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Lerf(x) = 2x2 + 1Estimate thearea under the 'graph off (x)on the interval [0, 3] using 6 rectangles of equal width and left endpoints: your estimate an overest...

Question

Lerf(x) = 2x2 + 1Estimate thearea under the 'graph off (x)on the interval [0, 3] using 6 rectangles of equal width and left endpoints: your estimate an overestimate Or an underestimate? Write an expression in sigma notation for 4n estimate of the area under the graph of f (x) on the interval [0, 3] using rectangles of equal width and left endpoints: Using the summation formulas we derived, write the sum YOu came Up with for part (b) in closed form in terms of n. Take the limit of che close

Lerf(x) = 2x2 + 1 Estimate thearea under the 'graph off (x)on the interval [0, 3] using 6 rectangles of equal width and left endpoints: your estimate an overestimate Or an underestimate? Write an expression in sigma notation for 4n estimate of the area under the graph of f (x) on the interval [0, 3] using rectangles of equal width and left endpoints: Using the summation formulas we derived, write the sum YOu came Up with for part (b) in closed form in terms of n. Take the limit of che closed form sum from part (c) This is the exact areal



Answers

Find a formula for the Riemann sum obtained by dividing the interval $[a, b]$ into $n$ equal subintervals and using the right-hand endpoint for each $c_{2} .$ Then take a limit of these sums as $n \rightarrow \infty$ to calculate the area under the curve over $[a, b]$ $f(x)=3 x+2 x^{2}$ over the interval [0,1]

All right. So this question, we are asked to estimate the area under the curve using the left green and some main point streaming some and and right Riemann, some methods. So let our function year after of X equals X squared, plus two number seven rolls of four. So the first step is gonna be to get the length of each step intervals. That's gonna be our range between zero and two. Divided by the number seven year olds. Full r equals 0.5. So next we have to figure out thank zero. So that's beginning us for seven role. That zero thanks. One is going to be eggs, Eero plus Delta X. So that's 0.5 and so on and so forth to get next to experience for the next step, we're gonna start with the left wing and some and we are going Teoh Um, yeah, I just use the form enough left even some so f of X, not plus fx. One does left next to the next three all that most blind by Delta X so ever. That's not well. That's the value of X squared post to when X equals zero. So That's two radio and X. Um, if x one, these value of X squared plus two one x one equals 0.5. So that's +212 and so on and so forth and multiply by Delta X being 0.5 and we get 5.75 And so this graph right here that's a sketch of the left with them left Freeman Very rough sketch of what the left or even sums look like. So next we're gonna do the midpoint calculation. Eso here, we're gonna have to use different Um, we have to use the midpoint, stow endpoints for X values and celebrate where we doesn't need those with a bar. So expire one is the halfway between zero and X one a k. It's the midpoint of the first interval. So expert one is 0.25 because it's not a zero and one is your wife. So then what we do is we plug those values onto our expression for the immediate point formula. So FX by her one, just like we did before. So that's the value. Its value. That's weird Post, too. When X equals 0125 So expired two is your 175 So f of X Part two is the value of X squared plus two one X equals zero points of five. And so you want to buy the that? Oh, you mad those things up By about zero point fire, you're gonna get 6.625 And this is a little sketch with the right Riemann sums, which are a press. They are an overestimate, as we can see. So I have the midpoint reading some. So that's gonna be our closest estimate. Lastly, you were going to do the right Riemann sons. So now we're using just our exes again on our X bars in the formula for the right Riemann some. So we go back a beer, remember? Experiment 0.5 f of X wanted X squared plus two one X equals your heart. Five. We were golden o and multiply by Point X and we're getting in our answer of 7.75

