5

Questlon 1 4pts . Set Dctalls {or MnolcNctt questionG2lHml mectanYou can reiny this question belovthe Dosmos craph Limits and Continuity: Informa entrst tna follotn...

Question

Questlon 1 4pts . Set Dctalls {or MnolcNctt questionG2lHml mectanYou can reiny this question belovthe Dosmos craph Limits and Continuity: Informa entrst tna follotnna Qucslion: Drag tha blue polnt cunently locahd al (7 ") te (7 [J You may also Ui INE numerical slder for /After making thls adjustment to the Desos graph , the numerical velue Of tha Uimit at, =70Atter Qaking thl: adjuslincnt (0 {hc Desmo' graph the value ofthe functionBy using the -lder for Tu drecging thc red polnt curre

Questlon 1 4 pts . Set Dctalls {or Mnolc Nctt question G2lHml mectan You can reiny this question belov the Dosmos craph Limits and Continuity: Informa entrst tna follotnna Qucslion: Drag tha blue polnt cunently locahd al (7 ") te (7 [J You may also Ui INE numerical slder for / After making thls adjustment to the Desos graph , the numerical velue Of tha Uimit at, =70 Atter Qaking thl: adjuslincnt (0 {hc Desmo' graph the value ofthe function By using the -lder for Tu drecging thc red polnt currently locatcd at (5,2). explorc Urc 50857 * * Jncroises Itom C rncucn contuous e Queon Help: 0ves #RL isuructot Submiit Queston are To Sentch W E scotc 0411



Answers

Figure $32-37 a$ is a one-axis graph along which two of the allowed energy values (levels) of an atom are plotted. When the atom is placed in a magnetic field of $0.500 \mathrm{~T}$, the graph changes to that of Fig. $32-37 b$ because of the energy associated with $\vec{\mu}_{\text {orb }} \cdot \vec{B}$. (We neglect $\vec{\mu}_{s^{*}}$ ) Level $E_{1}$ is unchanged, but level $E_{2}$ splits into a (closely spaced) triplet of levels. What are the allowed values of $m_{\ell}$ associated with (a) energy level $E_{1}$ and (b) energy level $E_{2}$ ? (c) In joules, what amount of energy is represented by the spacing between the triplet levels?

Yeah. For this given problem we want to show the graph of the butterfly occur which is given by R equals E to the code signed data. Read it too. Co signed for theater. Yes, time. Cute. Ada over four. Yeah. Once this is cubed will have our butterfly graph. That's right here is the resulting butterfly graph that we see. I'm given to us on the page. We can state the parameter we need well notice that co sign is fine because we'll go more than enough through the given interval. However this right here sign of data over four we're going to need to have um so we get sign of two pot are two pi at some point because that's when the graph starts over. So we see that data needs to be a pie in order to ensure that's the case.

Atom that has to energy levels. And we place this system in ice extent of magnetic field and he happens. I split in the second energy level, and we want to know where are they are over. I lose for ml for the energy level off the one and a two. So the potential energy off the atom in association with the presents over and cashed in a magnetic field is given by you. Is it going toe minus mu or the tone be external? Mmm mmm. And this is retained terms of the magnetic moment. So there's this minus L you be bar magnet be extended for you on There is no change in their energy. So we have that for a M. L is equal to zero for you to the single level splits into a trip it in the presence off their sin a magnetic field. So we have the possible violence off M l. A 01 and minus one for part C. We want to know what amount of energy is represented by the spacing between the people levels. And we can find this by finding the variation of the energy. So we have this as Delta M. L. Mu Bai, my mentor field and the various showoff ml is one. So this gives us A and B a sterile field, and this is 9.27 times 10 to the minus. 24 Jews Kessler times 0.5 Kessler. This is 4.64 time stand to the minus 24 Jones.

