4

RATE LAW DETERMINATION IODINATION OF ACETONE Homework SheETTableclap cdnmc completionreactonlacelone][HCI aheaedbe 40 AALL Atlme 5LAecA t0.O @Ezpl Expt 2 Z.0'4...

Question

RATE LAW DETERMINATION IODINATION OF ACETONE Homework SheETTableclap cdnmc completionreactonlacelone][HCI aheaedbe 40 AALL Atlme 5LAecA t0.O @Ezpl Expt 2 Z.0'40 Expt Ak Expt 3_ROn Expt = 3557 Expt Expt ? 239Table _calculatetha ordercalculate the order hydrochloric acid (vl comparc experimcnis Four Weaherecakculate the order icdlne (zk, compare experiments 7o76czaucelone (*, comparc exoenimentsvalue OtXTablerate[acetone]" [Hci]Y [iodine]" from rate lavExpt 1Expt 2ExptExpt -Expt 5Ex

RATE LAW DETERMINATION IODINATION OF ACETONE Homework SheET Table clap cdnmc completion reacton lacelone] [HCI aheaedbe 40 A ALL Atlme 5 LAecA t 0.O @ Ezpl Expt 2 Z.0'40 Expt Ak Expt 3_ROn Expt = 3557 Expt Expt ? 239 Table _ calculatetha order calculate the order hydrochloric acid (vl comparc experimcnis Four Weahere cakculate the order icdlne (zk, compare experiments 7o76cza ucelone (*, comparc exoeniments value OtX Table rate [acetone]" [Hci]Y [iodine]" from rate lav Expt 1 Expt 2 Expt Expt - Expt 5 Expt 6 Expt ` average



Answers

Acetone reacts with iodine in acidic aqueous solution to give monoiodoacetone. Write the rate law that you derive from this mechanism.

This question is a method of initial rates. Question where to determine the order of the reaction with respect to each particular reactant. We need to see how the rate changes when we change the concentration of that particular reactant. Then, from the order of the reaction with respect to each reactant, we can write the rate law, which is what is requested in this problem. The rate law will be equal to rate multiplied by the rate constant multiplied by rate will equal the rate constant multiplied by the concentration of one reactant n no raised to an appropriate order which we will determine, so we'll call it X, multiplied by the concentration of CL raised its order. So we need to determine what these orders are. Put some numbers in here and this will be the rate law to figure out what these exponents are. We simply look at the data that is provided and see what happens to the rate when we change the concentration. When we only double the concentration of cl two, keeping the no concentration constant. We see that the rate doubles because the rate doubled, then why is going to be equal to one when we only double the concentration of N O. Looking at experiments one and three, we see that the rate goes from 2.27 times 10 the negative 5 to 9 point oh, eight times 10 the negative five where the rate is quadrupled. If we double the concentration and the rate is quadrupled, then this is second order rather than first Order and X in this case would be to So the rate law is simply going to be equal to rate is equal to the concentration of n O raised to its order which will be too multiplied by the concentration of CL two raised to its order, which is one

