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A solution contains 0.0400 M Ca?+ and 0.0990 M Agt. If solid Na_POs is added t0 this mixture; which of the phosphate species would precipitate OUt of solution first...

Question

A solution contains 0.0400 M Ca?+ and 0.0990 M Agt. If solid Na_POs is added t0 this mixture; which of the phosphate species would precipitate OUt of solution first? Caz(PO4)2 AgsPO4 NagPO4When thc sccond cation just starts t0 precipitate , what percentage Of thecalonFn in solution?perccntagc:

A solution contains 0.0400 M Ca?+ and 0.0990 M Agt. If solid Na_POs is added t0 this mixture; which of the phosphate species would precipitate OUt of solution first? Caz(PO4)2 AgsPO4 NagPO4 When thc sccond cation just starts t0 precipitate , what percentage Of the calon Fn in solution? perccntagc:



Answers

Three solutions are mixed together to form a single solution; in the final solution, there are $0.2 \mathrm{~mol} \mathrm{~Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}$ $0.1 \mathrm{~mol} \mathrm{Na}_{2} \mathrm{~S}$, and $0.1 \mathrm{~mol} \mathrm{CaCl}_{2}$ present. What solid(s) will precipitate?

For part A. When these three Ionic solutions air mixed, we have sodium sulfates and as a chloride, too. And berry, um, sign aids. Um, which solutions will be precipitated out. So we will produce BSO four on zinc sign, eat and, uh, to in a c l A quiz. So, uh, that is balanced. Our precipitates would be B A s 04 and Zet n c n two for part B were asked, What is the morality of each iron assuming complete precipitation. So, assuming complete precipitation, we're going Thio have the total volume is 250 mill leaders from all three solutions N a two s 04 would associate to an A plus and s 04 to minus and we're told that similarity is 0.1 Moeller so sodium what you would point to Mueller and s 4.1 Mueller, we have 100 mL of the two s, l four. Um, we have zed n c l two todo zinc two plus to see off minus. And this is three Mohler's 0.3 Moeller and six Smolar and this is 50 mL and we also have B A, C N to be a two plus two CN minus. Went to Moller 3.2 Moeller four Moeller And this is also at 100 mL. So from here, we can solve for the morality of the S 04 to minus way that we have 0.1 Moeller and it will be 100 0 millimeters it per 250 mL. And this would be equal to 2.0 400 Moeller. The Moliere ity of the variants you plus will be 200 Moeller 100 mL, 2 50 mL Of the total volume of this or cow took 500.800 Mueller so okay, 0.400 Moeller be a two plus will react with 0.0 for points. Sorry, this should be 0.400 Moeller 400 Moeller s four to minus, um so there will be no s 04 to minus left in the resulting solution morality of be a two plus in the resulting solution is going to be put 0400 Moeller left over in excess. Let's look at the morality of the zinc two plus, which will be equal 2.300 Moeller, 50 mL, 2 50 mL Yes to this workout 0.600 Mueller and the polarity of a C minus is equal to 400 Mueller on 100 mL over 250 mL. This is equal 2.16 year old Mueller. So, UH, 0.600 Moeller Zed and two plus or react with points 0.1 to 0 Moeller CN minus So zinc two plus, um so So there will be no zinc two plus in the resulting solution, the morality of the sea ed minus in the resulting solution would be equal to point 16 by this 0.1 to 0 to be with the 0.400 Mueller and the morality of the In a plus, things does not precipitate. So this will be a 0.200 Mueller times 100 0 mL over the 2 50.0 mL. This is going to be equal to 0.800 Moeller and the polarity of the C L minus is equal to point. It's six Moeller 50 mL over the final government to 50 mL. This will be equal to uh huh 0.1 to 0 Moeller. So in summary here, the malaria t of the zinc two plus in the resulting solution of zero the morality of the barium two plus in the resulting solution is 20.400 Moeller the morality of the n A plus and the resulting solution is 0.800 Mueller the mill arat e of the S 04 to minus and the resulting solution is zero the morality of the CN minus and the resulting solution is 0.400 Mueller and the mill Arat E of the C L minus and the resulting solution is 0.1 to 0 Mueller.

