5

3. In the reaction 2NOz(g) <77 NzO4(g) the initial concentration of NOz was 0.250M and NzO4 was 0,000 At-equilibrium; the concentration NzOa was measured 0.0133M...

Question

3. In the reaction 2NOz(g) <77 NzO4(g) the initial concentration of NOz was 0.250M and NzO4 was 0,000 At-equilibrium; the concentration NzOa was measured 0.0133M.Calculate the equilibrium concentration Of NOz (W) Calculate Kc

3. In the reaction 2NOz(g) <77 NzO4(g) the initial concentration of NOz was 0.250M and NzO4 was 0,000 At-equilibrium; the concentration NzOa was measured 0.0133M. Calculate the equilibrium concentration Of NOz (W) Calculate Kc



Answers

For the reaction, Kc = 0.513 at 500 K.
If a reaction vessel initially contains an N2O4 concentration of
0.0500 M at 500 K, what are the equilibrium concentrations of
N2O4 and NO2 at 500 K?

First step is to determine whether solid, edgy I owe three forms. Don't do this. We need to calculate the concentration off silver. Ah, nde are your three negative mix. Using these formula? We can determine the concentration substituting the values we have. Emily Michael played with 0.200 divided by 100 move, which gives us the value off little 0.1 mullah for the 2nd 1 substituting the value stable points you 100 divided by 100. The value to know Toby 0.0 five Moola. Now we need to determine the value off Q, which will be equal to the concentration off product substituting the randy okay, multiplied by 0.0 fight. It gives us the Vandy off for you multiply 10 days to problem minus six. In this case, the value off cue is larger than ks being, so precipitation will occur. No. The next step is to run the precipitation equilibrium reaction as represented over here, along with before and after concentrations for dough. We need to note that excess off Ayotte really means after precipitation reaction goes to completion, so concentration off I want three negative excess frequents. 0.400 Divided by 100 equals 0.0 for Mullah. Although we have assumed that Eiji Positive is completely consumed, we know that Eiji positive concentration will not be zero at equilibrium. Let me represent it. Reaction Eiji, are your tree gifts e g border? Do yes. Are you three negative and gai sp? He quote concentration off 80 positive on DDE are you? Three negative equals three points. It'll 10 days toe or negative eight Now we'll be right Initial and equally broom concentration I see will be initial concentration on DDE e C will be equally grim concentration. So for a G for the two equals zero Molo on for this would we have X concentration off? I owe three negative 0.4 And for the right side equilibrium the 0.4 plus x as x more poor leader A g r u tree dissolves So make the reaction reached equilibrium No! We calculate the KSB as 3.0 10 days. Tobar. Negative eight equals the concentration off Eiji positive on DDE. I owe three negative substituting in the value we have X multiplied with 0.4 plus x x that is concentration off a G positive at equally broom. Don't know Toby seven point for you multiply 10 days to burn minus six Mullah.

So the equilibrium constant of a chemical reaction is the reaction quotient at equilibrium. So this is a state approached by a dynamic chemical system. After enough time has passed at which its composition has no measurable tendency towards further change and chemistry. Our concentration were fast to the amount of a substance that is in a defined space, where our concentration can be expressed in terms of must pay unit volume. So we're looking at the following reaction here of two eso To add 02 is an equilibrium with two eso three. So given the information in the following values, we will be determining a concentration value. So the equation that we're needing to use is R K equilibrium, constant equation where we have our product concentrations multiplied by the street. You metric coefficients over the starting material concentrations also multiplied by their strike you metric coefficients. However, this has been arranged. Where s 02 concentration is thesis object off our problem now where we have a streaking metric coefficient of two. So that means we square root are valued to generate no 0.52 as our missing folly

