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A student prepares a solution by combining 6.4 g of compound A with 50.0 g of ethanol_ Calculate the boiling point of the solution Assume compound Ais a non electro...

Question

A student prepares a solution by combining 6.4 g of compound A with 50.0 g of ethanol_ Calculate the boiling point of the solution Assume compound Ais a non electrolyte and has a molar mass equal to 152.14 g/mole: The Kb of ethanol is equal to 1.22 "Clm and pure ethanol boils at 78.5*C. Your answer should have precision to the tenths place

A student prepares a solution by combining 6.4 g of compound A with 50.0 g of ethanol_ Calculate the boiling point of the solution Assume compound Ais a non electrolyte and has a molar mass equal to 152.14 g/mole: The Kb of ethanol is equal to 1.22 "Clm and pure ethanol boils at 78.5*C. Your answer should have precision to the tenths place



Answers

The boiling point of ethanol $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)$ is $78.5^{\circ} \mathrm{C} .$ What is the boiling point of a solution of 6.4 $\mathrm{g}$ of vanillin $(\mathscr{M}=$
152.14 $\mathrm{g} / \mathrm{mol}$ ) in 50.0 $\mathrm{g}$ of ethanol $\left(K_{\mathrm{b}} \text { of ethanol }=1.22^{\circ} \mathrm{C} / \mathrm{m}\right) ?$

Vueling Morning point is the temperature at which the per pressure on the liquid becomes equal toe atmospheric pressure. That is $760 depression. And the pressure is given my their top P musical stroke. Eggs salute. Peanut off solvent where X is more factional. Salute on DPI. Note is insolvent is the pressure of the solvent and Delta P is changing the pressure. Oh, no. Le p is 7 16 minus 70 7. 40 tour and yeah, next salute on 7. 60. Tar this was on 22 or excessively ought into seven tips. Tree door X off snoot can be on this point 0 to 6. The Moller myself salute Mama's off. The salute can be calculated as oh, number off malls off. Salute Divided by total number off. Total number off malls in solution, which is going to 0 to 6. Yeah, em one by m one thio m one on one class into my m two spine. Her past six. Yeah, yeah, yeah, No. One plus and two I can t o by. I'm one by m one is 38.4 six one glass 100 grounds. This week's grounds Permal at nine points 15 g from one with just 38.46 100 g. Empire 46 camp are more 9.15 ground floor, 1.59 point four on five ground. There's 37.46 Okay. Ah, subtracting one. So from here we can find the value of M one, which is approximately questo 1 58 g by log.

To calculate the boiling point, we need to know what the boiling point elevation equation is, its delta B. Which will be the change in the boiling point of the pure solvent when a salyut is added equal to the morality of the solution, multiplied by KB, which is the boiling point elevation constant for the solvent being used. In this case it's water. So how do we calculate morality, morality is moles of solute per kilogram of solvent? So we'll start with the 3 10 g of methanol. For ethanol, convert the grams into moles by dividing by the molar mass. Now we have moles of the sol ute will divide by the kilograms solvent, which we don't have. We just have mill leaders of the solvent water. If we assume a density of water being equal to one g per mil leader, we can then convert the middle leaders two g and then divide by 1000 to get into kilograms. We then multiply all of this, which is the morality of the salyut in the solvent, by the KB value for water, which is 0.512 degrees Celsius, Permal AL, and we get 3.45 degrees Celsius. This is the increase off of the normal boiling point of water, which is 100. So the new boiling point would be 100 and 3.45 degrees Celsius.

All right. So you were tasked with another boiling point elevation question. And so let's go ahead and get our bowling point equation up on our screen here. So it tells us that the change in bowling point when we add a non volatile saw you to a solvent is going to be equal to the van off. I factor times the boiling point, constant times the morality. And so, in this case, what they're asking is to find is a normal bowling point of the solvent kind of based on the results when the bowling point was elevated due to the presence of the soul Butte. Okay. And so, essentially, what we're going to be doing toe find our final answer is solving for how much the bowling point change. They tell us that the bowling point was 79.1. And if we can figure out how much of a change that waas from the original bowling point, then we can subtract to find the original starting boiling point him before it was elevated. All right, so let's go ahead and fill in the information that we know. So our Salyut here's glucose, which is a CO Vaillant compound. Covent Compounds Event a factor one because they do not break in the multiple particles when dissolved and an assortment the came. But you was something that we had to look up in the textbook and that is specific to our solvent. Ethyl alcohol that has a value 1.22 degree Celsius times a kilogram. Permal. That's a set value for the solvent. Then the last portion that we need to solve for is the morality. The morality is defined as the moles of saw. You'd her the kilograms of solvent. And it's just another way to measure the concentration of decision. In this case are saw. You'd is glucose, and we're told that we have 26 grams of glucose, which has a chemical formula. C six, h 12 06 So what we'll do to convert from grams to moles is will add up the molar masses of six carbons. 12 hydrogen zand, six oxygen's from the periodic table that results in overall mass of 180.18 grams. To find our number of moles will divide 26 divided by 1 80.18 and that tells us that for our Salyut. We have 0.1 core, four moles of it. That's what we'll go in the numerator when we're solving for morality. Next, we need to find the kilograms of soul in which is ethyl alcohol. They tell us that we have 285 brands of ethyl alcohol when going from grams. Two kilograms you divide by 1000 which is the same is moving the decimal place three spots to the ride. This is going to result in value and point to 85 kilograms of our solvent. And so what we can do is go ahead and plug that in, just as is. That's that's 0.1 44 divided by point to 85 that will make her answer a little more accurate. Armpits. Let's go ahead and multiply everything together one times 1.20 times 0.144 divided by 0.285 And make sure that this last part in parentheses and so what? Lincoln's for us for the change in boiling point because it tells us that it has changed by 0.0.62 degrees Celsius. Now take note because this is not why our final answer So what this dope it eBay means is it's telling us the bowling point was elevated by this much. So when we have done this experiment, the bowling point was measured at 21 or excuse me is 79.1 degrees Celsius, and so if it was raised by 0.62 degrees Celsius, what we have to do is subtract to find the original bowling point. So if we do 79.1 minus 1.62 what that gets us for our original boiling point with 78.5 more or less degrees Celsius for the original boiling point before it was elevated.

Well, first, um, calculate the number of moles. 35 grams of the, uh known electrolytes were not told exactly what it is, but we're told that the molar mass is 58 grams for more so we can calculate numbers of moles, which is 580.6 serum. Oh, we can then calculate the morality, which is moles of Saul Utes over kilograms of water. We're told that we have 600 grams of water, which is 6000.6 kilograms of H 20 and then that leaves us with the morality of just one. We can now calculates the boiling point elevation. Since it's a non electrolyte, we do not need the Vantaa factor. The constant for water is 0.512 degrees Celsius for Melo will ality and the boiling point elevation is 0.0.512 degrees Celsius. The come bowling point of pure water. Uh, at uh during this experiment, we're told his 99.7 to 5 degrees Celsius plus the elevation of 50.512 degrees Celsius, would leave us with a boiling point elevation of 100.237 degrees Celsius.


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