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ConstantsPan AThe radius of the aorta is about 1.4 cm and the blood passing through has speed of bout 45Calculate the average speed of blood flow in the major arter...

Question

ConstantsPan AThe radius of the aorta is about 1.4 cm and the blood passing through has speed of bout 45Calculate the average speed of blood flow in the major arteries of the body; which have total cross-sectional area of about cm? Express your answer to two significant figures and include the appropriate units_HAVartcricValueUnitsSubmitRequest Answer

Constants Pan A The radius of the aorta is about 1.4 cm and the blood passing through has speed of bout 45 Calculate the average speed of blood flow in the major arteries of the body; which have total cross-sectional area of about cm? Express your answer to two significant figures and include the appropriate units_ HA Vartcric Value Units Submit Request Answer



Answers

Blood flows through the aorta at an average speed of $v=18 \mathrm{cm} / \mathrm{s} .$ The aorta is roughly cylindrical with a radius $r=12 \mathrm{mm} .$ The volume rate of blood flow through the aorta is $\pi r^{2} v .$ Calculate the volume rate of blood flow through the aorta in $\mathrm{L} / \mathrm{min}$.

Yeah, this problem governs the concept of the continental equation. From the content in question, we can write the total cost 16 area of capillaries. 8 2 equals a cross sectional area of the aorta into. We want. Upon which let's say this is the question wrong now, uh We can write the number of Kabul R. equals the total cross extend area upon the cross 16 area for uh single capillary. Okay, so from this we can buy it. The number of capillary equals mhm. Even V. Even upon A into b. two. Now replace the area in terms of diameter. So the total number and equals bye. G. Square. We went up on four upon by D squared. Uh we do a 14 or N equals ah dearborn, small G squared. We were born v. two. Now substitute the value. So the number of capillary equals the diameter of order is 0.5 cm R 0.5 into Tenderness minus uh two m square upon the diameter of uh a single capillaries, 10 micrometer or turn into. And this minus six m squared into. We even that is one m 4/2. The speed in the order And the speeding. The coupler is one cm for a second. Are one in two tenders -2 m for a second. So the number of Cavalleri equals 2.5 into Tender. Seven capillaries

I agree. But this is a problem based on equation of continuing according to okay, A question of the product of area into veracity. To be constant a C into the sea is got to a into b the pressure in capillary you will get no substitute the value by our a square. We by r V s r c square or you can also write are a square B A upon our suspect meeting Substitute the value when Giovanni square in 213 a boy, How would you? Oh, yeah. Mhm. Total area number of crops. Sorry. And we have to multiply with the end. And it's to into 10 to the power nine. So he will get four point point seven. Turn to the par minus four m per second. Okay. Her son. Thanks.

Question number 61 from the given condition, the blood flow rate in the iota and the end number off capillaries should be same. So we can write the area off Artur A into velocity. In Alta we A is equal to and times and his number off capillaries required into area off one capillary into. We'll all stay in one capillary. This can also very tennis the A square Where does the diameter in the V A is equal to end times B C squared into the sea. The rate off low must reach them in the end number off capabilities and out. So no substituting the values. Dia is 1.6 in 2 10 to the power minus 2 m. Velocity is 1 m per second, equal to end times D. C is tend to the power minus 6 m is squired in two velocity in one cap. Ilary is then toe the power minus 2 m per second. Here, we should consider the units in meter per second. Solving this, we will get the number of capillaries and equal to 2.56 in 2, 10 to the power Then this is the required number of capillaries

In this exercise, we have information that the blood flows through the aorta at a speed of 0.3 meters per second and that the Orta has a radius of one centimeter. Ah, we also have the information that the body has about two times into the ninth Capital Aires. And each of them has a radius R c. It goes to six equal to six. Um, my perimeters. And we want to find at what Speed? Ah, the blood flows through the capital Aries. So we're gonna have to apply. What we're gonna have to apply here is the relation that the total Votomatic flow read is the same. So v a the the speed of the blood through the aorta times the cross sectional rate. I'm sorry, the car sectional area of the aorta are a equals two total volumetric flow rate of the of the blood through the capillaries. And that's gonna be and times the volumetric flow rate in each Cavalleri. And that's gonna be the speed of the blood in the Cavallari V C times the area of the Cavalleri. No, the area of the order is pie times The radius of the awards is square and the area of the capital is gonna be pi times the radius of the capillaries care square. Now he cancel out the pies and we get the sea equal. Yea, Ari square over in r C squared V 0.3 meters per second are a is one centimeter So are a squared is gonna be 10 to the minus fourth meters square and is too time sent to the nine and R. C is six micrometers So R C squared is gonna be 36 time stands in the minus 12 meters squared so the speed through each capital area is gonna be 4.17 times 10 to the minus four meters per second.


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