This next question is a very challenging question. It's a two equation to unknown question. We have a solution that contains silver and mercury and it's going to be reacting with an iodide solution, sodium iodide. So we need to know the reaction between iodide and silver, and the reaction between iodide and mercury two plus reaction between silver and iodide is a 1 to 1 strike geometric relationship, but between mercury two and iodide, it's a 2 to 1 relationship. Okay, both of these reactions will occur when we add the sodium nitrate. I'm sorry, the sodium iodide to a solution containing both of these cat ions, the total moles of iodide that is required to react with all of the silver. And the mercury can be determined by taking the polarity of the sodium iodide solution that reacted with a solution containing silver and mercury and multiply it by the volume of the sodium iodide solution and we get 0.1 to two moles of iodide. I'm now going to take some liberty and define a couple variables. I'm going to say that X. Is the mass of silver iodide that is formed. And why will be the mass of the mercury to iodide that is formed these two right here, and the sum of those two will be the value that was given 28.1 g. So now I know the total moles of iodide that was required to make this mass of these two X and Y products. Why could be calculated as 28.1 minus X. This will become important in a minute. So if I know the total moles of iodide, I should be able to if I actually knew the massive silver iodide and mercury to iodide. If I knew these two masses, I could calculate in reverse the moles of iodide that would be required. The total moles of iodide that would be required by summing the moles of iodide required for the formation of each mass um of the precipitate silver iodide and mercury to iodide. How would I do that? I would take the mass of silver divided by its smaller mass to get the moles of silver iodide, then knowing the moles of silver iodide and the story geometric relationship of 1 to 1 between silver iodide and I died. This would give me the moles of iodide required to make this mass of silver iodide. I'll then add that to the moles of iodide required to make the Y mass of mercury too. I had died by taking the massive mercury to iodide, dividing by its molar mass to get the moles of mercury to iodide, and then converting the moles of mercury to iodide into moles. Iodide using the 2 to 1 strike geometric relationship. This was the hard part setting up the problem was the hard part. We now have two equations, this one and this one and two unknowns X and Y. Hopefully you can see that I can replace 28.1 minus X. For why. And then I will end up with one equation and one unknown. And all I need to do now is sulfur X. X. Being the value that was requested. The massive silver iodide in the precipitate. So with a little smoky geometry, this simplifies to 4 to 59 times 10 the negative three. And then this simplifies to 28.1 minus X. Multiplied by 44 times 10 to the negative three. I distribute the 44 times 10 to the negative three through. And I will get this as my expression, I'll then collect my ex terms and collect my non X terms. And then divide all sides of the equation by negative 1419 times 10. The negative four and X is 11.8 g silver iodide.

