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Part AAn electrochemical cell - based on these two half-reaclionsOxidation: Ni(s) Reduction: VOz (aq, 0.035 M) + 2H+(aq; 1.0 M) + eNi?+ (aq; 1.5 M) + 2e VO2+ "...

Question

Part AAn electrochemical cell - based on these two half-reaclionsOxidation: Ni(s) Reduction: VOz (aq, 0.035 M) + 2H+(aq; 1.0 M) + eNi?+ (aq; 1.5 M) + 2e VO2+ "(aq, 1.5 M) + HzO(l)Calculate the cell potential.Express your answer t0 two decimal places and include the appropriate units.EcellValueUnitsSubmitRequest Answer

Part A An electrochemical cell - based on these two half-reaclions Oxidation: Ni(s) Reduction: VOz (aq, 0.035 M) + 2H+(aq; 1.0 M) + e Ni?+ (aq; 1.5 M) + 2e VO2+ "(aq, 1.5 M) + HzO(l) Calculate the cell potential. Express your answer t0 two decimal places and include the appropriate units. Ecell Value Units Submit Request Answer



Answers

An electrochemical cell is based on these two half-reactions:
$$\mathrm{Ox} : \quad \mathrm{Pb}(s) \longrightarrow \mathrm{Pb}^{2+}(a q, 0.10 \mathrm{M})+2 \mathrm{e}^{-}$$
$$\operatorname{Red} : \operatorname{Mn} \mathrm{O}_{4}^{-}(a q, 1.50 \mathrm{M})+4 \mathrm{H}^{+}(a q, 2.0 \mathrm{M})+3 \mathrm{e}^{-} \longrightarrow$$
$$\mathrm{MnO}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)$$
Calculate the cell potential at $25^{\circ} \mathrm{C}$

Auto reaction in which the silver irons react with then farming silver and and sent to plus on this reaction that 10 oxidizes and toe has sent to Pless releasing two electrons. So e oxidation for the 10 is 0.14 world, while the silver edgy plus can the electrons released by their 10 reduces to silver solid, It's e reduction is equal toe 0.80 world. Combining the two equations. We will get the E off the cell. So is in plus two, a G plus passing electron on both sides. Form is in two plus plus to a D. Here in Not Off, the cell is equal toe some of e oxidation plus reductions so that some of the boat cell is zero point 94 World no to find easily nonstandard self potential is equal toe in our standard self potential. Minus 0.5 nine to divided by N log off Kill is Q. Is the concentration off the ins on the product side? Divide by concentration on the eyes on the reactor inside, so chemo is equal toe on the reactor Inside. This is there is isn't two plus ions while under products sign there is edgy. Plus there are two months. So we will ride the months in power and is the number of electrons last and again? So here two moles up electrons asked our can. So putting the values for the Q and and so we will get their e self is equal toe in ourselves as we know is equal toe zero point 94 world minus 0.592 and stood up and we will write to the log up. Cure is equal toe then two plus concentration divided by a G plus concentration square. As in this reaction, we have given the S and two plus concentration is equal toe zero point 0 to 0 model while the edgy plus concentration is going 0.1 Moeller putting the value we will get s cell is equal toe 0.94 world minus dividing 0.592 by two we will get 0.0 296 longer zero point 20 Moeller divided by 0.1 Moeller Yeah. So e cell is equal to 0.9 forward minus 0.0 296 and taking the log off thes values, we will get the answer that is equal toe 2.3, multiplying these values and subtracting from 0.94 we will get. SL is equal to 0.94 world minus multiply 0.296 with two point three we get it zero point 068 So we find easily which is equal toe zero point 87 world. This is the required potential Are the cells are given concentration off the cell? This is the required answer to this part question.

