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1 givcn that IL 39.504 and 0 L ohazm Ml compoteu 1 H with excess LO_(NOs)z: 3 {140001 7 the compound 1 NizC,04 MLOQE 5 H inflate - 1 cvllnoc Cilculalc ILS cmpincl ...

Question

1 givcn that IL 39.504 and 0 L ohazm Ml compoteu 1 H with excess LO_(NOs)z: 3 {140001 7 the compound 1 NizC,04 MLOQE 5 H inflate - 1 cvllnoc Cilculalc ILS cmpincl requind 1 UO2(C,04) 3H,0 [ 1 1 CllciciuC 1 U0z(C,04) JHzO 1 368 L 1 1 0 E Nou EONENZ MAud te molcculan 0 1 Bofka € 04 A: 31 ofthe

1 givcn that IL 39.504 and 0 L ohazm Ml compoteu 1 H with excess LO_(NOs)z: 3 {140001 7 the compound 1 NizC,04 MLOQE 5 H inflate - 1 cvllnoc Cilculalc ILS cmpincl requind 1 UO2(C,04) 3H,0 [ 1 1 CllciciuC 1 U0z(C,04) JHzO 1 368 L 1 1 0 E Nou EONENZ MAud te molcculan 0 1 Bofka € 04 A: 31 ofthe



Answers

I Icre, the compound (D) and rhe basic salr dctecrcd by ir are, rcspecrively (a) $\mathrm{K}_{2} \mathbf{I} \mathbf{l}_{\mathrm{g}} \mathrm{I}_{1}$ and $\mathrm{N} 1 \mathrm{l}_{1}{ }^{\prime}$ (b) Bacycr's reagcnr and $\mathrm{N} 1 \mathrm{l}_{1}$ ' (c) Tollen's reagcnr and $\mathrm{Nll}_{i}{ }^{+}$ (d) $\mathrm{K}_{2} \mathbf{H}_{g} \mathrm{I}_{1}$ and $\mathrm{N}_{1}^{2}$

In this problem, I can write the reaction eight to A. D. Plus plus Ash to S. Will react to form A G two S plus two H plus and see you too. Plus as to us will react to form See US plus two edge plus here, 0.1 more A t minus requires S two S is equal to 0.5 mol and 0.1 mole See you two plus requires as to S is equal 2.1 more. So ratio is equal to 0.5 is 2.1, which is equal to one is 22 So obstinacy it's correct here.

The fall. Let's have a look at what all is given in the problem. It is given that the volume of the compound is von animals, volume of a lymphatic compound is vulnerable and the molecular formula is given us CNH three N oh um This is the molecular formula and it has been told that it is completely undergoing combustion in excess of photo that is oxygen is an axis and we are supposed to find out the contraction and volume contraction in volume. We are supposed to find out the contraction and volume. So first of all let's raid the combustion reaction. Let's straight it in forms of exercise at C. X. X. Y. Oh there plus express via before plus minus that. By two Or two will form x of co two plus vibrate to orphanage too. In combination the products former carbon dioxide and water. Only Here we can say that X is equal to end vehicles to three and N. Z equals two M. So we can write about reaction in forms of and then and that is C n H three, N O M laws, N plus three and by four miners and by two or +42 will form and of CO two plus three and by two of H two so the volume of which two can be ignored since it is a liquid. So we can say that contraction of volume will be one plus in one plus N plus three in my four minus. and by 2- isn't this is nothing but one plus three and by four minus and by two because plus into a minus and got canceled. Hence the correct option is one plus three in my four minus M by two. But this hence the correct option is option. That would be

In this problem, I can write the reaction. It ft s 04 Into seven H 2. Whoa. This is compound x. When it is heated, then it will change into A few years of 4-plus 7. As to Now to a fearsome four will heat it to give every two or three plus S 02 plus S. Or three, and MPS 04 Who. 04 plus two. N o h will react to give f o h. All too, Does any to as a four and f E two plus when goes in oxidation In alkaline medium, then it will give a 53 plus plus E minus so according to the option option. Beach, correct option B. H. But it dance it.

In this problem, We already know that see you as a four. See you also for Into five. Page 2 has the lowest number had low wished number of UNP aired D locked on UNP aired B electrons and lowest degree and low waist degree off para magnetism. But magnetism, therefore, according to the option option B eat Of seven b. H. Correct and said, Well, this problem.


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