We are going to be placing this polar equation into our calculator. Um But before we do that we are going to set our screen so that we can actually see the resulting graph. So our angle step I always use the same. I like to use pi over 20 for that. Just allows for as many plots so that I can actually see a nice continuous curve. Now my angles are given its told that we're gonna be going from 0 to 12 pie so I can place those in and then as far as my X men X max and my wyman why max remember with polar, no matter where I am directed um You know I have a max value here of E to the 0.1 times at 12 pie. So my X men I'm gonna put a negative and then of course I can multiply 12 by 120.1. So I'll use that 1.2 pi. Now most calculators you can actually put you know um numbers like this into your X men and X max or you can find its actual value to place in. So what you see here is just like you would expect the um function E to a power it um you know gets exponential growth is going to get bigger and bigger and bigger quite quickly. So you can see that as it spirals the tighter spiral and then the spiral definitely ends up um having bigger and bigger radius is as it goes a radio i as it goes

Okay we're given a polar equation to grab but before we do that we need to be able to um set our window criteria. So Arteta step I'm gonna be using a pie over 20 for this is just gonna allow enough points to be plotted that will show nice and continuous. Our angles are actually given we're told we're going to be going from a negative 1.2 to a positive 1.2. So I'm going to consider um what kind of that max and min values of this will be. So I'm gonna go ahead and put 1.2 and take it to the third power and then subtract 1.2. What I end up giving getting is that .5-8. Now whether I'm putting the positive value in or the negative value in I get that .5-8. Either negative or positive. But remember with a polar function negative and positive isn't so important right? It's just that it's going that direction. So I use that as all my criteria. You can see from our graph here that maybe we didn't need that full amount for the X. Or even the negative Y. But by making my window that you know I'm able to see my whole curve