Okay. Good day. Ladies and gentlemen, Mrs Problem number 49. Section my point to, uh, we're given a function to x cubed interval. I equals 01 and we're expecting and we want to find a formula for the and three months, some over I and then I use this formula s o. I'm just a couple words here before we get started. Um, I did in a number of the previous, um, slides. You can 43 to about 46. I provided a lot more of the details. So if you're, um if you want to go back and see a bit more than detail work about reminds sums of stuff, you can go back there. But at this point, I want to just sort of cut to the bone year and basically summarized the ideas. If if you don't understand anything if you if anything, here, um, I don't You don't understand. Please just go look at either your textbook or some of the previous slides to get more. Are some of the previous problems to get more information. So, uh, I'm I'm gonna try. I'm gonna be a bit quicker. Ah, bit quicker on this rather than go through a lot of the details. Okay, So, um, let's let's just get straight to what we what? We're after here. So, um, we're we're after the Riemann some SN force just for some given and is equal to, um s and is equal to, um it's the Sigma notation, Of course, which is the sum here. Ah, from, uh, k equals to one two and of, um, s off, uh, k over and and then multiplied by one over end. Okay, um, that's what we're looking for. Uh, and of course, um, half of x and year. We know what? Half of exes. So this is just equal to two. This is to, um, a to the third, divided by n to the third. And then I'm just gonna multiply through by the one over, and so instead of into the through, get in to the fourth. OK, so this is the formula for the S end. And now when I have to do is I want to compute a another formula, a second formula. Um, And to do that, I'm gonna factor out the two over end to the fourth. Um, So we'll just, uh Yeah, we'll put the two to the ER. Yeah, we'll move. The two to the end of the fourth are here. So this is to, um, in to the fourth, uh, and we have in here. Then. Is this a cube? Okay. And there's a formula now for this internal some. So this some here there's a formula, and it is in your textbook. So if you feel free to just look it up in your book, uh, it is equal to, um it is equal to, um you see, So it is equal to and squared times and plus one, uh, squared, uh, divided by. Yeah. And then, of course, we're gonna multiply by the two ends of the force here. So we just multiply on the outside here by to over end to the fourth. Um, okay. And at this. Okay, so with this formula now, what I want to do, I want to simplify this down. So I'm just gonna cancel, do a bunch of canceling and use foil on the numerator, And I guess, um, and to the seconds plus to end plus one, um, he invited by now canceling the two. I get her to and B N squares gives me and square. Um, and now this formula, I'm gonna I want to sit. So, um, now I want to simplify again Here. Ah, by, um, how would they do this? So how would I say that? So I'm gonna factor this into, uh, you know, I'm gonna break the fractions up. Ah, and this is Chu and squared, Um, one, too. So I'm just I'm just extending or not. I don't think extending is the right word, but I'm expanding is the right word I want. So I'm just expanding the previous, um, fractions the fraction out into three. And now all I want to do is cancel. So, um, this and squared becomes the end square here, just becomes one. So this is one whips, one over. Um, just canceling, man. Um, next Thea the end cancels with the end of the denominator. And, um, the final one is just that there's nothing to cancel their on. This, of course, is as I say, this is equal to s end. So this is equal to s. And so finally. Now, um, now all we have to do is our final steps. So this is This is the formula we wanted. And now all we have to do is for their for final step is compute the limit. So now we have to compute the limit. So we look at the limit, eyes a CZ and goes to infinity of s end. Of course, of S N. And, um, this is equal to the, um, limit as and two infinity of we just replaced this. So it's 1/2 plus one over end, plus 1/2 and to the second. And of course, you know, when we do these limits, we see this one goes to zero. Um, and this one goes to zero saw we're left with Is this 1/2? And that, actually is our answer. It is equal to, um it is equal to 1/2. And yes, this was definitely much shorter's in some of the previous ones botch in the previous in the previous size, I sort of expanded. The idea is a bit more and was a little little bit more explanatory here. It was a bit shorter with it. So Anyhow, this is this is what this is. The answer is 1/2 and I hope you have a good day. So thank you very much.

