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4 FA-Calculate pOH if 2OmL of 0.15M NaOH is added to ZmL of 0.3M HF (Ka is 6.6X10" ):Select one: 1.99b. 1.4812.01d. 12.52Question 2Not yet = answeredMarked out...

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4 FA-Calculate pOH if 2OmL of 0.15M NaOH is added to ZmL of 0.3M HF (Ka is 6.6X10" ):Select one: 1.99b. 1.4812.01d. 12.52Question 2Not yet = answeredMarked out of 1.50Flag questionCalculate pH when 1OmL of O.1M HCI is added to 10 mL of 0 My: CHBCOONa (Kbz1.6X10 Select one: 5.5 b. 11.8 c.2.8 d.4.3Question 3 Not yet answered Marked out of .50Flad question

4 FA- Calculate pOH if 2OmL of 0.15M NaOH is added to ZmL of 0.3M HF (Ka is 6.6X10" ): Select one: 1.99 b. 1.48 12.01 d. 12.52 Question 2 Not yet = answered Marked out of 1.50 Flag question Calculate pH when 1OmL of O.1M HCI is added to 10 mL of 0 My: CHBCOONa (Kbz1.6X10 Select one: 5.5 b. 11.8 c.2.8 d.4.3 Question 3 Not yet answered Marked out of .50 Flad question



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Calculate the $\mathrm{pH}$ and $\mathrm{pOH}$ of the following solutions: a. $0.0450 M$ NaOH b. $0.160 M \mathrm{Ca}(\mathrm{OH})_{2}$ c. a 1: 1 mixture of $0.0125 M \mathrm{HCl}$ and $0.0125 M \mathrm{Ca}(\mathrm{OH})_{2}$ d. a 2: 3 mixture of $0.0125 M \mathrm{HNO}_{3}$ and $0.0125 \mathrm{MKOH}$

