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Calculate the energy required to heat 199.0 mg of mercury from 114 %C to 19.0 %C. Assume the specific heat capacity of mercury under these conditions 0.139 J*g K Ro...

Question

Calculate the energy required to heat 199.0 mg of mercury from 114 %C to 19.0 %C. Assume the specific heat capacity of mercury under these conditions 0.139 J*g K Round your answer to 2 significant digits_DDP0.09

Calculate the energy required to heat 199.0 mg of mercury from 114 %C to 19.0 %C. Assume the specific heat capacity of mercury under these conditions 0.139 J*g K Round your answer to 2 significant digits_ D DP 0.0 9



Answers

It takes 585 $\mathrm{J}$ of energy to raise the temperature of 125.6 $\mathrm{g}$ mercury from $20.0^{\circ} \mathrm{C}$ to $53.5^{\circ} \mathrm{C}$ . Calculate the specific heat capacity and the molar heat capacity of mercury.

In order to calculate this question. First, we have to calculate the heat capacity so the heat capacity is basically just he absorbed in the reaction divided by the increase in temperature that he absorbed in the reaction is 585 draws and the change in temperature, which is 20 degrees to 53.5 53.5 minus 20. That's the change of temperature, which is 33 25 degrees C. And you will get your keep he capacity, which is 70.5 J. Percy, Jules per Celsius. And there we have the heat capacity. So how do we calculate the subservient keep capacity? Um, that depends on how much we're using. So in this case, we're using to 125.6 grams off mercury And in order to calculate specific key capacity, you just use the value of God for this is the he capacity divided by the mass off the substance, Uh, which is 125.6 grams of mercury. We'll eventually get 0.139 drew Hursey grams and there with subsisted key capacity was specific. He capacity. Then I ask you this What is the molar? He capacity? The Mueller he capacity is basically how much he it has for everyone. More of mercury the way we one more mercury is 200.59 grams off, um, Mercury in one mode. So we just use our specific heat capacity time. This values are specific. Heat capacity is 0.139 draws Percy from scram and this is grams. And once we times this by this, we cancel the grams and we'll eventually get and 27.8 Drews Her Grimm's No, not a gram. Sorry, mo, because this is grams per one more, so we eventually get Drew's per See times more 27.8.

Thermodynamics represents the relationship between heat work temperature and energy. And so essentially we're looking at the transfer of energy from one place to another from one form to another. So the equation we need is the expression for the amount of heat absorbed by the substance. To increase the temperature Q. The heat absorbed is equal to end the mass of the substance, multiplied by the specific heat capacity, multiplied by the change in temperature. And so what we have for T. One is equal to 37 degrees C. T. Two is equal to 39.6 degrees C. This is converted from Fahrenheit, so delta T. Is equal to 2.6 degrees C. And so now what we can do is plug these values into our equation where Q. is equal to 20g, multiplied by 9.140 jules per gram, Her degrees C multiplied by 2.6°C. What we're left with is 7.28 jewels, which is the amount of heat absorbed by mercury.

This question asks us to calculate the heat associated with mercury, Where we want to calculate the energy necessary to raise the temperature of one mole of liquid mercury by 36°C.. To do this, we need to know a couple conversion factors. Well, a couple of values. One is the specific heat of mercury. This was provided at .0332 calories per gram degree C. The molar mass of Mercury is also necessary at 200.59 g per mole. So Q. Which is the heat will be equal to the amount of mercury in grams. If we have one mole, we need to multiply it by its molar mass to get grams. We can then multiply the mass by the specific heat by the change in temperature. And all the units will cancel except for the heat units, and we get 240 calories are required In order to warm mercury 36°C to warm one mole of Mercury,

So this question asked us to calculate the amount of heat liberated and killer jewels when some York Mercury cools down. So in order to find the toil, amount of heat were using equation that he is equal to the mass from the specific heat capacity of that substance times a change in temperature. So we already know two of these things. You know that the MASS 300 and 66 grams of mercury and we know that that change in temperature is going to be 12 minus 77 C. Last thing that we need is we need the specific e capacity of mercury and they specific heat capacity of mercury is equal. 2.139 Jules per grams. Integrate. Then all we need to do is multiply these three values together. Many multiply all through these values calculator. You will get that the amount of heat that is liberated in this chemical reaction is equal to two negative 3.31 times 10 to the three jewels. But because it asks for the answer to be in the amount of heat liberated not in the delta H. And it asked for it to be in Killer Jewell's. The final answer is going to be in positive and killer jewels, which is why it is going to be 3.31 Killer Jewels Night is the final answer.


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