All right, So in this question, were given the reaction between nitrogen monoxide and molecular chlorine forming this product and were asked if eyeing the rate law for this equation. So we're given some initial data with their initial rates for the concentrations of each of the reactant. So the first thing that I'm going to do is use experiments one and three to find the the order with respect to nitrogen monoxide. Since the ah concentration of chlorine is constant during experiments one and three. So writing all of that out, I'm going to put Experiment Three over Experiment One, since the values of Experiment three are larger and I wont have to worry about units or fractions when I divide both of these things out. So the first thing I'm going to do is write my rates for both of these equations. So here's the rates, according to the data that was given to us and this is going to be equal to K times the rate of nitrogen monoxide which is 0.250 to the end power and this is multiplied by 0.255 Moller to the end power it's gonna be oh, divided by the same thing. Our rate constant multiplied by our first concentration of our first reactant to the empower multiplied by the same concentration as the expression above. When I simplify this, I find that my case cancel out and the concentration for chlorine cancels out as well. This left side of the equation simplifies to four, and this right side simplifies to to em solving for am I find that em is equal to two by the rules of exponents. So this is my order with respect to nitrogen monoxide. Now that I have this, I can go ahead and find the order for chlorine. And this time I'm going to be using experiments one and two for the same reasons as the previous problem. So I'm gonna put experiment to over Experiment one, and I'm going to write my rates for each of them for Experiment two, that is 4.55 times 10 to the negative five moller per second. And for experiment one that's 2.27 to that unit. That's going to be equal to K times or concentration of nitrogen monoxide, which is 0.125 to the M, and this is going to be multiplied by 0.510 to the end. Dividing this out by are data for experiment once that's K time 0.125 to the Emma multiplied by 0.255 to the end for chlorine. When I simplify this case, cancel out my concentrations for nitrogen monoxide. Cancel out and I am left with just some basic simplification. So I have to on my left side and two to the end on my right solving for N I have n is equal to one. And that is my order with respect to chlorine. Now that I have both these values, I can go ahead and solve for my cake Constant. So I'm gonna go ahead and write out my general rate law equation. So my rate is equal to K times concentration of nitrogen monoxide and this is squared since this is what we found earlier and C 02 to the one power to solve. Okay, I'm going to use Experiment one to plug in some data. You can use any of the data from the table. That's given to us, but I just use Experiment One, since that was ARB arbitrary choice. So I have my concentration for nitrogen monoxide as well as my concentration for chlorine and with some basic algebra. I console for K and K is equal to 5.7 with the units of em to the negative too. And in verse seconds. Now that I have all of these, I can go ahead and just write my general Ray claw for this problem. So my rate is equal to 5.7 with the unison I found earlier times a concentration of nitrogen monoxide squared times my concentration of chlorine to the one power. And this is my general rate law for this reaction.

First time writing the equation which is given in the problem A. Plus to be gift C. Plus to the. Now the rate law is given by rate is equal to k. Multiplication A. To the power X. Multiplication B to the power Y. Now going forward here I can write the expression has nine multiplication 10 to the power minus port is equal to K. Multiplication 100.32. The power X multiplication 0.32. The power Why? Similarly I can write three multiplication 10 to the power minus four is equal to K. Multiplication 0.10 to the power X multiplication pointed you to the power Why now going forward and dividing both the expression. So I can write nine multiplication 10 to the power minus four by three. Multiplication 10 to the power minus four is equal to K. Multiplication 40.30 to the power X. Multiplication 0.32 to 0 to the power Why? By game multiplication 0.10 to the power X. Multiplication 0.30 to the power. Why? On simplification I get three is equal to three to the product. So acts is equal to one. The order of the reaction with respect to they attend one each order one. Now I am going forward and simplifying it for part B. So here I can write the express an edge. Just look at it carefully. Three multiplication tend to depart minus four is equal to a multiplication 0.10 to the power X. Multiplication 0.10 to the power Why? Also I can write three multiplication 10 to the power minus four is equal to K. Multiplication 0.10 to the products multiplication 0.30 to the power. Why dividing both? I can write three multiplication 10 to the power minus. Put by three multiplication, 10 to the par minus police equal to K. Multiplication 100.10 to the politics point. When you go to the party, why by K multiplication point went to €1 to the barracks 0.3 year to the Power white Un simplification. I get the value of one is equal to one by three to the power wine. So why is equal to zero? So the order of the reaction with respect to be each 00 That means the reaction is independent of B. Now going to calculate the date. So here there it is equal to K. Multiplication. A. So having it further. I can write the express an edge. Just look at it carefully. Three multiplication 10 to the power minus four. Am. For a minute is equal to K. Multiplication 0.10 M. On simplification. I get the value of kids three multiplication 10 to the Power Ministry one minute. As the rate law expression. So the rate law expression can be written Edge R is equal to three, multiplication 10 to the power minus three. For me not multiplication A, but this is our end.


