19.34 - Level 2 Unansyeicd attempts left Which statement concerning alkenes is falsed A trans alkene releases less heat upon hydrogenation than cis alkene. A cumulated diene is less stable than an isolated diene. Multiple products can always form when a conjugated diene is treated with HBr: Conjugated systems arise only between spz ~hybridized atoms. Conjugated double bonds involve unhybridized ~orbitals aligned with each other Submit



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Each question in this section has four suggested answers out of which ONE OR MORE answers will be correct. Which of the following statements is correct? (a) Cyclopropane will react with chlorine or bromine at room temperature, in diffused light to give a dihalogen derivative. (b) A hydrocarbon of molecular formula $\mathrm{C}_{4} \mathrm{H}_{6}$ should contain always a triple bond. (c) The trans isomer of an alkene is generally less polar than the cis isomer. (d) $\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}$ is an example of cumulated diene.

Okay. It's rescue for most for the compounds or the akin's A. BNC. So all of my the formula C. Six, H. 12, but B and C. Can be assistant trans ice Merce. So if we put the are keen on carbon too and we draw the assistant trans I summers. She was drawing back in first and then on the left of the method group. And on the right we have this three carbon gina here to the species because they're on the same Salvador bond. And then we also get trans isometsa. Be comparing this. If we put the Our keen on carbon 3-1 2 and three we get these ice MERS. It's on the left of an ethnic group. And on the right we have a um ethel was gone. Just put in the effort down here. The other one up here 123456. Okay, so we're told that be produces two alcohols. And um this would have to be compound B because if you look at the reaction, we react two vaccine with water and sulfuric acid. So it's gonna put an alcohol. The first step is the Elkins going deeper into the acid and water is going to attack the secondary carb account on. So if you have a car bearcat, All right there and we put a hot sugar here, it will lead to these products. But if we had it on the adjacent carbon, ha Sure. Here, do you get this? So we get to external. So this has to be compound B. Because if we try the same thing with um compound C. So we would get an alcohol here, but we would also get and alcohol right here And for you from right to left, this is 123 Left to right is also 123, which is the same product that has to be compound c. Then compound they will just be a um This all keen because we can't get any sister transformers is building of hydrogen is on the left. This would be compound A. And um I've seen treating all these with hydrogen gas and some metal catalysts would give us the same arcane, but really the difference comes with the acid catalyzed hydration. These would get Either two alcohols or one, depending upon where the key is located. Systems a vaccine or one vaccine and then compounds C. Is going to be three vaccine, but at rest and this is ah to heck see.

The first structure. We're gonna look at his tomb, Ethel. One beauty mean which, as you can see, is illustrated by the structure as there's a method on carbon to and the Alcon starts on carbon one. When this is hell gin ated by age to MPD, the double bond on the AL came disappears and it becomes an out cane which look like this. And that is because ah, hard region is added here and here, which gets rid of that double bond to close a far this al cane and the reactant. We first want to count how many substitue INTs it has, and so an out can have a total of four. And so, as you can see this first, carbon has zero, it says. Both of them are 100. Jin's coming off of it, and then the other all keen has to. So this is a die of instituted and I'm just going to put a little note so we don't forget. And then it's also important that we look at this heat of it, that the molecule will need to be heated up to an order for halogen nation to occur. Some I simmers of we're to metha. One few teen will be this structure of the L cane moving from here to here and then another structure for I summer would be here as since the bunk has moved here. It can then move to here and this was just involved. Hydrogen is being removed in place on other parts of the structure in order to figure out which ones are more stable. We look at how maney substance substitue INTs the Al King has, and the more substitutes it has, the more stable it is. So we've already characterized as our main I simmer being die subsidy substitute. The first time summer that we labeled we see has 123 So it would be a little bit more stable. This might be a little misleading and then we see here at zero on here, but one carbon or alcohol group off the other carbon in the al cane. And so it is a model substituted. Therefore, if we're labeling this in terms of stability, the try so said two did would be the most stable. Then the dye substituted and then lastly, the one that only has one group does no hydrogen and our next example We have three metha, one beauty mean, if this is halogen ated Ah, he of negative 127 co jewels per mole. The heart surgeons will will be added here and here, which causes the Al Cane bon to break and your product will be. And OK, in order to label this one, we see that the first carbon in Al Cain has to hide regions. We should just gonna add another blind. And the second carbon has only one and it has one. I'll kill group, so we know that it is mono substituted. And again, I'm just gonna label it for future reference. If we were going to do I summers of this one, we will notice that the how clean bond can switch over and create the I summer of this one as well as another I summer. If the Al King Bron moves Wimmer, please, it can go either here or here, but whatever, wherever you move the outcome, bond will not change the I summer. And so we now can Christ classify the i Zimmer's in order to figure out stability. So we've already crossed apart our main one for this one. We see that it has three. So it's try substitue int id and this one right here has to therefore as we As I said previously, the more groups that the carbons have that are not hard region will be the most stable. And so this one will be the most stable. So be number one and stability and then it will be you. This one since as to and then this one will be three. Since it only has one our last example, we can go ahead and characterize it. We see that it only has 100 younger, so we know that it is. Try Subsisted, you went in and so again I'm just going to Rabel this and then the reactions air heat up. Two negatives Ah 113 killed Jules promote. It will go through hell origination with age 10 PT pd and the outcome will be removed and it will form and out King. And so the product will be simply this and Hodgins will be added here and here to get rid of the Al came bon. If we're also going to look at, I simmers for this. We see that the AL came bottom can move here to outside or can either move here or here it will be the same and so are I. Summers will be. And then this one and then we've already classified this one and we see that our first I simmer only has one group that is not hard to gin. And then our last Ice Emyr has two groups that are no hydrogen therefore stability this one will be the most stable. Then our second I simmer and then finally this one that only has one Alfio bore group and then overall looking at are three examples of two metha one beauty mean which has a heat of negative 1 19 Killer drills promote three methyl one beauty in that has a negative 127 killed joules per mole and two metal tube you teen which has a he of negative 113 killed joules per mole to perform hell origination. And so generally, when you're looking at the stability of these, the more stable the compound will be being thought. It will take more heat to break the bones for hell origination to break the out king bone so we can look at the heat and we see that our last one, which is two methods to beauty, has the lowest he or has the highest heat. Excuse me for halogen ation, so it will be the most stable. So I'm gonna put a number one, because if you're gonna put this in order for most able to least, this one would be number one and then between our other two, we have a negative 119 in negative 127. Well, im negative. 119. It's harder than 1 27 And so we know this will be the second most stable, and this one will be billy stable. Another way you can check yourself is again looking at these. How many groups that are not hydrogen are on the al cane cause the least amount of groups are hydrogen on. The outcome will mean its most stable. So, as you can see, most stable has three. Our second, the stable has to know

