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Unethyl-2-butene B) trans-2-pentene C) cis-2-pentene 0) 2-methyl: ~butene 39 Which of the circled hydrogen atoms E the MOST acidic? Which of the circled hydrogen Al...

Question

Unethyl-2-butene B) trans-2-pentene C) cis-2-pentene 0) 2-methyl: ~butene 39 Which of the circled hydrogen atoms E the MOST acidic? Which of the circled hydrogen Aloms the LEAST acldlc? CH HaC HzC-C HGc Hc CHaMOST reactive in an Sk? reaction? LEAST reactive in an Sw? reaction? 43. MOST reactive an E2 reaction? LEAST reactive an E2 reaction?45. MOST reactive in an E1 reaction? 46. LEAST reactive In an E1 reaction?Determine Ihe C-H bond wilh (he GREATEST bond dissociation energy: 48. Determine the

unethyl-2-butene B) trans-2-pentene C) cis-2-pentene 0) 2-methyl: ~butene 39 Which of the circled hydrogen atoms E the MOST acidic? Which of the circled hydrogen Aloms the LEAST acldlc? CH HaC HzC-C HGc Hc CHa MOST reactive in an Sk? reaction? LEAST reactive in an Sw? reaction? 43. MOST reactive an E2 reaction? LEAST reactive an E2 reaction? 45. MOST reactive in an E1 reaction? 46. LEAST reactive In an E1 reaction? Determine Ihe C-H bond wilh (he GREATEST bond dissociation energy: 48. Determine the C-H bond with the LOWEST bond dissociation energy: Hc_ Hd He TURN OVER YOUR SCANTRON and START at #51 (15 questions,2 pts each = 30 pts)



Answers

Rank the following dienes from most reactive to least reactive in a Diels-Alder reaction: The most reactive diene has its double bonds locked in an $s$ -cis conformation, whereas the least reactive diene has its double bonds locked in an $s$ -trans conformation. The other two compounds are of intermediate reactivity because they can exist in both $s$ -cis and $s$ -trans conformations. 1,3-Pentadiene is less apt to be in the required $s$ -cis conformation because of steric interference between the hydrogen and the methyl group, so it is less reactive than 2 -methyl- 1,3 -butadiene.

The question is classified are following as a strong acid or weak acid on the basis of percentage of organization. So we are going to discuss how can we differentiate all the given options? On the basis of percent organization? As we know that as the percentage organization increase or up 200%, then it will be the strongest id if percentage of ionization is very very less than it will be we casted. So in the first option we have percentage organization is 1%. So it will be weak acid. Acetic acid is a weak acid. In B option we have H two C 03 and it is ionized Approx 1%. So it will also a weak acid N. C. Option we have at C. A load to It is also ionized up to 1%. So it will also a weak acid. But in the option we have at CL. and it ionized up 200%. So it will be as strong as Cedar. Okay.

So here we're just looking at some different properties off different structures. So firstly, we've got diamond salty thought followed by Try me, Sell a mean Next we have to try me, Sal Boron. And finally we have carbon dioxide. So as you can see here, I've drawn up my confirmation off the first example We have a central oxygen to me thought groups who are on meth eyeless ch three. We have bonding angles of about 104.5 degrees There on we have SP three hybridization and that's because we only have single bonds present. So now I'm gonna look at my c 02 example So that is in fact, a linear structure. We have sp two hybridization about that central carbon because we have double bonds, we have bonding angles of about 180 degrees, as you can see from not linear confirmation and when looking at the die poll, we have die polls in the direction of our more election negative atoms which are oxygen's. However, due to the symmetry, we have equally and opposing die polls on these, therefore, cancel one another out. So it carbon dioxide is not polar when compared to our dime is a lethal which is ever so slightly polar. However, it is used as a non polar solvent due to the symmetry and how small the Dye Poll is. So not just using that rational, you can complete the next few examples that I've missed out. I've done a slightly polar on a non polar example up on the screen now to aid our learning.

Identify the most acidic I'd regions in each of the fallen molecules and first of hard regions in the off position to the Carbonnel group are most acidic because the country did base would be devised back in education with a minor name. First Cardiges in the opposition to the companion group would be most acidic for the same reason. See this the most acidic hydrogen because it's a taste ravine. Starbucks. The group there country good base will be Gillick allies by conjugation with other religions did bins on my most acidic conditions. They are harder Jin's that teach toe natural gin because the country good base would be jellicle ized by conjugation with bunions. E m. How religions Next with the Metrorail across the big crunch you get best will be jellicle ized and stabilized by conjugation with no trial if that in mind, those Cartagines next to the companion group with the most acidic, because the conjugate base would be stabilized by conjugation with the carbon who

I didn't define the most acidic conditions in the foreign compounds. This hydrogen. Next, prove it. Combining a little purple off religions. Those two hard vigils them three high additions there. Here is the most acidic. Hydrogen is actually, uh, the car box of hydrogen here. Hostages, additional nitrogen. That's too hard. Regions next to the Santa Group and three Cartagines next to the curb on your group.


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