5

Activity 1. Simple Activity on Factors Affecting the Rate of Reaction Objective:At the end of this activity, you will be able to determine the factors affecting rea...

Question

Activity 1. Simple Activity on Factors Affecting the Rate of Reaction Objective:At the end of this activity, you will be able to determine the factors affecting reaction ratesMaterials: drinking glasses (same size) Paper and penWater (hot andtap) iodized saltRock saltcamera (if available)Procedure: Pour tap water t0 the same level on two drinking glasses Take a pinch of iodized salt and drop it in one of the glasses_ Do not stir. After one minute _ stir the glass slowly until no iodized salt can

Activity 1. Simple Activity on Factors Affecting the Rate of Reaction Objective:At the end of this activity, you will be able to determine the factors affecting reaction rates Materials: drinking glasses (same size) Paper and pen Water (hot andtap) iodized salt Rock salt camera (if available) Procedure: Pour tap water t0 the same level on two drinking glasses Take a pinch of iodized salt and drop it in one of the glasses_ Do not stir. After one minute _ stir the glass slowly until no iodized salt can be seen_ Record the time it takes for the iodized salt to be dissolved completely _ Repeat procedure no.2 , this time use rock salt. The size of your rock salt should be the same size of a mongo bean: Repeat the entire procedure using hot water. (Extra caution in handling the hot water) DIRECTIONS: Complete the table below by discussing the rate of chemical reaction (speed: slow or fast) under the following conditions: concentration, temperature and size of particles_ Concentration Temperature Size of particles Substance High Low Hot Small lodized salt Rock salt Tap Big



Answers

The use of iodine crystals is a popular way of making small quantities of water safe to drink. Crystals placed in a 1 -ounce bottle of water will dissolve until the solution is saturated. After saturation, half of the solution is poured into a quart container of water, and after about an hour, the water is usually safe to drink. The half-empty 1-ounce bottle is then refilled, to be used again in the same way. Suppose that the concentration of iodine in the 1 -ounce bottle $t$ minutes after the crystals are introduced can be approximated by $C(t)=250\left(1-e^{-t}\right) \quad t \geq 0$ where $C(t)$ is the concentration of iodine in micrograms per milliliter. (A) What is the rate of change of the concentration after 1 minute? After 4 minutes? (B) Graph $C$ for $0 \leq t \leq 5$.

Yeah. Then why? Be equal to f f T. NFL T denotes the amount of iodine and the blood at time. T. So given the idea answers and since the blood a rate of 4%/h, the Andean answers to your the your brain Um at a rate of 10 per hour. So the rate of change of the rate of change of iodine iodine levels of blood per hour will be dy over DT. Which is equal to negative for 100. Yeah. Tom's wide minus 10 over 100 times. Why, jesus? This becomes negative 14 over 100 times. Why? And the the initial condition Y. of zero. Yeah, Becomes f of zero mm. Here the negative son indicates that the iodine levels decreasing as time progresses. Yeah.

All right. So, in this question, it involves the analysis of a tablet of potassium iodide H Right. You want to determine the mess of potassium iodide date in the tablet. So, first the tablet was dissolved in water and acidified and it was converted to this tri iodide iron. Then they try Knight Iron. I was reacted with this amounts of it by yourself. A solution. All right. So, We want to know their mass of potassium iodide eight in the tablet. So France. We need to know the most of potassium my date, but we need to start with the face off it. All right. So, we will start with that. And if you have zero the most of thai software, we must apply the malacca city by the volume of the by yourself eat in liters. 0.02261. Yeah. Yes. All right. So, we will find the most of the try try how you died. I am by using a more issue. Uh So, we have one more of the it's a date I am and to most of the thyself feet. Yeah. All right. So that would be the most of the tri iodide. Now, there's more asia between the tri iodide and the idea is this. Yeah. So, uh we'll have one more Yeah, of the a date and three malls of Mhm. Uh The miners. All right. So, that's give us the most of the uh I did in that tablet. Okay, so that gives us 3.967/10 Temper minus four moles of Yeah. Mhm. Okay, so, we will convert this to mess by using the miller mass of potassium. Are you dates? Which is 21 4.001g of Yeah. For more. Yeah. All right. So That gives us zero 08 Just 61 grabs in Milligram. Will multiply by 1000 to get 80.61 milligram of protests in. Yeah, I did. All right. So this is the mass of potassium a date in the tablets. Yeah. All right. Yeah.