They were looking at problem number uh, 46 from section 5.2. And it, um so given a function function three X squared and the interval I equals to 01 We, uh, want to determine a formula for the n three months some and use that lemma that that, uh, um, formula to calculate the respective limit. Um, so first off, I'll give you a brief explanation of what is going on here. So basic idea is that we have you know, we have we have the the, um, autograph of the function here. And, um so in this case, the function, of course, is three x square. So it looks something like this, uh, and we're going from the, uh we're going from, um, zeroes are Interval. I is here. Zero, um, to, uh, up to one. And, um and you break the the interval and your we're looking at breaking the interval into the interval. Ianto and, uh, and segments of equal legs. So, for instance, if n were five, um, we would have segments are segments would look like this. Basically, we have, um, one, um on fest. Um, two fists, two fists. I'm sorry, but maybe this one over a little bit, Um, to FIS. Um, we have way have, uh, three this and, um, forthis. Come on. Okay, we have we have, um, for soups or fists and, um, five this and, uh, is he, uh, the idea is that these we pace it. We we By dividing the interval into the sub blocks here into these sub, I may be making a little more even here. Um, and then each of these, you'll notice that the with for the length of each of these segments are exactly equal. That, um, the, um let me see. Is he, uh, the wiz here? The w, um, is sometimes referred is often referred to as, um the delta, um of X k. So x k being, um Does he just women. So delta of X, k, um, is equal to Well, ex, huh? Were CEO X. Oh, sorry. Um, it is X is equal to, um, ex pay minus x uh, que minus one. Um, so and in this case, it is equal to one over n or in particular in this case, is won over five. So, uh, the at K, Of course, being this being this end point or what we call the right end point, it's the right and point minus toe left endpoint. It's the right end point dynasty and left endpoint, of course, gives you the length of this guy. And then you look and s o er the right end point and we connect. We connected to the curve and draw a little box here like this. And this guy, of course, has the height, which will call H and of course, um h here, Um, maybe I do it over here. Of course, the the H is equal to, uh, half off um X k so in particular than in this case, it is equal to, um f of 3/5 Um, f of 3/5, uh, which is equal to 9/24 hour, uh, 27/25 Three times three squared over five squares, which it's 27/25. So ah, then the the area of this, which of course, is equal to we'll just call this guy. This guy here will be our the will call this guy are here the area of our our area of our very, uh, it is now is equal to Well, it's the Delta. So it's with which is 1/5, um, 1/5. Um, sorry. Won over five, uh, times the twenties, times the height, which in this case, is 27 over 25. This is the area off that guy. Now what I want, what I need to do is instead of and I was working specifically with n equals five here, but five really isn't special in any way. And then I can replace this by end. So now I just change the five, if you will to end. And of course, that would move it closer together. But then what I end up with is, of course, this would be on minus one over end and the end of the the last end point would be an over. And so the final in plate with end over end And then, of course, using the same exact same region. Reasoning as I did hear the with would end up being I'm not 1/5, but one over in. And in this case, um, is the ah, the end of the f of It's not F of K 3/5 Here I was taking again a example. But this is K over n which ends up being, um, three times, uh, k squared, um, k squared and then divided by and square. Okay, so in this case are we're just replacing We're not really doing anything out of the ordinary. I'm just replacing. Ah, the end by, um are justified by n and a za three by K and so my area, in that case doing the exact same thing here, um, again. Then I get 1/5, which is one over end times. Now I get it. This three k squared, um, divided by, Of course, it's n squared. Uh, which, of course, is just gonna be ah gree k squared over and tube when we just get rid of one over. And so the area of our is just that. And of course, if I want if I have, like, say any of these, What I do is I just sum up to get the portal area. So if you look, then if I do it, um so I just draw. Now I connect. Um, just end