Similar Solved Questions

4 answers
8 Gaseous Subinit miscaiculalions If the 8 W erro; has been deteciod in your anst { for this reaction | of azomethane 8 V Check ior lypos flask the 5 min how much first-order reaction remains after 0.0S00 hour? when bcated:
8 Gaseous Subinit miscaiculalions If the 8 W erro; has been deteciod in your anst { for this reaction | of azomethane 8 V Check ior lypos flask the 5 min how much first-order reaction remains after 0.0S00 hour? when bcated:...
5 answers
Solubi Imy of Ag 3p0- tnc 1. Kx [epueSenis Iht molar solubimy procluut fol Ihis Sall wouid bc
solubi Imy of Ag 3p0- tnc 1. Kx [epueSenis Iht molar solubimy procluut fol Ihis Sall wouid bc...
5 answers
23.26 A total electric charge of 3.50 nC is distributed uniformly over the surface of a metal sphere with radius of 24.0 cm, If the potential is zero at a point at infinity, find the value of the potential at the following distances from the center of the sphere: 48.0 - cm; (b) 24.0 cm; (c) 12.0 cm.
23.26 A total electric charge of 3.50 nC is distributed uniformly over the surface of a metal sphere with radius of 24.0 cm, If the potential is zero at a point at infinity, find the value of the potential at the following distances from the center of the sphere: 48.0 - cm; (b) 24.0 cm; (c) 12.0 cm....
1 answers
Let Lie algebra be spanned by the generators I,y;_ subject to the relations [I,y] = > ly,2] = [&,1] = Show that the dimension of the Lie algebra is at most one:
Let Lie algebra be spanned by the generators I,y;_ subject to the relations [I,y] = > ly,2] = [&,1] = Show that the dimension of the Lie algebra is at most one:...
5 answers
Dectnat aenzte6153 40x42i3mibITe54236 133mmpZp 1Fak 132854280 83
Dectnat aenzte 6153 40x42 i3mibI Te5 4236 1 33mmp Zp 1 Fak 1 3285 4280 83...
5 answers
QuestionConvert each Dinary number t0 nexadecimal 1010 1010NotvatenswamdMenai o; jLoDp fei QurstidtSelect one;a.100.CC,6 C FF4IOTHER '2.AAje THIE8: BB;
Question Convert each Dinary number t0 nexadecimal 1010 1010 Notvatenswamd Menai o; jLoD p fei Qurstidt Select one; a.10 0.CC,6 C FF 4IOTHER '2.AAje THIE 8: BB;...
5 answers
12.3.13Quaston HelpFind the 2rc lengu darmeiet akmg the cutve trompoint wbereevahaling Ue inlogual 5 Ivldr Then Ind the length ol te tdcaied poruon al Ihe curar) = (2 <' cosf)i+ (22' sint)]+22' In421<0The arc lengti patumeter [s s() = (Typa An Bictansiyc ulind n ccmT1u4 Ued
12.3.13 Quaston Help Find the 2rc lengu darmeiet akmg the cutve trom point wbere evahaling Ue inlogual 5 Ivldr Then Ind the length ol te tdcaied poruon al Ihe cura r) = (2 <' cosf)i+ (22' sint)]+22' In421<0 The arc lengti patumeter [s s() = (Typa An Bictansiyc ulind n ccm T1u4 ...
5 answers
044F%urerrztue QNE1at & Tas [ Arttul Lalhimm %4
044F%u rerrztue QNE1at & Tas [ Arttul Lalhimm %4...
5 answers
Show arrow pushing mechanism for the following reactio HBr BrOH
Show arrow pushing mechanism for the following reactio HBr Br OH...
1 answers
Determine whether the series converges or diverges. $$\sum \frac{11}{1+100^{-2}}$$
Determine whether the series converges or diverges. $$\sum \frac{11}{1+100^{-2}}$$...
4 answers
The decomposition of hydrogen iodide on finely divided gold at 1509C is zero order with respect to HI, The rate defined below is constant at 1.20 x 10 molL s2 HI(g) 4" H2(g) + 1z(g) [HI] Rate k=1.20 X 10-4 mol/L - AtIf the initial HI concentration was 0.400 mol/L; calculate the concentration of HI at 24 minutes after the start of the reaction:ConcentrationMHow long will it take for all of the 0.400 M HI to decompose?Timemin
The decomposition of hydrogen iodide on finely divided gold at 1509C is zero order with respect to HI, The rate defined below is constant at 1.20 x 10 molL s 2 HI(g) 4" H2(g) + 1z(g) [HI] Rate k=1.20 X 10-4 mol/L - At If the initial HI concentration was 0.400 mol/L; calculate the concentration ...
5 answers
Dimmecric enuamionsXilt; YeYi describe theIlne segment that JoinsQnereToinis Pi(ri, Yi)Pz(*2+ Y2)-Jraphing deyiceJnwthe trlan Wth vertices Aii B( s, 4), C(1,Flndthe Danmernanan ncidingnonointssketchchecknsiyencommaDTnclcnscerms Oft)3:
dimmecric enuamions Xilt; YeYi describe theIlne segment that Joins Qnere Toinis Pi(ri, Yi) Pz(*2+ Y2)- Jraphing deyice Jnwthe trlan Wth vertices Aii B( s, 4), C(1, Flndthe Danmernanan nciding nonoints sketch check nsiyen comma DTnclcns cerms Oft) 3:...
5 answers
The initial rotation of the disk is @0 19 rad/s and it's subjected to a constant angular acceleration of a = 15 rad/s? Determine the magnitude of the velocity of point A at the instant t = 2.2 s. Round your answer to three significant digits.(00.4m0.5 m--8A
The initial rotation of the disk is @0 19 rad/s and it's subjected to a constant angular acceleration of a = 15 rad/s? Determine the magnitude of the velocity of point A at the instant t = 2.2 s. Round your answer to three significant digits. (0 0.4m 0.5 m--8A...
5 answers
Which of the following molecules are chiral?NHz H ~COOHOHOHOH
Which of the following molecules are chiral? NHz H ~COOH OH OH OH...
5 answers
(8 points)Evaluate the integral"/3 8 l(tan(z)) dc "/{4 sin(1) cos(€)
(8 points) Evaluate the integral "/3 8 l(tan(z)) dc "/{4 sin(1) cos(€)...
5 answers
Part AS MeaUsing Nowton'8 [ laws; calculale n , (he Express your answer magnilude ol Ihe narmal lorce Ihat _ nowtons (ho Hoor exorts on mho == Vlew chait Avallable Hint(s)Azd
Part A S Mea Using Nowton'8 [ laws; calculale n , (he Express your answer magnilude ol Ihe narmal lorce Ihat _ nowtons (ho Hoor exorts on mho == Vlew chait Avallable Hint(s) Azd...
5 answers
Describe the end behavior ol the graph of the polynomial lunction:Ix)=526 4x" +x2 - 3Choose the corect answer below;0 D.
Describe the end behavior ol the graph of the polynomial lunction: Ix)=526 4x" +x2 - 3 Choose the corect answer below; 0 D....

-- 0.019728--