All right. So those video, we're going to be answering questions. Six from chapter 20 Which us is to calculate the salt potential to determine that each of the following balance redox reactions is spontaneous is written. You stable 20.1 to help you determine the correct half reactions. S So how do we know if a redox reaction is going to occur spontaneously? Ah, spontaneous reaction is Warren. Where are salt? Potential is positive is greater than zero. So we need to take our balanced redox reactions and identify the 2/2 reactions and look up thesis all potential breach of the half reactions and table 20.1 um and then add those together to get the to get these all potential. And what if it's positive that it will occur spontaneously? Um so the reaction were given is mg solid, plus a qui est p B plus two ions forms PB solid plus a Clios mg plus two ions. Eso we have the oxidation number going from zero to plus two for magnesium arms of the oxidation number is increasing, which means we're losing electrons. Loss of electrons is oxidation. So here's our oxidation half reaction um And then we're going from a Clios PV plus to an oxidation number plus two two solid PV with an oxidation number of zero arms or oxidation. Number is decreasing, meaning we're gaining electrons by reduction. So there's a reduction, half reaction so we can write those two out. Um, And here just to balance the charge in each side of the equation, we're going to add two electrons. So our A P B plus two is balanced by two electrons, and RMG plus two is balanced by two electrons and we can look up thesis potential. The reduction potential over each of these half reactions s o for the 1st 1 it's negative 10.1262 bolts. I'm sorry. I forgot to write my units here, but these Aaron volts, um and that's good is written. But for the 2nd 1 for oxidation, the tabulated values are all for the reduction reaction. So we're only going to see the reverse of this reaction in table 20.1 on DSO. The reduction potential for the reverse of this is negative two point 372 bolts, but we're going to write at the rate the way it occurs in that reaction. So we have we flipped the sign of our cell potential in order to match That s o we have positive. 2.372 bolts on. Then we add these together and we get the equation we were given. And we add together the salt potentials and we get positive. 2.2458 volts s o the overall cell potential for this reaction for this Redox reaction is positive. Meaning it's going to occur spontaneously is written.

Okay. To convert from s and solid us and and two electrons, we need negative 0.1375 me. And from C you two plus two about John to you. We need 0.3419 So we see that the energy of our hotel is equal to 0.3 for 19 minus negative. 0.1375 which is equal to no point for 794 Therefore, since it is positive we have a spontaneous Yeah.

So this problem You're with the galvanic celery extenders you're given for this government. Still, ion concentrations of the standards Still part of your astral signed on the cellphone and shell at 25 degrees C for this calorie cell. Soldiers first right down the Garland Cooper toe Cooper to place an equation involves copper in solid state Waking Wait and Plus Ireland. Three plays gender separation for and very Cooper two plus toe every two plus in Akwa State. And if we sum this to values and iron to the valve for this one is minus zero point 34 and now on the value for the cell potentially 25 degrees one applies down seven. Artistic warren, which is and this will give us available plus syrup warrant is equal to 4 to 4. So this is the standard sell foreign shell for it Still Now, we were just planning this value in this reaction equation. Five are in this Formula nine to warn if we do that, the number of difference transfer are Look you 25 years. So here this is not is the standard supper and feel because you can calculate for Hadi from the standard oxidation griffin potential values off this company cell. And then the killer is basically the ratio off the iron concentration point on the product side over that really inside to hold over the number of electrons transferred in between, um from the reactors and borders. And you can see that from here we can easily see that Cooper was converted to copper to plus let Miss Cooper have copper has donated two electrons and the story veteran sir on. Taken up by this, every three plus two off this every three plus took those three electrons to become two, if it to play sand. So that means the number of electrons that were transferred in the process is to. And that's why our value for in is also to Seoul place to a developer rent. And now we have to. I don't the log off the broader concentrations over the reactant concentrations. And here are brutes. Our goal for to place. And if you do plus And since we have to, every two players will have a Squire there for this to and and the bottom we'll have if you three bless. And since we have to every three Plus, we'll put a Squire for this one too. And since corporation solid form, it will not be included in the ratio here. So that's all we I need to plan in the formula. And if we calculate these values, will there 0.43 fold miners? We can't go despite it will be Is it a planned 17 84? And the answer will be, Is there a plan to fight to vote? So this is the sell foreign shell at 25 degrees C for the government itself, keep it.


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