Similar Solved Questions

5 answers
Problem 2 Nonparametric Statistics. An economist asked to 500 business executives do you believe the rate of inflation will be higher during the coming year than last year?' Table 2 summarizes the result Can the economist conclude that the expectations are homogenous across the industries?Table 2: Inflation expectation Industry A B C D E Response 25 75 50 45 65 Yes 75 25 50 55 35 No
Problem 2 Nonparametric Statistics. An economist asked to 500 business executives do you believe the rate of inflation will be higher during the coming year than last year?' Table 2 summarizes the result Can the economist conclude that the expectations are homogenous across the industries? Ta...
5 answers
Find parametric equations for the line. (Use the parameter t.) The line through the points 2,1) an (5, 1,-8)(x(t), y(t), z(t))Find the symmetric equationsX - 5 = 2y - 2 = 2 + 5 + Sx = 1 + 2 =-8 _ 2x - 2 = Y_5=2+8X55 = 2y - 2 = 2+8 X+8 2y - 2 = 235Need Help?Read It_Watch ItTalk to Tutor
Find parametric equations for the line. (Use the parameter t.) The line through the points 2,1) an (5, 1,-8) (x(t), y(t), z(t)) Find the symmetric equations X - 5 = 2y - 2 = 2 + 5 + Sx = 1 + 2 =-8 _ 2x - 2 = Y_5=2+8 X55 = 2y - 2 = 2+8 X+8 2y - 2 = 235 Need Help? Read It_ Watch It Talk to Tutor...
5 answers
I1-D. Consider the titration of 50.0 mL of 0.050 0 M malonic acid with 0.100 M NaOH_ Calculate the pH at each point listed and sketch the titration curve: Vb = 0.0,8.0, 12.5,19.3,25.0, 37.5,50.0, and 56.3 mL_
I1-D. Consider the titration of 50.0 mL of 0.050 0 M malonic acid with 0.100 M NaOH_ Calculate the pH at each point listed and sketch the titration curve: Vb = 0.0,8.0, 12.5,19.3,25.0, 37.5,50.0, and 56.3 mL_...
5 answers
Question 510 ptsUpload your answer to this question Make sure the parts are well-labeled. a) Set up the integral for finding s(t), the arc length parameter: 2t2 + 1,6t,t3 2) b) Find the length of the curve on the interval t € [1,3],round to the nearest0.01.Upload Choose a FileQuestion 65 pts
Question 5 10 pts Upload your answer to this question Make sure the parts are well-labeled. a) Set up the integral for finding s(t), the arc length parameter: 2t2 + 1,6t,t3 2) b) Find the length of the curve on the interval t € [1,3],round to the nearest0.01. Upload Choose a File Question 6 5 ...
5 answers
Speculate, giving reasons, on how the absence of a gene product could regulate a specific cell division: Work through this question by concluding whether the blockage of cell division is specific (division plane; cell lineage) or general to all division planes and all cell lineages_
Speculate, giving reasons, on how the absence of a gene product could regulate a specific cell division: Work through this question by concluding whether the blockage of cell division is specific (division plane; cell lineage) or general to all division planes and all cell lineages_...
5 answers
Qucstoam $ ( 17 marks)Solve the following initial boundary value problem8u 1du a' B &0<<4">0,3(0.)= 24(1,)=0 1>00 <8<1/2 /2s*S1."(xO) = Jo
Qucstoam $ ( 17 marks) Solve the following initial boundary value problem 8u 1du a' B & 0<<4">0, 3(0.)= 24(1,)=0 1>0 0 <8<1/2 /2s*S1. "(xO) = Jo...
5 answers
JnsycincorrectuquinBccause not Ji Jining passenders Sho; Up oncir rescivcd scjt airline sells 125 tickets Independenciy Rcuno answen tour decimal places 98.76541.flight that holds only 115 passengersDrobubility thatPusscnacinot shor Up 0,05Dussendels penavc(a) What (ne Diodadilicy hal Evci passe noer Mno <nowscan [akcflignt?0.8426(b) What the probability that tne ilight depatts with at least one empty seat?0.7456
