4

6_ When we are finding confidence interval (CI) of the population mean (p), the CIa) shrinks as the sample size goes up. b) shrinks as the confidence level goes up....

Question

6_ When we are finding confidence interval (CI) of the population mean (p), the CIa) shrinks as the sample size goes up. b) shrinks as the confidence level goes up. shrinks as the population standard deviation (o _ goes up. expands as the sample Size goes up_ (e) None of the above

6_ When we are finding confidence interval (CI) of the population mean (p), the CI a) shrinks as the sample size goes up. b) shrinks as the confidence level goes up. shrinks as the population standard deviation (o _ goes up. expands as the sample Size goes up_ (e) None of the above



Answers

When all other quantities remain the same, how does the indicated change affect the width of a confidence interval? (a) Increase in the level of confidence (b) Increase in the sample size (c) Increase in the population standard deviation

So for all kinds parts of the problem, we are going to use the formula, those Z squared, I used this, Yeah, tv standard deviation squared divided by e squared. Yeah, So starting with answer a we have a 95% competence Of a standard deviation of 30 and e value equals to 10. So first we want to get the confidence interval into is a score. So we would take put it a small and subtracted from one. So you would get points There are five and then you would Divide that by two, that equals .025 and then you would look on your table and see what that equals and you'll find about you 1.96. So now we can put it back in our formula would be 1.96 squared I'm already which was the standard deviation and you divide that by e squared which was 10 and you get an answer of 34 557 and a decimal is the best around up. So the minimum for this one would be 35 I'll do the same thing for B and C. So we had a 99% confidence interval, The standard deviation is 30 and e equals 10. So we're gonna start with the confidence interval, 88.01 and when you divide that by two you would get .005. And if you look that up on a busy table value is 2.58. So now we can plug it into our formula, So maybe 2.58 square types 30 squared Divided by 10 squared. And you get 59 ft nine. So your minimum value Would be 60 participants. Then finally, 1st Steve we have again The information 30 and 95% confidence in a real But our E has changed a five. So you look different. So since we're already doing the 95 in the per A we'll just use that number. So one point not six squared times 30 squared. Bye Bye. five square this time. And you get 138.3, and you would Round up to 1 39 minimum participants, right?

It's now What is the formula for my margin of error? He is equal. Do Z Alfa by two multiplied by sigma by route And this is a formula. Now if I increase the confidence level, if I increase the confidence level, it means that my Z Alfa by two valuable increase right? I'm looking at party If my Z Alfa by to value increases and I want this to remain same my end If this value increases, my end will also have to increase. So in this case, my sample size increases my sample size increases right now moving on toe Part P Yeah, What is part B C. If I increase the error tolerance if I increase the error tolerance which means that instead off e now I have something greater, which means I want this overall value this overall value to increase And in order for that to happen my end because it isn't the denominator has to decrease. So my sample size is going to decrease. My sample size is going to decrease. Remember, we're keeping all the other things constant aware. Moving on to park si if I increase the population standard deviation Okay, now What is happening is everything is saying. But now I am changing the population standard deviation, increasing it. If I increase my numerator, I will also have to increase my denominator if I want to keep this quantity same. So again, in this case, my sample size is going to increase. My sample size will increase and these are my answers.

So for this question we will be using the formula for all three parts is c squared standard deviation squared quite a by the evil he squared. So for a we have a standard deviation of four, We have a 95 confidence interval. Mhm And E equals one. So first made after you switch the confidence interval into a Z score, So you would change it to a distance of traffic from one And then take that divided by two. And for this one you get .025, you look that up on what that score would be on AC table Andrew Value is 1.96. So that's what you'll be using the formula. There we go. 1.96 squared times four square divided by one square, which would just be one of course. And when you put this in the calculator, you get 61.5, but you would need to round up Because you can't really have a half a person, so it would be 62, the property well, I do something pretty much just saying, be just different value. So you have the standard deviation up for 90 99% confidence interval, Your E is equal to one. So switch the comments and a rule to a Z score again. Oh right, to and you get points here is your efi and when you look that up on easy table, The value is 2.58, So now we can plug that into the formula To be 2.58 squared Times four square divided by one squared again, This one you hit when I was 6.5, but we would need to round up For this case, so the minimum participants would be 107. And then finally, for C you have a standard deviation for 895% confidence interval, what he is able to 8950.5 and because we already did the confidence interval to disease from apartment, we can just use that number. I was walking Point or 1.96, I was four squared divided by a half squared and you get 235.9. But again, we have to round up, so that would be A minimum of 246 participants. Okay?