So let's figure out what the equilibrium concentrations are for each of these substances by setting up an ice table. Now if we know what the initial concentrations are of the S. 03 and um the N. O. We can plug that into the initial line. But we plug in polarities. So we're told that we have 0.240 moles of each of these in a two liter container. So when we take molds and divide by leaders or 20.240 divided by two. Each of the polarities are .1-0. So make sure you put polarities into your ice table and we don't have any of our right side. So we're gonna have to make some right side. Which means that the right side is going to go up, the left side is gonna go down all of our coefficients in our chemical reaction or one. So let's look at the N. 02 1st I have to make some I don't know how much X. But I know for every N. 02 I make the same amount of S. 02 So that's gonna be X. I also know that for each N. 02 I make I have to use one N. O. Use the same amount and for the S. 03 of the same thing I use the same amount. So in equilibrium I started with .120. And it went down by a certain amount. Started with .120 went down by a certain amount started with none. Wind up by a certain amount started with none when up by a certain amount. Now I can write the law of mass action expression. So I can take my products and divide by my reactant since yeah I can now put those in X times X is X squared and 0.12 oh minus X times 0.12 oh minus X. 6.12 oh minus X Squared. And we know the value of the equilibrium constant is .5. All right. So why don't I put this to look like squares? Because now it's easy to just square root both sides. To make the math easy. So if I square root both sides, I get X Over .120 -1 Equals the Square Root of .5, which is .77. Now we'll go ahead and I'll cross multiply and then I'll collect life terms and solve for X. so .120 times .707 is point oh eight for eight And then .707 -1 is negative .707 x. And then when I cross multiply x times one his ex. So I'll collect like terms bring the X to the other side, Divide by 177. And I get X. Is equal to 004 nine seven. Okay so if I want to know what the concentrations are an equilibrium I have to go back to my ice table, N. 02 and S. 02 are represented by X. So in my polarity I have my concentrations of those two substances. So I know The concentration of n. 0. 2 And the concentration of S. 02. If I want the other ones I have to take .1-0 -1. Yeah. Yeah. Yeah. Mhm. Six. And that's point 0703 moles per liter. And that's the concentration of both My reactant. So is the concentration of S. 03. Mhm. And the concentration Havana. Yes.

For question 13.2 will use the equilibrium expressions that we wrote in 13.1 and substitute the values in the Miller d of S 03 We'll leave out units is 5.0 times 10 to the negative too Squared little come down here 4.0 times 10 to the negative three squared The polarity of S 02 is three 0.0 times 10 to the negative three, 3.0 times 10 to the negative three. And that squared 3.0 times 10 to the negative. Three squared and the polarity of 02 is 3.5 times 10 to the negative. Three. When we compute the answers here for a we'll get an equilibrium constant. That is 7.9 times 10 to the fourth. And for B, we're going to get in equilibrium constant.


