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Atwhat speed must the sliding " rod in the fgure betov move t0 produce an emf of 2AVin a 1.1T field, given the rods length 5 32 o?(Note Only enter your numcri...

Question

Atwhat speed must the sliding " rod in the fgure betov move t0 produce an emf of 2AVin a 1.1T field, given the rods length 5 32 o?(Note Only enter your numcric answer, do not Inchude te unlts)Increasingahr-2BApplication of Lenz's lawBnd

Atwhat speed must the sliding " rod in the fgure betov move t0 produce an emf of 2AVin a 1.1T field, given the rods length 5 32 o? (Note Only enter your numcric answer, do not Inchude te unlts) Increasing ahr-2 B Application of Lenz's law Bnd



Answers

At what speed must the sliding rod in Figure 23.11 move to produce an emf of 1.00 V in a 1.50 T field, given the rod’s length is 30.0 cm?

Because we know the moment you, over your math Can we go to be Aldi and my nephew? Be can Because Museo I overthrew by our therefore happy man into off the map is even use your i r over two pi r. So, as you can tell, the magnitude of the IMF is correlated with the one what? While our So if I said that are increased, that means the map should be decreased because early mentee over your map is inversely proportional to the radius r and he's on the answers for this question.

So we have a rod that has a length of 12 centimeters. Being pulled with speed of 15 centimeters per second in this world is immersed in the field as a strength of pointing. Tesla directed out of the page. So as this rod is pulled along the electrons within the body, we're experiencing a net magnetic force. According to Levin's Force law, this will occur and move the electrons with Bob, causing it to polarize somewhat. Let's say, for example, visibility of negative charge on this side and develop a positive charge on this side. This magnetic force will persist until this has become polarized enough that the induced enough on the rod caused by the bullet of charge on end exactly counters air counteracts magnetic force that will occur. Induced coma has value the magnetic field strength times l the length of the rock V, the speed at which the bodies being pulled. So now we're simply filling in values for this to find the induced visible toe. What do you think? That's my point? 14 0.4 No holes. So this is our final answer

In the given problem, there is ah, street conductor carrying a current in upward direction. The current is high. So this current will in news a magnetic field all around it. No and really stands, uh, from the road from this wire, your day a metallic role. The distance between the wire and the roar is ah, in the land of this roar is l And it is going of a the velocity we. So here at this instant, the value off magnetic field at this distance are we'll be giving us new not by four. By do I buy our using by it and several slaw. This is the standard expression for magnetic field. But this much dispense are so we can say at this instant, this road is in the magnetic field be and it is warming the state we the land, Ellie. So there will be any American news there will be and e m f Indy used rather we can say emotional Yemen in news it grows the ends off the roll which is given us be and to be in tow. And here be is new, not by to buy I by off and into V in tow. So finally, the expression for you have confused emotionally refused, maybe given us new. Not you. Really? Into I in tow. L invited by do by, Uh, and actually he have toe Show this. So this is fruit. Thank you.

Hi. In the given problem, a magnetic created is represented with the help of doors Means the magnetically is coming out off the plane off paper perpendicular early. There is a role which is moving in this magnetic field. The worst right. The velocity be length of the road here has been given as l is equal to 13.2 centimeter which can be gluttonous 0.132 meter after dividing it by 100. The only thing used as a result of motion of the conductor Anything used across the end of all the conductor is 1 20 million bowl. What we can say This is 1 20 into appendage to the par minus three hole. And this Magarity food you've given us zero 0.90 s la Now, in the first part of the problem, we have to find the velocity with which the rod is moving towards right. So to find it, we use the expression for emotional you Nothing News which is given asked the product off magnetic clear be you know the velocity And and then so from here the expression for this velocity comes out to be the racial. You know confused man, the product off magnetic field with the lens. So the velocity here comes out to be a silent for this enough. In news, we put 1 20 into 10 dish par minus three for magnetosphere. This is 0.90 Tesla, or length is 0.132 meet up. So then we solved them. We get the answer for velocity, which comes out to be 1.1 meter on a second. This is dancing for the first part of the problem. No. In the second part of the problem, we have to find electric field across the land. Talked this conductor. And as we know, Electric Field is given us the potential Grady End means potential 40 minute rant and potential easy enough in use. So this is 1 20 into 10 Special par minus three, divided by the length of the conductor, which was 0.1 32 wound for a meter. And here it comes out to be zero wine, nine one rule for a meter. This is the answer for the second part of the problem. Thank you.


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