In this question were given some data on the reaction of di ethyl hydrazine and iodine. First, we want to find out what the great expression for this uh reaction is. So we know that the rate should be equal to K times the concentration of dimethyl hydrazine. Okay. Yeah. Some experts at A times the concentration of iodine to some extent, be to solve for A B and K. We can take the data from the experimental, from the experiments to make the systems of equations. So we know From experience at one at 1.08 Times 10 to the negative 4th Should be equal to K. 0.15 To be a time 0.25 to the B. Some experience to we know that 1.56 times 10 to negative west equal K Times 0.15 to the A. Time 0.362 to the B. and from experiment three, we know that 230 Times 10 to the negative fourth should equal okay, Times 0.2 to the A. Time 0.4 to the B. Solving the systems of equations. We get that A. Should be equal to one point oh 05 which is according to one Be should be equal to zero 99 which is a client one. And K. Should be equal to 0.00 two 88 leaders per mole per hour. So now that we know the orders of both diable hydrazine and iodine, we can come up with the overall order. Which should be to which is the son of them and also the overall rate expression which is great equals K. Times the concentration of diagonal hydrazine. Yeah. Mhm. To be a. Which is one time is the concentration of iron to the A. To the B. Which is also. So that's a great expression. Finally, we want to determine what the concentration of dimethyl hydrazine has to be so that the rate of the reaction is five times 10 to the negative fourth moles per liter per hour. When the concentration of iodine is 100.5 Mueller. So using the right expression we just came up with we plug in what we know and solve for a concentration that we won't divide. Yeah. Mhm. Yeah. Mhm. Mhm. We find back to the concentration. Mhm. Of diet to hydrazine necessary should be 0.347 bowler

Let's go over how to determine the rate law for the reaction In this problem, we need to find the experiments in which one of the reacting concentrations remains the same and one of them changes. So if we look at reaction one and three, we can see that hydrogen peroxide concentration remains the same and the iodide concentration changes. So let's take a look at how the iodide concentration changes and how this changes the eight of the reaction. So if we divide the concentrations of iodide, then we see that the concentration goes up by a factor of four. Now we're going to do the same with the rates. So we're going to take The rate from reaction three. The boy by The rate from reaction one. We also get about four. So from this we can see since the concentration and the reaction rate go up by the same factor. This reaction is first order in the aisle diet ion. Now, we're going to look at experiment two and four. So in these two experiments, you can see that the iodide ion concentration say the same, but the hydrogen peroxide concentration is changing. So let's determine how the hydrogen peroxide concentration changes. So if we divide the concentrations, We see that the concentration goes up by a factor of two, and they were going to do the same for the rates. And we see that is also a factor of two. So, because the concentration and the rate is going up by the same factor, it's also a first order in hydrogen peroxide. So this is going to be the expression for the Great Law. Now we are asked to calculate the value of K. To get the value of K. We're going to plug in the numbers from any experiments. So, I'm just going to do experiment one. So now we're going to plug in the numbers Mhm. And now, So for cake. So this is the value that we get for K. Now we're giving some reaction conditions and we add K I. As well as a solution of hydrogen peroxide. In this case, one more of KI contributes one more of the I have died ion. So since we know this, if we calculate the moles of K I, we have also calculated the moles of iodide ion. So what we're going to do is we're going to take the mole aren t of the solution, multiply it by the volume, which we need to convert two leaders first And then we're going to put that over the total volume. And we're told that we have 25 ml at its 25 million. So the total volume is 50 Bill leaders. Then this will give us the polarity of the iodide ion. So now we have to determine the modularity of the hydrogen peroxide. So we're going to use the density and the volume to find the mass. The density is one g over one millimeter And we have 25 ml of the solution. So that means that we have 25 g of the solution. 10% of this is a hydrogen peroxide. So we're going to convert the percentage to a decimal, multiply it by the mass of the solution and that will give us a massive hydrogen peroxide. Now that we have the mass of the hydrogen peroxide, we can convert two moles of hydrogen peroxide using the molar mass. So from a periodic table we get the molar mass. Well the masses 34.01 g. And that loves to convert two moles. And then we're going to put this over the total volume, which is as many leaders. And then we're going to end up with the polarity of ha jin peroxide. Now that we have the more clarity of both of the reactant. We are going to solve for the rate using the rate law. So we calculated the value of K earlier and we can use that. And we're just going to plug in the numbers and recall that this reaction is first order in both the iodide ion and the hydrogen peroxide. So then we're just going to multiply everything together. So we get .36 polarity per minute as the rate.


