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0) M emg Br THF 2 H+DhH2sey hea t...

Question

0) M emg Br THF 2 H+DhH2sey hea t

0) M emg Br THF 2 H+ Dh H2sey hea t



Answers

Addition of diborane in THF followed by treatment with $\mathrm{H}_{2} \mathrm{O}_{2}$ in the presence of $\mathrm{OH}^{\circ}$ to

How would you answer in this question? They asked Additional diversion in th followed by treatment there shortly in presence of H -2. This computer is one Little Cyclops & Pain. Yeah. So they have given different options. So in this option option B is current option B is correct. Yeah, When we to a six. Yeah, this is what do you mean tile psychlos 19? So we know dive boring B two at six in DHF it is a red, Yeah, elongate Bh three Followed by H two or 2 or h minus this takes place. Aspirin and tim are gonna cops rule there. You d marco the cops ruled and Bill gates this product ch three edge and it's ohh yeah, this is one metal psych blow up and down on one with tile side lobe. Thank donald so. Mhm. Mhm. Geometries France, this is Geometries bronze dance when we tiled cyclops. Internal and colonel is fog. Yeah, because addition of water, what does takes place by and be marconi cops rules and be marconi cops ruled. So, senior edition takes place. So Sin at each other. X place explains. Thanks lot

So we have this Ah methyl amine 0.1 Moeller solution and we want to know which of the following pertains to it. And so that solution that substance, rather is a weak base. And that solution will be basic. Ah, and so the hydro ni alli on will not be anything like, uh, 0.1 Moeller. And likewise, since it's not a strong base, neither will the hydroxide pH of less than seven would be an acidic solution. This is a base. And so it's not a strong base. The pH would be less than 13 and two that Syrians

In this problem, I'm writing the reaction here. So just look at it carefully. This compound here it is and or two and here it is. Have In pageants of CS three hole too. CS three 0.2 an edge will give this compound and Cst CST and or to which on further reaction with. And I know two plus SCL As well as H two Or an IG. Go to 5°, integrate. It will finally give this compound as the product. Here it is an H two and here it did. And Cst Cst. So According to the options in this problem, option eight correct answer.

Okay, so we're gonna find the ph and the hydroxide iron concentration of several buffer solutions here. We know that through all these buffers. The hs 03 minus concentration is going to stay at 30.4 to 9 moller. And the easiest way to find the concentrations of H plus and minus for buffers is to use this equation here, H classes K A concentration of the acid over the base. So we'll go ahead for this first example. Okay, We'll plug in our K. A. Which is 6.0 times 10 to the -8. The concentration of our acid is going to be .4-9 the entire time. And for this first one the concentration of our base is .0249. So we'll multiply that out and we'll get 1.03 Times 10 to the -6 Moller H plus. So if we go ahead and take the negative, the log of that ph negative log of 16 times 10 to minus six will give us a ph of 599 And also we can find the o h minus O h minus is simply kw over H plus. So one times 10 to the negative 14, divided by 1.3 times 10 to the negative six Will give us our OH -9. 7 Times 10 to the -9 Moller oh H minus mm. So these next are going to be the same. The only thing that's changing in these examples in this problem is going to be the value of the concentration of the base. So Kay is the same. The Weak acid is still .4- nine moller. And the base in the second example is .247. So multiply that we'll get our 1.4. I'm saying the -7, that's the polarity of the H plus. If we take negative the log of that, we'll get our ph And our Ph will come up to be 6.98. And again, hydroxide ion is just going to be one times 10 to minus 14 divided by age plus. So you'll get 96 times 10. A negative eight more oh H minus. So a couple more again where not much is changing. So once you get to hang on one of these, you've probably got them all 3.429 moller of our acid And in this example are basis .54 moller. So we'll get the concentration of R. H. Plus -8 Solar Age Plus. So again, ph is just minus the log of the H plus concentration. So minus a log of 5.11 time center minus eight Will give us 7-9. And hydroxide is just kw over H Plus. So one time send a negative 14 divided by R. H. Plus Will give us 2.0 Times 10 to the -7 More. And that's our wage negative. Cool. And then For the next one H plus here's our k. Okay so .4-9. Now this is changing 2.811. That's our concentration of our base. Again. This is all going to be very repetitive once you've got the hang of one of them you're probably good to go. So ph is minus the log of the H. Plus. So we get 7.50. Oh h minus one times. Send the negative 14 divided by 3.17 times seven minus eight. Well give us 3.2 Times 10 to the -7 Moller. Oh age minus And one last 1. Yeah. Hey this last concentration is 1.2- three moller. So that will give us the concentration of H. Plus We can use that to find the Ph Monster log of that is going to be 7.68. And in the same way we'll find the hydroxide ion That's going to be 48 Times 7 -7 More.


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