of these guys, if you can imagine. I just connect any of these guys. Oops, that's not right. Tree that. I do the same thing in each case and to get the total area that's covered by these guys. I just look at the Somme of those guys. So, um, I look at the Somme, and how many are there? Well, of course they're the sum the area covered by those guys. Um, is just the sum, Uh, in this case, it goes from K equals one. Uh K equals one, two, and, uh Come on, turn it. Oh, sorry. K equals one in of the, uh, the the respective areas. Oops. Of the of the ark. A's of the areas, uh, are okay, But of course I know what that is because Ivory calculated it here. Maybe I rewrite this is instead of maybe this is the area of R K. That I don't like to do is replace this in here by this formula here. Cool, Happy. And, uh, that is my This is equal to what we denote as s n here as n an estimate, of course, is as I tried to explain to you, get rid of this. So it's a little clearer here. It's a little confusing right now, but this this is the formula. This right here is what I call our first step. So, uh, this right here is our first step. And, um, to make it a little clear for what we need to do going forward, what I want to do now is just, um I want to, uh, because it's something over K. I can, um, factor. I can I'm gonna take out the, uh let's see. I'm gonna take out the three over, but Okay. So sorry. I'm gonna take out the or, ah, actor out these three over and to the third. And now we see that the sum itself is actually on Lee over is, uh, over k cubed or a K squared here. I'm sorry, is K squared and that is equal to s. And okay, so with this in mind, now, now we proceed to the next step, and what we want to do is to get a formula, or we want to use this guy here. Um, what we have here, we want to use this and turn it into something a little better, if you will. A little more. A little easier. So to that end, um, we use the formula, etc. So we used a formula. Is that, um BC So we used a formula. Is that, um, you see? Have to have to check something here. Which one is this one? Okay, it's K squared. Sorry. I just need to check something. Um, that, uh, see a squared. So from, um, K equals hoops going from K equals one to end and frame. Sometimes a sophistry just doesn't want to behave. Right. Uh, doing area, uh, this formula that going from K equals one to end of k squared is equal to this is equal to it is equal to end times n plus one times to end. Plus one, um, divided by six. And this formula is, of course, given in your textbook. So if we multiply both sides by the the, um, that number, that's three. That three and over three over and Cube. So if we come on Okay. So we multiply by the, um three over and squared in this formula. If we multiply both sides by it, see, be so we multiplied by its three over and cubed multiply both sides by three over and Cube. Um, then and we simplify so in particular than, um, I'm gonna cancel. I'm gonna cancel the end here. I'm gonna make that a to cancel one of the S O. This becomes the denominator becomes and squared, and I didn't get rid of this guy here. Um, then this. Then I've got I've gotten closer to what I want, you know, this is nicer. But of course, I couldn't do a little better than that by, um, expanding the numerator out. I get a two and to the second. Um oh, boy. Sorry. Plus three and plus one. Okay. And now I want to simplify this. And of course, this is then equal to, um this is an equal to one plus, um, three divided by two. And, um, plus one divided by to end to the second. And this is equal to my ass in s. So this is what I get for my sn. And of course, this is really what I wanted. This is the exact formula and actually wanted because the next step is I want to take the limits of the next step. I need to I need to take the limit. Um, I need to use I need to take the limit of both sides here, so yeah, the next step, um, is to, uh, take the limits a cz and goes to infinity, Uh, both sides here, And this is really what I limits a CZ and goes to infinity, both sides. And this is the this Is that what I wanted in the end? And, of course, a Zen goes to infinity. This is going to go to zero, and this is gonna go to zero. So I end up with one, so my answer ends up being, um, one, and that is my answer. Um, so, uh, yeah. So? So the answer ends up being one in the so, and that's ah, that's all there is to it. Even though when I say that it sounds, there's actually quite a bit of work involved. So, um, Okay, uh, thank you very much. And, uh, have a nice day