Similar Solved Questions

5 answers
Shetem Froner Hi 1 8 pabuawons OFP 4 piston 1 rpiscoion experiments; M0jes li large Insulated W determined 5 1 (Seepsa II dutd 3 Lonseam that H 7464303,0 pressure Diston E 8 Jumoxil snoaseb Quom "sponpouduljuvois1 1e tenocratlte ottncor out 0i theSavc For Later
Shetem Froner Hi 1 8 pabuawons OFP 4 piston 1 rpiscoion experiments; M0jes li large Insulated W determined 5 1 (Seepsa II dutd 3 Lonseam that H 7464303,0 pressure Diston E 8 Jumoxil snoaseb Quom "sponpoud uljuvois 1 1 e tenocratlte ottnc or out 0i the Savc For Later...
5 answers
Find parametrization of the circle of radius 10 with center (-8,6,=10) in a plane parallel to the yz-plane:(Use symbolic notation and fractions where needed. Give your answer as comma separated list of x, Y, components. Use cosine for parametrization y variable:)r(t) =<help (fractions)
Find parametrization of the circle of radius 10 with center (-8,6,=10) in a plane parallel to the yz-plane: (Use symbolic notation and fractions where needed. Give your answer as comma separated list of x, Y, components. Use cosine for parametrization y variable:) r(t) =< help (fractions)...
5 answers
10. The point (~ 2}, 131 is on Ihe transformed function: 2log dl - 56 S-9 Find the original polnt on (he parent function /6) tost Justily your answer. [Ta] [Cz]
10. The point (~ 2}, 131 is on Ihe transformed function: 2log dl - 56 S-9 Find the original polnt on (he parent function /6) tost Justily your answer. [Ta] [Cz]...
5 answers
OivOiNonc of thcsc the product.Question " (4 points) 16. For tbc belov. Khil / Inc mtor noducit
Oiv Oi Nonc of thcsc the product. Question " (4 points) 16. For tbc belov. Khil / Inc mtor noducit...
5 answers
The M: and M'+2 peaks are almost equivalent in abundance Mt =166 tbese Draw structures of fragment peaks that fit the structure of this compound: mlz 29, 93, 121, 123 _ and 138. Draw the mechanism for the generation of the m/z 138 peak:I00173 79107151100 110 120 130 140 150 160 170 180 m/ 2 Xno nngsAlabcl 5192 ficant pcaksNEATs0 4i 40 twuHlyeIAEaLMicolet Tosx FT4R
The M: and M'+2 peaks are almost equivalent in abundance Mt =166 tbese Draw structures of fragment peaks that fit the structure of this compound: mlz 29, 93, 121, 123 _ and 138. Draw the mechanism for the generation of the m/z 138 peak: I00 1 73 79 107 151 100 110 120 130 140 150 160 170 180 m...
5 answers
Use $(6-72)$ to finish verifying that the set $(6-71)$ is orthonormal on $[-pi, pi]$.
Use $(6-72)$ to finish verifying that the set $(6-71)$ is orthonormal on $[-pi, pi]$....
4 answers
0B 1 correct Answor and8+ 4 Find #8
0B 1 correct Answor and 8+ 4 Find #8...
5 answers
Find the input impedance $Z_{ ext {in }}(s)$ of each of the circuits in Fig. 15.61.
Find the input impedance $Z_{\text {in }}(s)$ of each of the circuits in Fig. 15.61....
5 answers
Q3) For the combined linkage mechanism shown in figure, a) Calculate the number of the degree(s) of freedom please labelled all links and joints b) Write the constraints (position variables) and closure loop equation(s) C) Find values of all position constraints for given postureUse algebraic-solution methodO.S-60 mm 0,H-35 mm CD-50 mm DE=S0 mm 0-G-45 mmSA-30 mm AB-60 mm DOs-50 mm OsH-15 mmAC-40 mm BC-60 mm EOs-50 mm EF-45 mm06HB
Q3) For the combined linkage mechanism shown in figure, a) Calculate the number of the degree(s) of freedom please labelled all links and joints b) Write the constraints (position variables) and closure loop equation(s) C) Find values of all position constraints for given posture Use algebraic-solut...
