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Answers

Draw the conjugate acid of each of the following: a. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ b. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$ c. d. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}$ e.

For each to its congregate as it is etched Ria's positive conjugal basis and just negative for each to be awful. Negative. Congregate Asset is its Threepio for by base comes Out Toby HBO for two negative PS three Conjugated assets. PH for positive by the basis PH Too negative. It just negative as it is, it's us. Asset is EJ to us by bass turns out to be, It's too negative. Etch Sa three Negative Conjugated our cities. It's to escort revile, congregate bases S O. B to negative. Sane is for F G and a junction.

All rights for this problem. We're talking about congregant acids and congregate basis, and what they are is basically the products of an acid based reaction. So for this reaction, we know that an asset is something that releases a proton and a basis something and accept a proton. So in this case, the water would be the acid, and the first reaction would be face. Now, how do we tell which one which are the products is the contract acid and which is the congregate base? Well, imagine we flip this reaction and the products became the reactions. The reactions became the products Which one of the products would be the acid in which one would be the base? Well, if we flipped it, this first product would become this first reaction and would lose a hydrogen, therefore making it an acid. So we know that this is the code to get acid. We flip this reaction R o agent minus would become the water. It means it would have gained ah, hydrogen so that exit the congregate base. So what these pairs were given, we're when deciding whether it's the common to get acid of the congregate base that We know that the one with the extra proton is gonna be the kind you get acid because it's the one that if it flips, it would donate a hydrogen, as opposed in contrast to our continent days. Okay, so for a the conjugal acid is gonna be the one with an extra proton. So we know that this 1st 1 is the counter Get acid. While the 2nd 1 is the concrete base to be. The 1st 1 has an extra proton, so that's gonna be the continent acid. All the other one is gonna be the conduit base. Proceed. The 1st 1 has an extra hydra, so it's going to the country of acid. Well, this 2nd 1 is gonna be the Kandahar base for D. 1st 1 has an extra hydrogen socks with me, The contract acid. Well, the 2nd 1 is gonna be the contra bass for E. The 2nd 1 has an extra hydrogen, so that's gonna be the continent acid. Well, the 1st 1 is gonna be the conjugal base

Good base of each of the given species. First one is H. Two S. When H. Two S accepts a proton, it becomes a three S. Plus. And when sts loses a proton it becomes Hs minus. So HTS plus is the conjugate a seed of phase two S. And H. S minus is the conjugate base. Now next one is H. Two P. 04 minus. When it accepts support on it becomes a C. P. 04 So a CPO four is this conjugate acid and we need to P. 04 minus, loses a proton. It becomes eight P. 04 to minus. So it's the conjugate better. H. Two P. 04 minus. Next one is p three ph three when except support on it becomes P. H. Four plus. So this is the conjugated cedar ph three. And when ph three loses support on it becomes P H two minus. And this is the conjugate base up ph three. Now next one is eighties minus. When it accepts supporter it becomes H. Two S. And H two S. Is the conjugate acid of hs minus and hs minus. When loses a proton, it becomes S two minus. S two minus is the conjugate base off Hs minus. Next eight S. 03 minus. When except Supporter it becomes H two S. 03 H two S. 03 is the conjugate acid of H. S. 03 minus. And when H. S. 03 minus loses supporter, it becomes S. 03 to minus which is the conjugate base up 83 miners Next FH. three or 2 plus. When it accepts a proton it becomes 84 Or two plus and when it loses supporter it becomes H 202. Now, next one is 8 four and 2. When this one accepts a proton it becomes into age five plus, and when it loses a proton it becomes 10 to age three minus. So N two H five plus is the conjugate sc dot H four N two and N 283 minus is the conjugate Based off age four and last one is a little alcohol. When it accepts a proton, it becomes CS 30 H two plus, which is the conjugate A c dot c S 308 And when c s 308 loses a proton, It becomes CS 30-, which is the conjugate base up, See a 308.

This is the answer to chapter to problem number 35 from the Smith Organic Chemistry textbook. And this problem asks us to draw the congregate acid of each of these Brown said lottery faces. And so remember, by definition of bronze stead, Lowry base is a molecule that can accept proton. And so, essentially, what we're gonna do for each of these six is just add a proton. I mean, it should be pretty parent as to where that protons can add in many of these cases. Actually, in just about all of them, there's really only only one place the proton can add. So, for example, in a h 20 is gonna become each 30 plus, um, for B. And you know what? I'm gonna go ahead and put put lone pairs in because it may be helpful if you're still not entirely certain. I'm about some of this, so I'll put lone pairs in very quickly. Okay, there we go. So that that might help you decide where to. Where to put the hydrogen. Um, so for be, um, it's gonna go on the nitrogen so in each to minus, is gonna become and h three uncharged. And now, with only a single lone pair on the nitrogen, each C 03 minus is going to become, um well, so rather than right H two ceo three. Um, that would be correct. Answer. But just to make it, I guess a little easier to see you could write each 30 three h. Um and so that's actually it's gonna look like a central carbon. Um, so here you go. Here's, uh So here's the starting material, um, with three lone pairs and negative charge on one of these oxygen's, um and so obviously that oxygen with the extra loan pair and the negative charge is going to be the one that gets protein ated. And so there's the product. Okay, um and then for D again, the nitrogen is really the only place that a proton can be added. So this becomes sees three c h two n h two ch three. Um, and of course, by the nature gin now doesn't have a lone pair. And so we'll have this positive charge for bonds so likewise in e I'm the oxygen can be pro donated, but a result of that pro nation is going to be that it now only has a single lone pair, and it also has a positive charge. Um, and then for s f is going to become ch three c 00 h. And so this is acetic acid. So, uh, it's gonna look like this. So here's this starting material acid Tate, I on negative charge on the oxygen. Um, And then again, uh, that's the oxygen That'll be protein ated. And so there's acetic acid. Acetic acid is the contra Get acid of the acetate eye on which is base. Okay, um and so that's how you approach this problem. I just add a proton to everything to make the constant acid of these bases on. That's the answer to chapter to problem number 30.


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