It's a woman. This is problem number 45 from section 5.2. And essentially, the idea is that we're given, Ah, certain function. In this case, it's X squared with one and an interval. I, um, equals 03 in this case and were we want to find Thea. Uh, we first want to find a formula for the n three months some and then use that formula to get the the limit or to calculate the limit. Okay, so, um, no. The basic idea of what we're supposed to do is best described by the diagram by a diagram of eso. Um, and I'm gonna I'm gonna draw the diagram here, and it's in the textbook, and you can look at it there if you wish. But I'll still draw because it helps. Makes the explanation a little easier to have a drink. Diagram, toe, Look at. So, um Okay, so we're given a certain interval here in this case are Interval. I, um, down here, Um, and is the, um our function? Of course. Um, oops. Uh, way. Okay, so our function here is X squared, plus one. So if we draw, uh, draw a graph the, uh, the graph of it like this, Um, you know, like that. Okay. And, um, then we go from we're going from, of course, um, zero here, all the way out to and this is three. And for convenience sake, I'm just gonna write this as three, which is equal to three end over and just for ah, for I already say, And then if you, uh, if you look at, um So if you take a k value between well, we want to break. Um, this, uh, we want to break this into distinct of, um into segments off the same with here. So in particular than we're breaking this into and little ah, intervals here, Um, all of the same with And, um so in particular than this guy here, If we're looking at, um, some arbitrary And here, like this interval, uh, one of these guys would go from, for instance, it would go from three times K minus one to over and, um uh, Okay, that that's what Good? No, Uh, three K minus one. Um, over and two, um, 23 k here. Over. Oh, um, to, uh, three K over. And so you see that the west of this interval is going to be three over end. Um, And then if we take the this end, what we call the right and point here, then, um, the point on the curve, of course. Or is the point here? Um, is three OK, over in, Uh, oops. Sorry. Maybe I do it this way. Three k over n comma. Um, uh, half off, three k over in. Okay, just delete it. Okay, Um, and this point on the curve, um, it forms a We get a rectangle here, Uh, we get a rectangle, so you draw you get this little vikan draw properly, which is not easy to do. You get a rectangle here, and this'll ce rectangle was, um, the west of this rectangle the d wis of this rectangle here. So the if I draw that the West, um, is, um is three over end, So the width of it is three over. And while the height, the height of the sky from the top to the bottom, of course, is, um is equal to f of three K over it is f of three K over and, um, which in this case, of course, is equal to, uh, three. Or maybe I do it. Let's say nine K squared over and squared, um, plus one. So just taking effort. So So this gives us our height. This is our height, and the three over end is our with so in particular than if this if we call this rectangle here. Ah, call this rectangle are, um So this is so if this is my rectangle are this is my rectangle are. Then I get that the area of our So the area is l, which is equal to the, uh, West Times the height, um is then, uh, equals two. Um, free over end three over end Himes, nine k times nine k squared over end squared. Um, plus one s o if we if we simplify. So if we rewrite this, we get that this area is equal to, um was 27 k squared, uh, 27 k squared, divided by, of course, the end to the third, um, now, plus three over end. It turns out, of course, that this formula is important. Okay, so this is the This is the area for each of the given rectangles. Okay. Um so happy. Oh, for the next step. Um, what we want to do now is we want to take the sum. We want to take the sum over. All end of those rectangles, so in particular than we're taking the sum from, um of K uh, que Goes from k equals one to n of the area of those rectangles, Um, and of the, uh, area of the ours. So maybe l said the area off the r, we'll just call him our case for each of the different rectangles. Okay. And now we know, um, that this so we know. So, uh, this is equal to then I'm just going to replace I'm going to rewrite it. Um, I'm gonna rewrite it, using that formula that we got from the previous slide. Um, as be going, too. Course this goes from again. It goes from a equals one, uh, two in here. Whoops. Huh? Um