4 answers
For each polynomial function, (a) list all possible rational zeros, (b) find all rational zeros, and (c) factor $f(x) .$ See Example 3.$$f(x)=x^{3}-2 x^{2}-13 x-10$$
For each polynomial function, (a) list all possible rational zeros, (b) find all rational zeros, and (c) factor $f(x) .$ See Example 3. $$f(x)=x^{3}-2 x^{2}-13 x-10$$...
5 answers
Suppose there are 95 red balls and 145 yellow balls in a box.Two balls are drawn from the box without replacement. What is theprobability that one ball of each coloring is selected?
Suppose there are 95 red balls and 145 yellow balls in a box. Two balls are drawn from the box without replacement. What is the probability that one ball of each coloring is selected?...
5 answers
The ionic radii for K+, Ca2+, and Sc3+ are 138 pm, 100pm, and 74.5 pm, respectively.The observed decrease in the ionic radii is due totheA. decrease in atomic radius from K to Sc.B. the increase in first ionization energy from K to ScC. the elements being in the same period.D. the increase in effective nuclear charge.
The ionic radii for K+, Ca2+, and Sc3+ are 138 pm, 100 pm, and 74.5 pm, respectively. The observed decrease in the ionic radii is due to the A. decrease in atomic radius from K to Sc. B. the increase in first ionization energy from K to Sc C. the elements being in the same period. D. the increase in...
5 answers
Question (30 points) . Determine the value(s) of h for which the following set of vectors is linearly independent {B [ 0}
Question (30 points) . Determine the value(s) of h for which the following set of vectors is linearly independent {B [ 0}...
5 answers
How many total ATPs one molecule of triglyceride containing15 C each tail will produce.SHOW WORK
how many total ATPs one molecule of triglyceride containing 15 C each tail will produce. SHOW WORK...
5 answers
1) What does Figure 1 represent?Ba Bz B.BoAz Az AAo BaBz B. Bo 4-bit Binary Adder Ci 02 0 QoFigure 11'S complement circuitBinary addition subtraction2'S complement circuitBinary multiplicationBinary SubtractionParity bit generation and checkingpointl
1) What does Figure 1 represent? Ba Bz B. Bo Az Az AAo Ba Bz B. Bo 4-bit Binary Adder Ci 02 0 Qo Figure 1 1'S complement circuit Binary addition subtraction 2'S complement circuit Binary multiplication Binary Subtraction Parity bit generation and checking pointl...
5 answers
Demonstrate how individuals evaluate opportunity costs to make business decisions? Explain what role the production-possibility frontier (PPF) has in the decision-making process.]
Demonstrate how individuals evaluate opportunity costs to make business decisions? Explain what role the production-possibility frontier (PPF) has in the decision-making process.]...
5 answers
Plot the following points. Draw a blank polar coordinate on your paper (a) (-13) (6) (7)23u 2
Plot the following points. Draw a blank polar coordinate on your paper (a) (-13) (6) (7) 2 3u 2...
5 answers
012 pcitus| Ttc rndcm varirules Indyt Figrtn oin: prcaabllin o rihuldnQauS0175WerecucdilmannannEuch Value urId pulnklArr Indcpocerzernlzln04 [email protected] ilitvthst %-0?2 4E0la aq 0 @
012 pcitus| Ttc rndcm varirules Indyt Figrtn oin: prcaabllin o rihuldn QauS 0175 Were cucdilmannann Euch Value ur Id pulnklArr Indcpocerzernlzln 04 [email protected] Probal ilitvthst %-0? 2 4E0la aq 0 @...
5 answers
Of y=x shifted lefit 2 units and down 3 Write an cquation for a function the has the shape units.
of y=x shifted lefit 2 units and down 3 Write an cquation for a function the has the shape units....

-- 0.071590--