5

Cyclohexane cornbined with sodiur borohydride = (NaBHa) Brtetl (in Onc T I T Peraaroph (12p41 33 onLuptscntencesMidicate tfa outcore und "plIr Intan Joukonas...

Question

Cyclohexane cornbined with sodiur borohydride = (NaBHa) Brtetl (in Onc T I T Peraaroph (12p41 33 onLuptscntencesMidicate tfa outcore und "plIr Intan Joukonas

Cyclohexane cornbined with sodiur borohydride = (NaBHa) Brtetl (in Onc T I T Peraaroph (12p41 33 onLupt scntences Midicate tfa outcore und "plIr Intan Joukonas



Answers

Draw a chair conformation of cyclohexane with one CH$_3$CH$_2$ group and one CH$_3$ group that fits each description:
a. a 1, 1-disubstituted cyclohexane with an axial CH$_3$CH$_2$ group
b. a cis-1,2-disubstituted cyclohexane with an axial CH$_3$ group
c. a trans-1,3-disubstituted cyclohexane with an equatorial CH$_3$ group
d. a trans-1,4-disubstituted cyclohexane with an equatorial CH$_3$CH$_2$ group

In this problem, I can draw the reaction. Just look at it carefully. This compound is given here it is CS three. Here it is CH three. It is in pageants of dilute at course P M N 04 p. M. And or board will give the compounded this, just look at it carefully. Here it is CS three and in this side it is who X. Here it is. Oh it in this side it is CS three. And this compound in pageants of a t I 04 will change into this compound. Security. There were one. Oh, here it is CS three. Yeah. You teach double bond. Oh, he edited CS three according to the option. Obs indeed correct. I hope you understand the reaction.

This is the answer to Chapter 15. Problem number 13 Fromthe Smith Organic chemistry textbook. Ah, and this problem says show all steps and re agents needed to convert Psychlo. Heck saying into each compound. And so for a were asked to make the two and anti murders of Trans one to die Brohm of Psychlo, heck sane on and for B were asked to make one, too. A poxy cyclo taxi. Okay. Ah, And so immediately above this problem in the textbook Ah, there's the solution to Owen in chapter sample brought home on how to convert from an al came to an AL Keen, and so that's gonna be the first thing that we have to do. Ah, and that is a two step process on. And so the first step of this is going to be a radical perma nation. So we'll use b r two, um, and then some light to do a radical rumination here. Okay. And so we've we've added a brew mean, um, the way that I've had teachers explained this to me is to say that we're putting a handle on an al cane, so something eso alcanzar not reactive, But once we add a broom into them, they become very reactive. And we can do all sorts of other things. So the first step, when we're starting with an Al Kane is always gonna be to add that hey, lied handle that we can grab onto with other re agents and make whatever we need from there. Ah, and so we have this, bro. Mean, we can eliminate it with some potassium turkey tac side, uh, strong base on. So that is gonna get us to the Al Keen. Ah. And so we now have our al Keen, Um, And in order to get the trans one too, bro, most likely or die, bro mo cycle. Heck, saying all that we need to do is treat this out keen that we made with roaming gas. And we will get Trans died rumination. So that is going to look like this. And of course, we will get both on anti Merce. All right, so that's a s. So then for B were asked to make um up oxide. And that is easy enough to dio starting with the final intermediate. Um, from a So the al Keen that we made s a rather than redraw all those steps. And that is a terrible looking out, keen, terrible working cycle axing. Um So rather than redraw all those steps, I'm just gonna start at that that Final Intermediate. Obviously, it would be made the same way that we made it in part of this problem. Let's try this again. Okay, there we go. So here is our Psychlo Heck scene. Um and we can just treat this with M c p b A. It's going to do an approximation. So there we go. Um, in our final product will be the A pox ID. All right, now. And so that's how to solve this problem. Um, again, Uh, the 1st 2 steps that we did our directly from the textbook from right above this problem in the textbook. And then we just need to recall how to do a transformation from the AL keen chapter. Um, and how to make it up oxide with M c p b a. Ah, and that's the answer to Chapter 15. Problem number 13

Sure. The mechanism off oxidation off Z two butin with di metal, the accident and, uh, structure of the transitional state. So oxygen is transferred from carbon oxygen, part toe carbon couple park. This two turtles go for the formacion off. New oxygen carbon broke. And the Americans from the double bar by elections, they pushed toe the same oxygen, inform another burn. So those bonds are partially formed in the transition state, and this bomb is partially broken. Your veterans on this, but there are pushed to the next bug. So this ball is recon in, and this one is strengthening. That's the Foreman carbon oxygen double barn, which is strong. It does the reaction. And finally, this barn breaks in this bar form and oxygen would be connected to two carbons with new balls.

Six and put We have a cyclical molecule and we're going to be drawing the structure where we have assist trans ice amount. Where are Isopropyl group is trans to our alcohol group on Army Thall Group Assist you are alcohol group. So fastly Let's go ahead and draw on our alcohol group and then we can consider the other substitue INTs. So we've got alcohol group wrong and so now, in reference to our alcohol So we have isopropyl group dies trans so by transit means that it points in the opposite direction as a dashed bond. And now we have our missile assists to our O H group. So I'm Ethel is also wedged and is the same confirmation as our alcohol group and that completes the structure for our sister and ice Emma, with the correct confirmations drawn on all of our substitutions present and the cyclical molecule


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