This is the answer to chapter to problem number 35 from the Smith Organic Chemistry textbook. And this problem asks us to draw the congregate acid of each of these Brown said lottery faces. And so remember, by definition of bronze stead, Lowry base is a molecule that can accept proton. And so, essentially, what we're gonna do for each of these six is just add a proton. I mean, it should be pretty parent as to where that protons can add in many of these cases. Actually, in just about all of them, there's really only only one place the proton can add. So, for example, in a h 20 is gonna become each 30 plus, um, for B. And you know what? I'm gonna go ahead and put put lone pairs in because it may be helpful if you're still not entirely certain. I'm about some of this, so I'll put lone pairs in very quickly. Okay, there we go. So that that might help you decide where to. Where to put the hydrogen. Um, so for be, um, it's gonna go on the nitrogen so in each to minus, is gonna become and h three uncharged. And now, with only a single lone pair on the nitrogen, each C 03 minus is going to become, um well, so rather than right H two ceo three. Um, that would be correct. Answer. But just to make it, I guess a little easier to see you could write each 30 three h. Um and so that's actually it's gonna look like a central carbon. Um, so here you go. Here's, uh So here's the starting material, um, with three lone pairs and negative charge on one of these oxygen's, um and so obviously that oxygen with the extra loan pair and the negative charge is going to be the one that gets protein ated. And so there's the product. Okay, um and then for D again, the nitrogen is really the only place that a proton can be added. So this becomes sees three c h two n h two ch three. Um, and of course, by the nature gin now doesn't have a lone pair. And so we'll have this positive charge for bonds so likewise in e I'm the oxygen can be pro donated, but a result of that pro nation is going to be that it now only has a single lone pair, and it also has a positive charge. Um, and then for s f is going to become ch three c 00 h. And so this is acetic acid. So, uh, it's gonna look like this. So here's this starting material acid Tate, I on negative charge on the oxygen. Um, And then again, uh, that's the oxygen That'll be protein ated. And so there's acetic acid. Acetic acid is the contra Get acid of the acetate eye on which is base. Okay, um and so that's how you approach this problem. I just add a proton to everything to make the constant acid of these bases on. That's the answer to chapter to problem number 30.