Similar Solved Questions

5 answers
What reagents andsolvents would You utilize order comn lete the following synthetic pathway?ChOcho
What reagents andsolvents would You utilize order comn lete the following synthetic pathway? ChO cho...
5 answers
Problem 3_ Let f R = R be such that f(r) = 1+12 1.0 Just with algebra_ show that f (R) = [-1,4]. 2. Just with algebra_ show that fii-1p is bijective onto [~1,1],' 3. By the study of variations of f - reprove that fi[-14] is bijective onto [~1. 1].
Problem 3_ Let f R = R be such that f(r) = 1+12 1.0 Just with algebra_ show that f (R) = [-1,4]. 2. Just with algebra_ show that fii-1p is bijective onto [~1,1],' 3. By the study of variations of f - reprove that fi[-14] is bijective onto [~1. 1]....
5 answers
0l 10 comp etelHW Score: 78.33%6, 15.67 of 20 pts5.4.19Quastian HalpFind Ihe Work done #2xy 1+522,71 in Movino panicle once counlelc ockiiso around Ihe curvo Ee boundiry of Iho "trangular' region in tho frst quddrart onclosed by Ihe ,-axi5 , Ine line * = and tho curvo erThe amount 0f work done (Type simplified Iractlon )
0l 10 comp etel HW Score: 78.33%6, 15.67 of 20 pts 5.4.19 Quastian Halp Find Ihe Work done #2xy 1+522,71 in Movino panicle once counlelc ockiiso around Ihe curvo Ee boundiry of Iho "trangular' region in tho frst quddrart onclosed by Ihe ,-axi5 , Ine line * = and tho curvo er The amount 0f ...
5 answers
7) Name the following structure (8 pts. total)Draw the following compound:4-chloro-3,6-dimethyloctane
7) Name the following structure (8 pts. total) Draw the following compound: 4-chloro-3,6-dimethyloctane...
5 answers
La4 (0) (Lest S6i Tl) ( (es Nue): (-ftest isal 2 ) Ene 7() 9 AT_M n Enj 46 "yalio^ #L 456^ Rlact(o4Tk)
La4 (0) (Lest S6i Tl) ( (es Nue): (-ftest isal 2 ) Ene 7() 9 AT_M n Enj 46 "yalio^ #L 456^ Rlact (o4Tk)...
5 answers
Consider the following reactions and their respective equilibrium constants: AI(OH)3(s) ~Al+3_ "(aq)+30H "(aq) Ksp = 1.8x10-33 A/+3 "(aq+4OH" "(aq)-AI(OH)4 (aq) Kf= 7.7x1033 Calculate the Keq for the reaction:AIOH)3(s) OH (aq) AI(OHJ4 (aq)
Consider the following reactions and their respective equilibrium constants: AI(OH)3(s) ~Al+3_ "(aq)+30H "(aq) Ksp = 1.8x10-33 A/+3 "(aq+4OH" "(aq)-AI(OH)4 (aq) Kf= 7.7x1033 Calculate the Keq for the reaction: AIOH)3(s) OH (aq) AI(OHJ4 (aq)...
3 answers
In the dendrogram below, hierarchical clustering was performed for 30 universities based on variety of metrics in an effort to group the universities:1 4 % % 8 8 1 ili | V Ill 1 V iii jli 1 1 2 6 1(Using distance between clusters of 4,how many universities would be Inthe rightmost cluster?
In the dendrogram below, hierarchical clustering was performed for 30 universities based on variety of metrics in an effort to group the universities: 1 4 % % 8 8 1 ili | V Ill 1 V iii jli 1 1 2 6 1 (Using distance between clusters of 4,how many universities would be Inthe rightmost cluster?...
5 answers
6.2.59 Determine the area under the standard normal curve that lies to the left of (a)z = 0.64, (b) z = 1.64, (c) z = 1.33,and (d) 2 = 0.51QuesThe area t0 the left of z = 0 64 is(Round to four decimal places as needed
6.2.59 Determine the area under the standard normal curve that lies to the left of (a)z = 0.64, (b) z = 1.64, (c) z = 1.33,and (d) 2 = 0.51 Ques The area t0 the left of z = 0 64 is (Round to four decimal places as needed...
4 answers
= Op S! Jeym Itr(I + 2) = *p aJ34M {"p } ajuanbas BuIMolloy a41 Japisuo)
= Op S! Jeym Itr(I + 2) = *p aJ34M {"p } ajuanbas BuIMolloy a41 Japisuo)...
5 answers
48. Which oxides exist as individual molecules? 1. Al,O; 2. SiOz 3.P4O1o (A) 2 only 3 only 1and 3 only (D) 2 and 3 only
48. Which oxides exist as individual molecules? 1. Al,O; 2. SiOz 3.P4O1o (A) 2 only 3 only 1and 3 only (D) 2 and 3 only...
5 answers
Question 3Which of the following salts has the greatest lattice energy?LiClLiBrVF
Question 3 Which of the following salts has the greatest lattice energy? LiCl LiBr VF...
5 answers
(Round 8 Construct the auo decimal 13.4, indicated place 2.0 confidence needed ) 8 = interval for the population 1 ueaw using the t-distribution Assume populalion is normally distributed
(Round 8 Construct the auo decimal 13.4, indicated place 2.0 confidence needed ) 8 = interval for the population 1 ueaw using the t-distribution Assume populalion is normally distributed...
1 answers
Find the horizontal and vertical components of the vector with given length and direction, and write the vector in terms of the vectors i and $\mathbf{j}$. $$|\mathbf{v}|=1, \quad \theta=225^{\circ}$$
Find the horizontal and vertical components of the vector with given length and direction, and write the vector in terms of the vectors i and $\mathbf{j}$. $$|\mathbf{v}|=1, \quad \theta=225^{\circ}$$...
5 answers
2r-6 Given f (x) 1+2r-15Part 0f 5(a) Write the domain of / in interva notationThe domaln cf the function In Interval notatian I55) u (-5,3) U ((Q,D) [,O) (D,0][O,D) {J DUDPant: 1 / 5Patt ? 0/ 5(L) Simpllly tho rutiona expreselon dfining the (unctiom,22empies f() 124=5chae
2r-6 Given f (x) 1+2r-15 Part 0f 5 (a) Write the domain of / in interva notation The domaln cf the function In Interval notatian I5 5) u (-5,3) U ( (Q,D) [,O) (D,0] [O,D) {J DUD Pant: 1 / 5 Patt ? 0/ 5 (L) Simpllly tho rutiona expreselon dfining the (unctiom, 22 empies f() 124=5 chae...
3 answers
Please provide IUPAC name for the following compoundOH BrOH
Please provide IUPAC name for the following compound OH Br OH...

-- 0.022948--