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Ardloactivo substance docaya nccordina Io tho cqwntiouu 6n1e duulownl remaininq @ner $Ornu obaorvud |nioAo()': whetobyhours ,oriqinI AinouuIha bunticnc; HaaPro...

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Ardloactivo substance docaya nccordina Io tho cqwntiouu 6n1e duulownl remaininq @ner $Ornu obaorvud |nioAo()': whetobyhours ,oriqinI AinouuIha bunticnc; HaaProvided sOenbsl (ecotded an Inital amounl 0 740 gtums o the subsijnce, Juluuinu /10" Iona Ine acionIlsh will uxpucl t0 Wuli Iat Die substtnce havo 8 mase 0/ 106 grams Round your answor Io 2-ceciupl placosNumberhours

Ardloactivo substance docaya nccordina Io tho cqwntiouu 6n1e duulownl remaininq @ner $Ornu obaorvud |nio Ao()': whetoby hours , oriqinI Ainouu Iha bunticnc; Haa Provided sOenbsl (ecotded an Inital amounl 0 740 gtums o the subsijnce, Juluuinu /10" Iona Ine acionIlsh will uxpucl t0 Wuli Iat Die substtnce havo 8 mase 0/ 106 grams Round your answor Io 2-ceciupl placos Number hours



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Gallium-67$$\left(t_{1 / 2}=78.25 \text { hours }\right)$$ is used in the medical diagnosis of certain kinds of tumors. If you ingest a compound containing 0.015 mg of this isotope, what mass (in milligrams) remains in your body after 13 days? (Assume none is excreted.)

We were given a function A of T that represents the radioactive substance left over in kilograms after tea days in part A. We want to find the mass at time T equals zero. So a of zero is what we want. It would be five times eat an egg. A 0.347 time zero s o e to the power zero is one. So that will just be five kilograms in part B. We want to find the mass after 10 days. So a of 10 is that we're trying to calculate it'll be five e thing of 0.347 times 10. And if we put that to a calculator, that's e to the power of negative 0347 times 10 times five. So that would be 3.53 kilograms in part C were asked to sketch this graph, so I will just copy and paste that here it's just resize this so that we can see this is the graph for the function part, See, and part d. It's asking us to use this graph to approximate what the half life is. So if we started at five. We want to see how long it takes for it to lose half of its substance. So 2.5 is what we want to find. So when wise Eagle 2.5, I've created a horizontal line here and we can see that the intersection point is at X equals 40 equals 19.975 and ah, this 19.975 is the amount of days that would lead to having a substance of 2.5 kilograms. So to the nearest day, we're talking about 20 days for this halfway.

