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Lasiycor Via snEennaje0 C5 [CyCnlr of 9750O0 Thsslocoaratc vulozuVenesn2s05692108 Julo53 92109JSDo0 5700...

Question

Lasiycor Via snEennaje0 C5 [CyCnlr of 9750O0 Thsslocoaratc vulozuVenesn2s05692108 Julo53 92109JSDo0 5700

Lasiycor Via snEennaje0 C5 [CyCnlr of 9750O0 Ths slocoaratc vulozu Venesn2s0 5692108 Julo 53 92109 JSDo 0 5700



Answers

$$\frac{56 y^{4} z^{5}}{7 y^{3} z^{3}}-\frac{45 y^{2} z^{2}}{5 y}$$

In the question we have to perform the indicated calculation which is .0732 and 26,710 divided by .00134 in 2.0231. Now moving towards the solution First, we will be multiplying this and this. So we will get 491.172 divided by 0.0000 30954 dividing this, we will get 15 comma 867 comma 803.8379532 So on. So this can be written as 1.59 to 10 to the power seven. Thank you.

Mhm. 56 Y. to the 4th And see to the 5th divided by seven. Why cubed Z cubed minus 45. Why squared Z squared over five Y. So 56 divided by seven. We'll get the numbers first. It's eight. Why do the fourth over Y cube subtract those exponents? You get wider? The first. The 5 -3 is two 45, divided by five is 9. Why squared over? Why did the first gives us Why? And the Z squared? Yeah. We have like terms Y Z squared, So 8 -9 gives us -1 Y Z squared options And I don't have to write that one.

So for this one, believe it or not, all you have to do is take that number and plug it into your calculator because you are allowed your calculator on this test. And so that's just give you 713. It's that so.

Today we will be continuing our discussion of probability distributions with an example of a distribution and determining if it is a probability distribution for not now. Before we determine if this is or is not a probability distribution, we first need to review the definition of probability distribution as well as the two rules that accompany it. No, start with probability. Distribution is a table or an equation that links each outcome of his statistical experiment with its probability of occurrence. And, of course, the two rules that a company that our number one the all probabilities in the probable distribution must be between zero and one. We cannot have negative probabilities, and we cannot have probabilities larger than one. We can't suddenly have a probability of two because that's just not possible. And her second rule is that the sum of all probabilities must equal one. You're determining the probabilities of the entire sample space essentially, So all the probabilities combined must equal one because you can't just have extra probabilities that don't contribute to the overall instances occurring. Now the distribution will be looking at today is her ex sir X over our probabilities of x three day. Oh, our exes are negative. Five negative three. There we go. 30 two and four. Sorry, we don't need those lines there. My mistake. Here we go. And our probabilities are 0.1 to your 0.3 0.2 0.30 point one. Now, first thing we see after writing it out, writing out her distribution, we see that number Rule number one has followed. All of our probabilities are between zero and one. We don't have any negatives. And we don't have anything greater than one. No. For rule number two, which is the sum of all our probabilities must equal zero total. This quit one plus 0.3 so well right down here. 0.4 went to 1.3 point five 0.1 0.5 plus 0.4 is not 0.9. Sorry. Plus 0.1. Our total does indeed equal ones. Based on that rule number two is also followed. So this distribution is probability distribution. All our rules were followed and it is table that links each outcome of whatever this statistical experiment ISS with its probabilities of occurrence


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