So from the solution mixture we'LL have to find out the possible combination of the positive and negative ions that we form compound So I only compounds and we'LL have to check if they're water soluble or water insoluble and for a solid to form a precipitate in equals solution that's solid Need Toby water insoluble selects first right down the compounds we have here First one is lead acid in Then we have sodium self fight and finally we have calcium chloride First just make sure that all of these air water soluble So if we look at the saloon, Richard off Diane's will see that all the acid eaters are water soluble. That means later city. It is also water soluble and we'LL see that all the alkali metal compounds the water sea level and sorry, um, being an alkali metal that Miss sodium sulphide is also water soluble. And if you look at calcium chloride, all the calcium czar also sorry will accept some exceptions and kill shame is no exception Theirs That means Kenshin crew is also soluble in water so we don't have any water in soluble Sze solid here. That means now we have to We have to go find the ions that will be formed from this compounds Selena City. It will be to be we'LL form a letdown and as sitting down in an AC was solution and then sodium self I ttle form in a plus and self I down We have to sodium here and we have to tow and seated here And calcium chloride will be disassociated as Gil Sherman and the ride down Now we have to look for positive get on and on the combination for the solids and we'Ll have to look for if their water soluble are are insoluble And based on that we'Ll be able to see whether our which soliders will from the precipitated in this election Mr So First we'Ll combine the late cat town with the rest of the to announce here So fight and glow right And if we write them down we'Ll have blessed sulfide and let chlo Right then if we go for sodium um sorry, um will have toe possible combination with acid ate and Clu Wright. But as they always say that all the sodium compounds are all elderly, metal components are always salute in water so we can We can ignore the sodium combinations because sorry, um, comports will always be soluble in water and they cannot form a precipitate in unequal solution. Now we look for calcium. So two possible combination for calcium are as critical shamus civilian care and kills himself. Fight. And so if we can right here calcium as sitting and killed himself. Fight now from this four, we have toe look for their solid ability. And if we look at the salary chair will see that Ah, all the cell fights are normally normally insulin in soluble in water solution, request solution. But there are some exceptions and ladies no exceptions. That means late sulfide is insoluble in equal solution and that means it will form a solid precipitate so late will be our answer. And if we look at the celebrity charge, will see that all the clerks are usually soluble. But there are some exceptions and ladies an exception. That means let's go write is also insulin water. That means let red will also form precipitate from the from the solution. Mr. We have now, as you've already said that, um all the all the acid. Here's the water So level that means calcium carbonate is also water soluble and it will not form a solid precipitate. And then if we look at Cal's yourself, I'd we'll see that we'LL see that most of the salvage rights are water insoluble, but there are some exceptions, and calcium is an exception that mean kills himself. Fight is water soluble and it will not form a solid precipitate. So our answer is live sulfide and lead chloride will form the solid precipitate in the solution, Mr Given.

This question were told that we have their want to moral crow mates. It's a coven. Eights. I own hand right higher. And, uh, if they heard it, the other solution of silver nitrate switch off this weird first precipitate. So we have given the key s before they see Vikram rates for company Temple. Cool, right? So I'm writing a dish issue shin off the, uh, salts. And, uh, this is prettiest. See a tree to Linus Dan Seiver chloride or produce a cheap loss. Waas CIA Linus Okay, so less That's what's ah ee teach you Seattle for ksb being questioned The concentration of PG plus square one supplied by concentration of Seattle full remind us and, uh, we're given the, um the concentration of the chrome it's to be Is there a point to So this is zero point you and she Full square is the question The key s p for the cruelty to say won't want to 10 Stanish power My ass too, huh? Sorry. Concentration offs Even you did would be I want you 1.2 times. Terrorists by minus drawer. He founded by one to you and the square roots of the answer said it should be two point fall time Stairs Power Saraswati minus six Mortar. So that is the amount off. Um, see the high only. And it's to get studio. Uh, son of diligent products. Now we can go to the next one, which is the civil cabinets. So we have a G to see you. Three Casby. That's would be e G Boss Square much Bye bye. Still teaching minors And this quests are coming from the question with Britain because we are two into here. Okay, so the kiss beautiful Deceiver Uh, Coven ages. It's wants one. Science stands by minus truck will be age it, boss. Swear I want to fly by. Concentration off the carbonate is zero once one Okay, so hey, Gee, boss, concentration would be, you know So this should be nine standards to power wants minus six roller and then 40. Hey, gcl ksb. We'll be your quest to you, Agent Waas What's a blind eye CEO Linus Ke sp is given to us to be one wants eights. Times tears by minus 10. It was to aid you plus concentration off CIA miners is, um 0.1 Careful, Agent lost concentration and it will be four point age. I'm standing by my understand? Yeah. So this of you one point Age, time, standards to power wants, understands well, hates motor. So the question access, which will what's is the first compounds precipitates. So the one would, uh uh, you know, West concentration off Seaver needed would be the first ones you precipitates, and that's going to be to see about it. All right, so cva chloride, we're precipitate first thing, okay?


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