In this problem were given three different compounds, and we're trying to find the percent mass for each element in that compound. So first thing we have to do is to find our molar mass. So the first compound is caffeine, and so we're gonna be using our periodic table to find help us find our Miller Masters. Were you having carbon, hydrogen, nitrogen and oxygen to help us get the molar mass? So we're gonna have, um, eight times 12.1 plus 10 times 1.8 plus two times 14.1 plus two times 16 point. Oh, um, And before we add, all of, just do all of that, we can go ahead and find are the what each one of these values are Because we're gonna need that to foot in order to find the percent masks for each element. And so eight times 12.1 gives us 96.8 10 times 1.8 gives us 10.8 Um, two times 40 No. One is 28.2 and two times 16 is 32. So now we find that our total mass for our compound is going to equal 1 66.18 grams so defined our percent mass. We're gonna take each one of these values and divide it by our total mass to get the percentage off that the mass per element in the compound. So first for carbon is going to be 96.8, divided by R 1 66.18 and that gives us 57.8%. So I already turned the decimal into a percentage for hydrogen. We have 10.8 divided by the 1 66.18 and we get 6.7%. Uh, in the calculator, obviously be 0.0, uh, 607 But again, I'm just putting it right into the percentage for nitrogen. We have 28.2 divided by their 1 66.18 We get 16.86%. And finally, for oxygen, we have 32 divided by R 1 66.18 and we get 19.26 Her sense for our next compound we have Oops, uh, carbon, hydrogen and oxygen here. So we're gonna have a ton. 10 times 12.1 plus 20 times. One point. +08 plus 16 point. Oh, again, we're going to figure out what each one of these is. So it's 1 20 0.10 and 20 points. 16 um, and obviously for oxygen, we just leave it alone. Um, and we have that this total comes out to be 1 56.26 grams. So now doing are each of our elements for carbon. We're gonna have 1 20.10 divided by 1 56.26 And we have 76.86% for hydrogen. We have 20.16 divided by 1 56.26 and we get 12.90%. And then finally, for oxygen, you have 16.0 divided by 1 56.26 and that comes out to be 10.24 percent. And finally, for our final, we have cobalt chloride hydrated with six, um, water. So we're going to be looking here at Cobalts quarry in oxygen and hydrogen. So to find our mass, we're gonna have 58.93 close to two times 35.45 Plus, we have six of them. So 12 hydrogen on six oxygen. Hey! And when we find values here, this is 70.9. This is 12.96 and this is 96.0 Um, and our total on a total mass here is 237.92 sticks. So for cobalt we have 58.93 divided by 2 37.926 and that is 24.77%. For quarantine, we have 70.90 divided by 2 37.926 and that comes out to 29.80%. See, for hydrogen, we have 12.96 divided by 2 37th 0.9 26 and that gives us 5.8 percent. And finally, for oxygen, we have 96 divided by 2 37.9 to 6. And that gives us a total of 40.35 percents of the majority of the mass of this compound actually comes from the the oxygen of the water

Heroines. So in discussion there's calculate personally composition by mass of in each of the following. Uh So AIDS. Yes. Three toys. Oh yes and to H. Two that piece C. Two A shape and two. So more norma's 60 point and no percentage of carbon. That is equal to 24 points 02 upon 60.12 1 carbon 12.1 So two carbon 24.2 upon molar mass of this compound in 200 and that is equal to yeah. Mhm. 40%. Okay then the percentage of reduction that is equal to 8.6 Do I dare to buy 60.12 in 200 and that is equal to 13.4%? Then percentage of night duration. That is equal to green being upon 60.12 it to from brain. And that is equal to 46.6% bees C. Three a trade molecular mass 44.11. So percentage of carbon that is equal to three carbon 36.3 upon 44.11 in 200. And that is equal to 81 point sun pacific. Similarly the percentage of hydrogen that is equal to 8.8. About 44.11 in 200 that is equal to 18.3%. Yeah. Then yeah. See product F. E. Mhm and all three tries Iran night grape. Then Malema's 2 41.9 awesome. So percentage of Iran that is equal to 55.80. File upon 2 41.9 in 200 and that is equal to 23 point 1%. Then percentage of nitrogen. Yeah, percentage of nitrogen that is equal to 42.3 You wanted to buy 2 41.9 in 200 and that is equal to 17.4%. The percentage of oxygen that is required to 1 44 upon 2 41.9 into drains. That is equal to 59 point 5%. Yes. Okay.

Alright for this problem we're told that a body assimilates a 12 hour cold tablet at a rate model by D. C by DT equals eight minus lawn of T square T squared minus two T plus four. Where T. Is between zero and 12 and D. C. By D. T. Is measured in milligrams per hour. T. Is the time in hours. We want to use Simpson's rule with N equals eight to estimate the total amount of the drug absorbed into the body during the 12 hours. So one second here I'm just going to get things set up properly here so you can see that I have set up. First of all I state this is Simpson's rule then we set up. Okay A equals zero vehicles 12. The time step is b minus a over N. N. Is equal to eight. First of all, I'll print out what the evaluating points are going to look like. So we'll have b minus a over three and up front so we'll have one half in terms of function at zero plus four times a function at 3/2 and so on. I'm going to let you read that so I don't run out of breath here now. We just need to plug in. Okay, X equals or f of X equals eight minus log X squared minus two X plus four. Then execute that code again. And this is what you should have symbolically from plugging everything into the function. Then the numerical value you get should be 58.9125.


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