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PointsSerPSE1O 32.2.OP.003.My NotesAsk Your TeacheAs shown the circuit dlagram below, AC source delivers an alternating voltage at audlo frequericles to speaker con...

Question

PointsSerPSE1O 32.2.OP.003.My NotesAsk Your TeacheAs shown the circuit dlagram below, AC source delivers an alternating voltage at audlo frequericles to speaker connected to the source through resistor The source voltage has an amplitude of 12.0 V; the resistance 7.70 @, and the speaker equlvalert to resistance of 10.4 Determire lhe time-averaged power (in W) transferred to the speakerSpeaker

points SerPSE1O 32.2.OP.003. My Notes Ask Your Teache As shown the circuit dlagram below, AC source delivers an alternating voltage at audlo frequericles to speaker connected to the source through resistor The source voltage has an amplitude of 12.0 V; the resistance 7.70 @, and the speaker equlvalert to resistance of 10.4 Determire lhe time-averaged power (in W) transferred to the speaker Speaker



Answers

An audio amplifier, represented by the AC source and resistor in Figure P33.7, delivers to the speaker alternating voltage at audio frequencies. If the source voltage has an amplitude of $15.0 \mathrm{V}, R=8.20 \Omega,$ and the speaker is equivalent to a resistance of $10.4 \Omega,$ what is the timeaveraged power transferred to it? (FIGURE CAN'T COPY)

In this question we have this circuit uh there's a a C power supply with the RMS 15 votes. And then there's a speaker of 10.4 homes and a resistor a point. Um We want to find the time average power delivered to the speaker. Okay so to do this question first um we can calculate the rotation uh across the the we are mess across the speaker. Okay. Okay so what to do this? Um So this is like a potential divider. So you have 15 times 10.4 divide by 10.4 plus 8.2. Okay. And then you do this and the answer is yeah mm. You know thank you. 8.39 books. And then the time average power power across uh power delivered to resist them uh to the speaker. Sorry? Okay so this is equal to R. E. Speaker square. The RMS modish square. Uh right by the resistance of the speaker. Okay so just substitute 8.39 square by by 10.4. And then the answer is mhm 6.76. What? Right. So this is the answer for this question, and that's all.

Okay. So the question of figure is given where an audio amplifier is connected in the AC. Source like this. Okay. You can see the figure that is given in the book also. Okay. Like this. So this is this figure. Okay. S and the register has the resistance of 8.20 home. Okay. And the speaker is also equivalent to the resistance of 10.4. Oh okay. And the um source voltages given that is V. Max is given 15 world. Okay. From here we can find out we are M. S. And V. Rms. That is V. Max divided by Ruutel. Okay so it will be B max divided by a road to and it will be 15 divided by total. There it is 10.6 fold. Okay so this will be the V. R. M. S. 10.6 fold in the circuit. Okay and now from the RmS we can find out I. RmS the current. Okay I RmS It will be I will be be by our Okay so it will be V RMS divided by R. And R. Resistance. It will be total total resistance. That is 8.2 plus 10.4. It will be 18.6. Okay so it will be 10.6 divided by 10.6 divided by 18.6. Okay and it will be in NPR understand. And now what we have to find out we have to find out the time. Average power for the speaker. Okay so power of a speaker. It can be it an sp speaker. Their taste I square are okay and here we will find out I RMS. Okay. I square and are. And what is this? Are this is the resistance for speaker only? Okay. Not total here we have taken total resistance to find out. I. RMS. Okay so p speaker it will be I square RMS. I rms from here. 10.6 divided by 10.6 divided by 18.6. That is 0.56569. Okay. NPR so it will be 0.569 Squire multiplied by the resistance in this figure. That is 10.4 home. So it will multiply it by 10.4. And when we solve this will be 3.38. What? Okay. I square multiplied by our That is NPR's Squire. Multiplied by home. And answer will be in what? Okay. So the power In other time average power in this big audio amplifier. It will be 3.3 at what? Thank you.

Down the given deter Talk to we is equal to 15 world and then we have resistance Are distance r equals it going to arms and then the resistance of the speaker, uh, R s. Let's right on artists for resistance of the Speaker, which is 10.4 home, 10.4 home And now, using the relation of B, which is power is equal to root. Mean square, uh, current multiplied by our now by substituting values. Well, we have i r m s right. So they could be written is a cedar point on zero point seven 07 into into, uh, Delta week divided by are less r s Hold square, multiply by. Oh, right. So this is our no, by this is again rs, which is resistance of the speaker. Now, by substituting values, power bi is equal to zero point Zito Boeing 707 into 15 divided by it going to, let's standpoint for standpoint for, um hold square multiply by 10.4 and so power vehicles 3.3. It want

I'm not kidding. We have the gain ratio. It was all over. Swelled off r squared plus x l minus x c square at 200 Hearts weekend, right? Just 1/4. It was arctic was eight, um, divided by a squared off eight square plus x l is to buy F so two f is 400 FYI times l minus one over 405 c sweat What now? We have this falls that X so we will find that X equals negative, right? 13.9 home Just because x l is less than XY for the high frequency have footage point you have 8005 l minus one over 8000 by sea. 1000 bisi It was plus 13.90 solving this you find the capacitance to be 54.6. Microphone it on The induct in is 5 80 Michael


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