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Question 7 (1 point) What partial pressure of hydrogen, Hz, is required above an aqueous solulion order t0 ensure Inat (he concenh7 D 00 mmol dm-3? The Henry'...

Question

Question 7 (1 point) What partial pressure of hydrogen, Hz, is required above an aqueous solulion order t0 ensure Inat (he concenh7 D 00 mmol dm-3? The Henry' law conslant for hydrogen is 7.78 X10-J molm JAPe-] of hydrogen in the solulion is129 MPa129 kPa129 Pa12.9 kPaQuestion 8 (1 point)Ioluene, CoHsCH} and 136 2 g o butan-1-0l CAHgOH at 25 "C The An ideal solulion prepared by mixing 15 Calculate the partlal pressure butan-1-ol In the Vanoum pressure of pure butan-I-ol 885 Pa at thi

Question 7 (1 point) What partial pressure of hydrogen, Hz, is required above an aqueous solulion order t0 ensure Inat (he concenh7 D 00 mmol dm-3? The Henry' law conslant for hydrogen is 7.78 X10-J molm JAPe-] of hydrogen in the solulion is 129 MPa 129 kPa 129 Pa 12.9 kPa Question 8 (1 point) Ioluene, CoHsCH} and 136 2 g o butan-1-0l CAHgOH at 25 "C The An ideal solulion prepared by mixing 15 Calculate the partlal pressure butan-1-ol In the Vanoum pressure of pure butan-I-ol 885 Pa at this temperature vapoui above the mixlure speed your calculaticn note Ihai the molar maes toluene 9215 RInal - that of butan" T-ol 92 [5 Rtol -! 811 Pa 90.9 Pa 074.6 Pa 885 Pa



Answers

Small quantities of hydrogen gas can be prepared in the laboratory by the addition of aqueous hydrochloric acid to metallic zinc. $$ \mathrm{Zn}(s)+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g) $$ Typically, the hydrogen gas is bubbled through water for collection and becomes saturated with water vapor. Suppose $240 . \mathrm{mL}$ of hydrogen gas is collected at $30 .^{\circ} \mathrm{C}$ and has a total pressure of 1.032 atm by this process. What is the partial pressure of hydrogen gas in the sample? How many moles of hydrogen gas are present in the sample? How many grams of zinc must have reacted to produce this quantity of hydrogen? (The vapor pressure of water is 32 torr at $\left.30^{\circ} \mathrm{C} .\right)$

And this problem. We've been asked to understand the various conditions we will need in order for hydrogen to absorb into a metal surface. And all of these conditions are summed up in this equation for disassociative absorption. We'll get that data is equivalent to KP race to the 1/2 divided by one plus KP race. The one hat fado stands for the surface coverage. Que is constant and P is our pressure. So the first thing we're going to do is we're gonna say, Well, let's consider that are surface coverages 0.5 because we were told that only half of our surface is being covered or absorbed. So we'll say 0.5 is equivalent to keya Times 10 which is the pressure we were given raised to the 1/2 divided by one plus K times 10. Race to the 1/2. When we do, that will simplify it to get 0.5 in sick, open to 3.16 k divided by one plus 3.16 K And then we'll do a little bit of algebraic manipulation to find that K is equivalent to 0.3164 Well, now we're going to say we'll consider that our service could coverage. Pardon me is 0.75 So 3/4 of our surface is being covered by our die atomic hydrogen. We're going to use our K value because now we don't know pressure. We'll get that 0.75 is equivalent 2.3164 p raised to the 1/2 divided by one plus 10.3164 p raised to the 1/2. And when we saw for this the same way we would do with the equation before we'll get that P is 89.9 Pascal's That's our pressure. We need to reach 0.75 surface coverage. Well, now we're going to say, we'll consider that my pressure is 10. We're going to get that 0.5 is our surface coverage. Remember is equivalent to 10-K divided by one plus 10. Kate will solve for K and get that K is 0.1. Now we'll say that fate A is equivalent to 0.1 p divided by one plus 10.1 p. Now we don't know the pressure will solve for pressure by saying that our surface coverage is now 0.75 and will keep the right side of our equation. We'll solve for pressure, saying that our pressure is 300 Pascal's. So what this problem taught you to do is say, well, let's consider specific surface coverage and Saul for the pressure or K, that we need in order to reach that surface coverage of hydrogen that we need.