That said this question were given owes analysis products and has to determine what is the likely reactant. So the first thing we have is this guy right here, Um, like that. And we're gonna draw retro synthetic arrows. Kind of the double ended arrow to show that we're working backwards. So obviously we've got to carbon eels. Meaning there was probably to kind of available sites for cleavage. But we know we only have one product, So this probably was some sort of a ring structure. Um, not since the carbon eels air more than likely the site of cleavage. We can say this is 12345 six. Right. So that obviously kind of shows that we have some sort of six member drink like this where we just heard our key right here. There is no carbon one. We have a metals obstetrician. Meaning we probably have a method kind of just off the edge like that. All right, Bees just a little more complicated. Where we've got several products. The first being a 12345 member thing. So we have something that looks like this. Um, no. We also have two other products, the first just being something that looks like this. And the third being something that looks like this. Okay, so we can probably expect that this is going to be, um, a very, very long Harbin chain with multiple double bonds. Eso One way to do this is first just count of all the carbons and label of the chains. Obviously, we've got 12345 I'm gonna call this six and then 78 nine. Okay, so when I draw my retro synthetic arrows, I can draw this a nine member carbon chain. Right, So 23 four, 56 78 nine. Okay, so now the biggest problem is figuring out where to put the substitue INTs. Um, but we can tell based on this middle structure right here, that obviously one of the double bonds and this thing has to be terminal. And the reason for that is we have a single carbon that on Lee has hydrogen attached to it. So weaken weaken Reason that ah, one of our double bonds should be here. Right? Eso we can kind of label this carbon is going to see a little strange, but you can label it a six right now. The only other way that this makes sense is since we have this big first product right here with two cleavages, that this is in the middle. So obviously this would be uncovering 123 four, and five. Um, So with that being said, we know there's another cleavage of carbon five so we can imagine drawing a double another double bond right here. You can tell that that works because then I can also label this as seven, eight and nine. So that's a very weird way to label these carbons. But as you can tell, we can kind of pieces together like a puzzle piece and give us a structure which is going to be, um I'm going to erase these numbers because they're getting a little confusing. But, ah, we're still going to produce this, um, dying as our final product

We were taking a look at some contextual information students, all kinds and all canes. So these are on interesting sort of reactivity and chemical reactions. We're able to form our kids, and our came through the utilization or the extra pill bottles on carbon, aside from the PR battle that is involved in our Sigma interaction. So what we're looking at today is that ordinary Al Keane's are more reactive towards Electra, Filic re agents and all kinds. So are all Keene's, our double bonds, or all kinds. Our triple bonds. However, the Calkins obtained from the addition. Often Electra Filic, re agent to an Al Qaeda, have at least one Electra negative atom attached to a carbon half the double bond. So, for example, we have we generate the following product. Or, for example, we could use X two and then both of those groups that are labeled X and H on the above molecule, both the X. So these Calkins are less reactive than al kind towards electrical like addition, because the electro negative group makes the Double Bond Electron poll, where are double bonds are located here


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