uh que goes from one to, uh, end of, um, again. I want to just copy this copy in my little area formula out here, um, 27 uh, b and, um you see, and just plug it in here. So this is equal to Okay. Come on. There we go. Um, be. And of course. Ah. Since we have an off these, I'm gonna simplify the 2nd 1 In other words, I'm gonna just I'm gonna take uh okay, I'm going to separate this into this sum. Um, plus Okay, we have n of them, so three times, and this becomes three. Ah, three. Uh, this is three. And over. And so, in other words, you just get free here, okay? And again, I want to, um, on this 1st 1 I'm gonna fat this, uh, I'm going to use the formula. Um, this is a pretty important formula. Uh, and it's actually in your textbook, and it's what it says is that, um, z uh oops. That the sum here, uh, this is from K equals one thio end school to to end of, um, Now, this is K squared. Well, here, a squared is equal to, um it is equal to, uh, and and plus one, um, times two and plus one, um, all divided by, uh, six. And so you'll notice that, um, this K squared Aiken factor out the of 27 and cubed, and, uh, I can multiply this guy here by 27. Over and cubed. Um, so 27 um, over and shoot and multiplying both sides. Oops. Multiplying both sides by 27 over and cubed. Um, I get, um You see? Uh, okay. Not sure this is gonna know Twitter over here s I multiply both sides here by 27 um, over in to the third s o. Then once I do that, I can simplify here, I'm going to cancel the end, and this becomes and squared. Um, and then, uh, this guy becomes, uh, taking out the threes. Then I get a to here, and I get a three here, get a three there, and I want to use the foil here. I'm just gonna foil this out to make this, um, this becomes too and squared. Plus three and plus one. Um, and then, uh, times divided by two times three over and squared. And then it what, then what I want to do is I take this and simplify it down, and I end up west. Um, uh, just by simplifying it, I'm going to get, uh, three plus, um, nine and nine. Um, divided by two two and, um, plus three three divided by two. And the second for equal to equal to this. Um, which means, if so, this means then, um that Ah, If I moved to the next slide here, um, that my s and my sn, which, of course, is equal to the sum of the areas off the rectangles. Um, some of the area, the rectangles here, eyes equal to this sum here. This sum, which I found is right here, um is equal to obsess, Ari. Okay. Ah, went so I found my, um, found, uh, s and is equal to three. Plus, what was the other? Where's the other guys? Here it was three plus nine over to in. Oops. Okay. It was equal to three plus 9/2. And oops. Hurry. Ah, 9/2. And, um, plus was, uh, uh, three over to end squared plus three over too. And squared. Um, and then plus the three from the the three over here, So Ah, and then I can rewrite. This, of course, is just equaling two. Um, this it because this is just six, um, plus nine over to end plus three. Ah. Divided by two n toothy second. Okay, so now with this in mind now, finally, this is the formula I wanted. And now I want to take the limit as angles to infinity. So now I just look at the limit of this s ends. So now I look at the limits, um, as and goes to infinity of my s ends. Um, and, uh, this is equal to the limits, as in two infinity of that guy and pretty clearly now, as and goes to infinity. What's gonna happen? This guy is gonna go to zero, and that guy is gonna go to zero. So I end up with just six from, And that is, in fact, my answer it is equal to I just said so. Uh, yeah, so that's a bit of a long, long explanation, but our answer actually is So, um, uh, yeah, thank you very much. And have a nice day


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6 [ 1 3 1 3 iiiiiii 1 3 3 3 1 { 1 H 1 1 071 1 0 3 8 3 ! 1 I V J 1 I M U 1 1 | 1 1 V 1 1 J 1 | 1 1 U L 8 U 3 1 1 1 L [...
1 answers
The Laplace transform of the initial-value problem is \[s^{2} \mathscr{L}\{y\}-s y(0)-y^{\prime}(0)+5[s \mathscr{L}\{y\}-y(0)]+4 \mathscr{L}\{y\}=0\]. Solving for $\mathscr{L}\{y\}$ we obtain \[ \mathscr{L}\{y\}=\frac{s+5}{s^{2}+5 s+4}=\frac{4}{3} \frac{1}{s+1}-\frac{1}{3} \frac{1}{s+4} \]. Thus \[y=\frac{4}{3} e^{-t}-\frac{1}{3} e^{-4 t}\].
The Laplace transform of the initial-value problem is \[s^{2} \mathscr{L}\{y\}-s y(0)-y^{\prime}(0)+5[s \mathscr{L}\{y\}-y(0)]+4 \mathscr{L}\{y\}=0\]. Solving for $\mathscr{L}\{y\}$ we obtain \[ \mathscr{L}\{y\}=\frac{s+5}{s^{2}+5 s+4}=\frac{4}{3} \frac{1}{s+1}-\frac{1}{3} \frac{1}{s+4} \]. Thus \[...