So this problem gets us a reaction. Um, and we're collecting high shin gas, but we're doing it through, um, water displacement. So we're gonna have water vapor as well. So it gives us the total volume, the total temperature, the gentle pressure, um, and the partial pressure of water vapour at 30 degrees Celsius, the temperature of the system. And we need to find the partial pressure of hydrogen gas, the moles of hydrogen gas produced and the grams of sink that would produce that many angles of hard hitting us. So first we need to used also a partial pressures and find the partial pressure of hydrogen gas. So partial pressure. Eso pressure total is equal to the portal pressure of H 20 plus the partial pressure of age to so 1.32 And we need to convert 32 tourist a team. So to do that, we would divide by 760 Um, and because that's equal to one HTM and then we would get that value to be 0.0 for 21 HTM, plus the partial pressure. Parchin. If we rearrange that equation, will get the partial pressure of hydrogen gas to be equal to 0.989 HTM. So that's our first answer and will need to use that for finding the moles of hydrogen gas. So to do that will dio the ideal Gasol, which is P b equals NRT and when you to use that we're solving for the moles of art you got. So I need to use the specific values for hygiene, for pressure for volume for temptress So overpressure will use the same exact one we just saw for so n is equal to P B over rt. So is Europe When 989 times the volume which we were told the volume of hydrogen gas is 240 milliliters. So that's equal 2.24 leaders and then divided by R value 0.8 to 1 with these specific units and the temperature of the system is 30 degrees. So the temperature of hydrogen gas 30 degrees. So add 273 to get this value into Kelvin and we get 303 Copan And then if we plug these values into our calculator, we get the moles is equal to 0.954 nos a Haitian gas and then, when you find the grams of sink that would produce that amount of high drink us. So let's look at the equation. We see one sink forms one hydrogen gas, so they have a 1 to 1 molar ratio. So 0.954 moles of hydrogen gas. So for one more of hydrogen gas, there's one more of zinc and so and one more zinc. There is 65 grams of sink, and if we plug this into our calculator will get 0.62 grams of sink, and so these are our three answers.

What might be a little confusing with this question is the 0.4 grand mass of magnesium is irrelevant. Answering the question to find out the amount of hydrogen gas that, with produced, we really need to focus on the conditions after the reaction, namely the volume, the pressure of the temperature associated with the hydrogen gas that was produced. Here's our chemical reaction showing the production of hydrogen gas from magnesium with hydrochloric acid. The total pressure associated with just hydrogen is going to be the total pressure minus the vapor pressure of water. Then, to determine the moles of hydrogen will use the ideal gas law. PV equals NRT rearranged so that n is equal to P V over R T. The pressure that is just hydrogen pressure is the 7 60 millimeters of Mercury, which will convert teams by dividing by 7 60 the volume of the containers, 100 mil leaders or 1000.1 leaders. Our value, then is 0.8 to 1 leader atmospheres per kelvin mole. We choose this one over the other value that is given to us because we're going Teoh use pressure in atmospheres, which we calculated, appear and then our T value needs to be in Kelvin. So we convert 25 degrees Celsius into Kelvin temperature by adding on to 73 and we get 4.1 times 10 the negative three moles of hydrogen. The answer is B.

Reaction ALS Inc. Where they're still so for ISS, I think an image toe so far is the Nyquist form, which makes us the N s A four plus It's doing got home. How to cover the most housing honest or so forth. I think it is 2.50 g in tow, one mole off. Think by 65.39 g Oh zinc, which makes 0.313 small, most off issues of all, most off each two s 04 personal morality them into volume el, which is one I'm off h two so four in 2.15 letters miss 0.150 moles off each to pass 1/4. Both of them reaction wants to one ratio that there's 24 espresso for is the limiting reactant to calculate the partial pressure of h two, which is peace. It was two n r. T by the which is, uh, Vallis. Let's put all the values And is it a point there? 150 small 108 toe have eight m Farmall Okay. Into temperature is 2 98 Calvin divided by 1 to 2 else. Oh, just three point in Brazil. 8 18 According to Henry's Law to Deter Mined the scalability off H two as off H two is K p half to which is 7.8 into 10 to the par minus four. Small her 80 into 3.8 The team, which is a cluster two point 346 into 10 to the bar minus three. Small part later. Ah, now that's calculate the mole off H two dissolved mall off to a smaller city. Morality into volume. The Malaysia is 2.346 into the into the bar minus three. Most for little in the volume is 0.150 later, which was 3.5 inches under the bar minus five. Smalls off to yeah, no to calculate the fraction of gas molecule result. Yeah, yes Medical Dissolved 3.500. Enter the par minus five molds off H two. Divided by 0.150 Monseau. There's two in 200% 0.234% is approximately 0.23 percent. So yeah, it does reasonable to ignore any dissolved it, too, in part B, as it is a very small fraction


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