Similar Solved Questions

5 answers
13.0.5/1 points Previous Answers SCalcET8 7.8.029. Determine whether the integral is convergent or divergent: 14 Vx+ 2 dx
13. 0.5/1 points Previous Answers SCalcET8 7.8.029. Determine whether the integral is convergent or divergent: 14 Vx+ 2 dx...
2 answers
70 (e-J84 (e-JYJs ! 0 = Gg + Gxg 4 Xe e 0 = he + 8h fyxs + cX'0 =t2 + ck + (xs + z* 341 01 1uJ3U11 J41 JO ado[S 341 JUJU1?12Q (sutod 02) :r -*7) te JnIn? Su MO[[Q}
70 (e-J84 (e-JYJs ! 0 = Gg + Gxg 4 Xe e 0 = he + 8h fyxs + cX '0 =t2 + ck + (xs + z* 341 01 1uJ3U11 J41 JO ado[S 341 JUJU1?12Q (sutod 02) :r -*7) te JnIn? Su MO[[Q}...
2 answers
Let A = {a,b,c} and consider the relation R : A -+ A defined by {(@,a), (b,6), (b,c)}. Draw the two-set arrow diagram for this relation.Draw the one-set arrow diagram for this relation:
Let A = {a,b,c} and consider the relation R : A -+ A defined by {(@,a), (b,6), (b,c)}. Draw the two-set arrow diagram for this relation. Draw the one-set arrow diagram for this relation:...
1 answers
Prove that the image of $A l t_{k}$ is the unique largest subspace of $\mathcal{T}^{k}(V)$ on which each permutation $\sigma$ in the symmetric group $S_{k}$ acts as multiplication by the scalar $\epsilon(\sigma)$.
Prove that the image of $A l t_{k}$ is the unique largest subspace of $\mathcal{T}^{k}(V)$ on which each permutation $\sigma$ in the symmetric group $S_{k}$ acts as multiplication by the scalar $\epsilon(\sigma)$....
1 answers
A Kennedy half-dollar has a mass that is $1.150 \times 10^{-2} \mathrm{~kg}$. The coin is a mixture of silver and copper, and in water weighs $0.1011 \mathrm{~N}$. Determine the mass of silver in the coin.
A Kennedy half-dollar has a mass that is $1.150 \times 10^{-2} \mathrm{~kg}$. The coin is a mixture of silver and copper, and in water weighs $0.1011 \mathrm{~N}$. Determine the mass of silver in the coin....
5 answers
Hmw8: Problem 25Prevlous ProbkemProblem ListNari Problempoint) Loi f(z,V) 6r" + Sjy 6v? + 6c 5v + 0, Find Iha bnearlzntion L(I,V) 0 f(z.w) a the point (2,2)L(I,vlFind an upper bound tor the magnnude Elol Ihe #OI Ihe approximation {(*,m) L(V) 2 < 02 2 < 0 2roctangle
Hmw8: Problem 25 Prevlous Probkem Problem List Nari Problem point) Loi f(z,V) 6r" + Sjy 6v? + 6c 5v + 0, Find Iha bnearlzntion L(I,V) 0 f(z.w) a the point (2,2) L(I,vl Find an upper bound tor the magnnude Elol Ihe #OI Ihe approximation {(*,m) L(V) 2 < 02 2 < 0 2 roctangle...
5 answers
I. Determine the Gram Formula Mass/Molar Mass of the following compounds (1 point each) Ca(OH)zMg;(POA)z FeSO4C4HsCuSO4 SH,O
I. Determine the Gram Formula Mass/Molar Mass of the following compounds (1 point each) Ca(OH)z Mg;(POA)z FeSO4 C4Hs CuSO4 SH,O...
5 answers
What is the sum of the oxidation numbers of the atoms in a molecule?
What is the sum of the oxidation numbers of the atoms in a molecule?...
5 answers
Find the labeled sideFind the measurement of a central angle subtended by an arc of lenth 12 ftcifcle radius #ifthe angle isFind the shaded areaSolve tanr for Sinz in the II-quadrant:
Find the labeled side Find the measurement of a central angle subtended by an arc of lenth 12 ft cifcle radius #ifthe angle is Find the shaded area Solve tanr for Sinz in the II-quadrant:...
5 answers
3 1 3 1 L 1 { ~la J 1 3 1 1 V 3 1 1 2
3 1 3 1 L 1 { ~la J 1 3 1 1 V 3 1 1 2...
4 answers
5.3.9Diagonalize the following matrix, possible:[-3 Select the correct choice below and, if necessary; fill in the answer box to complete your choice_For P =For P =For P-LThe matrix cannot be diagonalized_
5.3.9 Diagonalize the following matrix, possible: [-3 Select the correct choice below and, if necessary; fill in the answer box to complete your choice_ For P = For P = For P-L The matrix cannot be diagonalized_...
1 answers
In Exercises $1-6,$ sketch the interval $(a, b)$ on the $x$ -axis with the point $x_{0}$ inside. Then find a value of $\delta > 0$ such that for all $ x, 0 < \left|x-x_{0}\right| < \delta \Rightarrow a < x < b$ $$ a=2.7591, \quad b=3.2391, \quad x_{0}=3 $$
In Exercises $1-6,$ sketch the interval $(a, b)$ on the $x$ -axis with the point $x_{0}$ inside. Then find a value of $\delta > 0$ such that for all $ x, 0 < \left|x-x_{0}\right| < \delta \Rightarrow a < x < b$ $$ a=2.7591, \quad b=3.2391, \quad x_{0}=3 $$...
5 answers
SORU k A bulunuz.0,8 44=0,6 P =0,2 P =0,4 olduguna gore Pl M nin degerini
SORU k A bulunuz. 0,8 44=0,6 P =0,2 P =0,4 olduguna gore Pl M nin degerini...
5 answers
MteanlOc /0Ataheee(leatieea
Mteanl Oc /0 Ataheee(leati ee a...
5 answers
A veterinary anatomist measured the density of nerve cells at a specified site in the intestine of fourteen horses Each density value is the average of counts Of nerve cells in five equal sections of tissue. Use the sign test to determine if there is sufficient evidence that the median nerve cell density at this site is below 35 [0 = 0.10]85 11.2 14.2 17.0 18.6 19.0 23.2 28.4 35.0 35.0 36.1 38.5 42.3 45.7
A veterinary anatomist measured the density of nerve cells at a specified site in the intestine of fourteen horses Each density value is the average of counts Of nerve cells in five equal sections of tissue. Use the sign test to determine if there is sufficient evidence that the median nerve cell de...

-- 0.017728--