1 answers
Changing bases Convert the following expressions to the indicated base $3^{\sin x}$ using base $e$
Changing bases Convert the following expressions to the indicated base $3^{\sin x}$ using base $e$...
1 answers
Use the laws of exponents to simplify. Do not use negative exponents in any answers. $$ \left(x^{-1 / 3} y^{2 / 5}\right)^{1 / 4} $$
Use the laws of exponents to simplify. Do not use negative exponents in any answers. $$ \left(x^{-1 / 3} y^{2 / 5}\right)^{1 / 4} $$...
5 answers
The rate constant for this zero‑order reaction is 0.0250 M·s−1at 300 ∘C. A⟶productsHow long (in seconds) would it take for the concentration of Ato decrease from 0.810 M to 0.260 M?
The rate constant for this zero‑order reaction is 0.0250 M·s−1 at 300 ∘C. A⟶products How long (in seconds) would it take for the concentration of A to decrease from 0.810 M to 0.260 M?...
5 answers
An object thrown upward near the surface of the Earth has heighth(t) = 128 + 16t – 16t2 , where height is measured in feet and time, t, is measured in seconds. Find the (absolute)maximum height the object reaches using derivatives
An object thrown upward near the surface of the Earth has height h(t) = 128 + 16t – 16t2 , where height is measured in feet and time, t, is measured in seconds. Find the (absolute) maximum height the object reaches using derivatives...
5 answers
Calculations on the graph attached), bisk or neutral? (1 pt ) Juppon voutantwicr reaction t occutring? 1 1 1 1 DJHZ attached 1 1 udejd 1 Thudrolysis on the 1 1 W euddance 'OJ'EN I0 uOlInjos snoanbe ue Japisuoj 8fphe} 1 1 1 1 adois 841 (Mate Write 1 report the answer: Slope
calculations on the graph attached), bisk or neutral? (1 pt ) Juppon voutantwicr reaction t occutring? 1 1 1 1 DJHZ attached 1 1 udejd 1 Thudrolysis on the 1 1 W euddance 'OJ'EN I0 uOlInjos snoanbe ue Japisuoj 8fphe} 1 1 1 1 adois 841 (Mate Write 1 report the answer: Slope...
5 answers
6. Let E be the solid bounded by the *z-plane; the yz-plane and the surfaces 2 = 3 _ 2y, 2 = 2c2 + 1 (see the picture below)Set; Up) tlc triple integral f(.y,:) &V lie order of vour clioice: Draw picture of tlre appropriate projection of E to rcceive full credit.
6. Let E be the solid bounded by the *z-plane; the yz-plane and the surfaces 2 = 3 _ 2y, 2 = 2c2 + 1 (see the picture below) Set; Up) tlc triple integral f(.y,:) &V lie order of vour clioice: Draw picture of tlre appropriate projection of E to rcceive full credit....
5 answers
16. [6 pts] Solve the trigonometric equation in the interval [0,2t). 2cos2x + 5cosx + 2 = 0
16. [6 pts] Solve the trigonometric equation in the interval [0,2t). 2cos2x + 5cosx + 2 = 0...
5 answers
MangiogdimenesOtm~Oce Gcnn7ten thut`| uMr IM E (eh (rrato ta #hranrh Tlednd RCATA #uton UitFudeneneymtnLSo
mangiog dimenes Otm ~Oce Gcnn7 ten thut`| uMr IM E (eh (rrato ta #hranrh Tlednd RCATA #uton Uit Fudeneneymt nLSo...
5 answers
Consider the double integral J1dy dx 1. Draw axes then sketch the region of integration2. Write the Integral with the order of integration reversed,
Consider the double integral J1dy dx 1. Draw axes then sketch the region of integration 2. Write the Integral with the order of integration reversed,...

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