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Circular coil of 9 tums and diameter of 30.0 cm oriented in vertical Plane with its axis perpendicular the horizontal component of the coil is made deflect 45.02 fr...

Question

Circular coil of 9 tums and diameter of 30.0 cm oriented in vertical Plane with its axis perpendicular the horizontal component of the coil is made deflect 45.02 from magnetic north bv curent of 0.630 in the coil: What is the horizontal component of the Earth'$ magnetic field? the Earth'$ magnetic field. horizontal compass placed at the center (b) The current E the coil svitched off, dip needle magnetic compass mounted the vertical. What is the total magritude of the Earth'$ magne

circular coil of 9 tums and diameter of 30.0 cm oriented in vertical Plane with its axis perpendicular the horizontal component of the coil is made deflect 45.02 from magnetic north bv curent of 0.630 in the coil: What is the horizontal component of the Earth'$ magnetic field? the Earth'$ magnetic field. horizontal compass placed at the center (b) The current E the coil svitched off, dip needle magnetic compass mounted the vertical. What is the total magritude of the Earth'$ magnetic field at this location? that can rotate vertical nonth- south Plane. At this location_ dip needle makes an angle of 23.02 from



Answers

A circular coil of five turns and a diameter of 30.0 $\mathrm{cm}$ is oriented in a vertical plane with its axis perpendicular to the horizontal component of the Earth's magnetic field. A horizontal compass placed at the coil's center is made to deflect $45.0^{\circ}$ from magnetic north by a current of 0.600 $\mathrm{A}$ in the coil. (a) What is the horizontal component of the Earth's magnetic field? (b) The current in the coil is switched off. A "dip needle" is a magnetic compass mounted so that it can rotate in a vertical north-south plane. At this location, a dip needle makes an angle of $13.0^{\circ}$ from the vertical. What is the total magnitude of the Earth's magnetic field at this location?


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