Jnsyc incorrect uquin Bccause not Ji Jining passenders Sho; Up oncir rescivcd scjt airline sells 125 tickets Independenciy Rcuno answen tour decimal places 98.76541. flight that holds only 115 passengers Drobubility that Pusscnaci not shor Up 0,05 Dussendels penavc (a) What (ne Diodadilicy hal Evci ...
5 answers
Acyclic stereochemistry & chirality Maximum allowed tries per question: Unlimited(33) Draw all stereoisomers of 2,3,4-trihydroxybutanal.
Acyclic stereochemistry & chirality Maximum allowed tries per question: Unlimited (33) Draw all stereoisomers of 2,3,4-trihydroxybutanal....
5 answers
Iction to Probability |i fall2oSuppose you are taking multiple-choice test with choices - each question: ansienno question on this test, the probability that you know thc answer 0.5. If you don't know thc answer; you choose onc randam What is the probability that you knew the answer question given that you answrcred correctly?Select one 0.78260.300.92310.80Finish attemption
Iction to Probability |i fall2o Suppose you are taking multiple-choice test with choices - each question: ansienno question on this test, the probability that you know thc answer 0.5. If you don't know thc answer; you choose onc randam What is the probability that you knew the answer question ...
5 answers
One end of a spa is a vertical rectangular wall 5.00 m wide. What is the force exerted on this wall by the water if it is 0.54 m deep?The force exerted on the wall by the water is (Round to two decimal places as needed )kNkN:kJ.
One end of a spa is a vertical rectangular wall 5.00 m wide. What is the force exerted on this wall by the water if it is 0.54 m deep? The force exerted on the wall by the water is (Round to two decimal places as needed ) kN kN: kJ....
5 answers
AuGren (wuo aurves by parametric equations; thcy have the intersection at some poing P Fugelfeos ais the acute angle between the tangent lines t0 these curves at P: (20 Points) Ia6=2. 31 _ 52 0 G:2,k.+' 42 0nong althe olhers
AuGren (wuo aurves by parametric equations; thcy have the intersection at some poing P Fugelfeos ais the acute angle between the tangent lines t0 these curves at P: (20 Points) Ia6=2. 31 _ 52 0 G:2,k.+' 42 0 nong althe olhers...
5 answers
Find the domain of each function: (3pts)X3. f(x)=r+2xb. g(x) = 1 _Sr+4C. h(x) = Vx" -25
Find the domain of each function: (3pts) X 3. f(x)=r+2x b. g(x) = 1 _Sr+4 C. h(x) = Vx" -25...
4 answers
Orct following molecules bitscd stabilityLJAastable;5 Iezst slable}
Orct following molecules bitscd stability LJAa stable;5 Iezst slable}...
5 answers
Find the Pad´e approximation R3,3 for f(x) = e x , starting withits MacLaurin expansion.
Find the Pad´e approximation R3,3 for f(x) = e x , starting with its MacLaurin expansion....
5 answers
12 of20 (1 complete)Fnd te slope and vertical-axis intercept of the Enear function; and sketch the graph: Pq) 4aTne slope of the funcbon is (Type a integer or fraction The vertcal-axis intercept is (Type a integer &r fraction ) Use me graphingtool to graph te InaClckto ename grapn
12 of20 (1 complete) Fnd te slope and vertical-axis intercept of the Enear function; and sketch the graph: Pq) 4a Tne slope of the funcbon is (Type a integer or fraction The vertcal-axis intercept is (Type a integer &r fraction ) Use me graphingtool to graph te Ina Clckto ename grapn...
5 answers
Qnestion DLamg = 8' . Find the measure of 25 which is formed by the bisectors of ZI and 2.0)6 160D} @ 80'0841130djo90"ej @ 120Nonea cftha above
Qnestion D Lamg = 8' . Find the measure of 25 which is formed by the bisectors of ZI and 2. 0)6 160 D} @ 80' 0841130 djo90" ej @ 120 Nonea cftha above...

-- 0.020274--