For this problem were given a few solutions, and we want to determine D. PH and PCO each of those solutions for a we've got sodium hydroxide, the we have calcium hydroxide. See, we have a mixture of acid and base and D We have the same thing, a mixture of acid and base. So we're going to do Ph MPO age of all these solutions. So in this we need a few things that we need to remember. So we know that doing the anti dog of our O H minus concentration or are H 30 plus concentration will give us T o H or pH, respectively. So negative log of O H minus gives us village negative log of H Torrio plus gives us pH. And we also know that if we have 14 minus ph, we get the O. H. And vice versa. We do 14 minus p o h. We get he age. So these will be useful things to remember for this problem. If you want to pause this and write these down, or however you want to do, just remember these for this problem, it will go a long way in helping us figure things out. So for our first solution, we have any wage and, you know, this is a strong base. So we have 100% ionization, meaning that our concentration were given applies to borrow H minus. So, in a H associates in the O. H, we have 00.450 moles of O. H and sodium. But we're gonna focus on O h. So we will do the negative log of R O H concentration 00.0 for five zero and that will give us a p o. H. Since this was in O. H minus concentration of 1.35 This is a very basic solution, as it should be using a strong face. So this is our p O H. Now, if we use the other Formula 14 minus p o h, we end up with our ph of 12.65 So these are our answers for our first example in a 1.35 for R. P O. H. And 12.65 Ferrar pH. And these make sense P. O. H is low, meaning it's basic, and our 12.650 high pH also meets that it is basic. So these numbers make sense and they add up to be 14. So we say that these are direct. These are answers to our first example going to our second example again, we have a strong base, but the biggest distinctions and making this problem is that we have to equivalents of our base. Actually, that, too, is not supposed to be inside of the bracket that's supposed to be outside of the bracket. So again, same concept we have 20 H minus is for every mole of this that we have. So we actually have another step in this one. We have to do 10.160 and we have to multiply that by two because of that to equivalents of base. And that will give us 20.3 20 moles per leader of O H minus. So our actual concentration of O. H minus is twice as high as for our overall substance. For that to acquittal. So now that we have r o H minus concentration, weaken, do the anti log of that number, and that will give us a P O. H of 1.49 and again. This makes sense because this is a strong base. So this is our P O H. Low p o. H. Means very basic. And if we want to get our pH, we can again do the same thing 1.49 out of 14 and that will give us a 12.51 pH, which also makes sense. High pH means basic low pH would mean acidic low p o. H means basic high P o. H would mean acidic, so they're opposites said these are two answers for this 11.49 p o. H. 12.51 ph. Now for see, we have a little bit different. We have a mixture. We have a mixture of equal parts a 1 to 1 mix of hydrochloric acid and calcium hydroxide, and they have the same concentration. But as we can see for this problem, we have one equivalent of our hydrogen. And again, I wrote this wrong we have to equivalents of our hydroxide. So let me actually write that in blue toe, demonstrate that so we have one equivalent of hydrogen and two equivalents of hydroxide, meaning we have twice as much based, since their concentrations are the same. So we'll do will take 0.125 and will multiply that by two and order to give us our actual concentration. Now, that is going to be Since I don't have it written down a two point or point zero to five, I think Let me double check this room. That is correct. Don't know. That is correct. We have 0.0 to 5 most of our demise twice as much of this as we dio off our ass. It. So in order to figure out what our agent, P o. H. All we need to subtract out smaller from the larger. And that's because we're going to form water with 0.125 moles of our hydrogen and 0.125 moles of our hydroxide. So our first step in this is actually going to be like a second stuff is going to be 0.25 minus point is euro 1 to 5. And that's because this is going to be our acid So r h 30 plus and this is going to be r o H minus. And remember that is because we are using up all of this acid with the base. So we're actually still going to be left with a basic solution. And we're going to be left with a concentration of 0.0 1 to 5 for our hydroxide. So if you need to pause it and make that make sense, our base. Since we have more of it, subtract out our acid that will form water and we are left over with this much hydroxide. So now, for our guests are third step is going to be the negative log of 0.125 and the is going to give us a p o H of 1.9 sirrah. So we have our p O. H. Now 14 minus 1.90 is going to give us a pH of 12.1. And this again makes sense low. P o h means basic. Hi. PH means basic, and adding these together would give us 14. So this will be our answer for this problem. 12.1. I kind of wrote over that 12.1 and 1.9. So a little bit of extra that we had to do here, but we still end up with something that makes sense. Hi. Ph Low P O H. Mawr Based. Left over. Now for this one for D We have a different ratio, but still the same concentrations of a strong acid in a strong base. So emphasizing that again if we have a 2 to 3 mix, we have a one subscript for our H plus and we have a one subscript for O. H minus this time. So we have one of each. But this time we have two equivalents of R h N 03 So two times 20.125 gives us 0.0 to 5 of our H plus and for R K O h. We have 00.125 times three because we have a three. So we multiply our 1st 1 by two because we had to equivalents of that and r k o h. We multiply that by three because we have eighth. We have three equivalents of it. So that is going to give us 0.375 for our O. H minus concentration. So we have our concentrations. Now we need to figure out which one? We're gonna have more off. So right away we can see that again. We're gonna take our larger number and subtract or smaller number out of it. Since these were both strong. So 0.375 minus went 0 to 5 is going to leave us with 0.125 Now, remember here we're going tohave o h minus. And here we have hte 30 plus. So if we have more base, we're going to be left with this as r o h minus concentration. Not our asset, because, see, all of our acid was consumed. We have less acid than we have base. They're both strong. We're left with just base. So now we can do our formula again. The negative log of our base concentration is going to give us a p o h of 1.9. And if we subtract that out of 14 we are left with again 12.1 for our ph. And you can see that this is actually the same as our last example. We just have different amounts of different components. But in the end, we're left with the same amount of base to work with. So we have for our answers 1.9 for our p o age and 12.1 for our pH. So going back through each of these, Paul's at any point that you need to We've got this for our answer. For a for answer for B Our answer for C and our answer for D.

In this question we have to calculate P eight and P 08 of the different solutions at 25. This intricate for which the solutions are nice completely. The first one is 0.000259 Moller More perfect. Our partner like acid And part of Florida's is strong as it and ISIS completely. And so the concentration of hydrogen are will be equal to the concentration of that acid. So hydrogen ion concentration will be 0.000259 moller. Now beach is negative law concentration of hydrogen ion which is 0.259 So this value will be 3.6. Now P eight plus P 08 is equal to 14. So P O H will be 14 minus ph 3.6 Which will be equal to 10 four. So the beach is 3.6 and po 80 is 10.4. Okay, the next solution 0.21 moller Suria hydroxide, strong with sodium hydroxide. So the concentration of O. H minus ions will be called the concentration of the best which is point to one. And so be or age Negative law concentration of or China which is 0.21. This family will be 0.68. Now p. eight plus p. 0. 8 is 14. So here we already happy way. So it will be 14 minus P. O. H. Which is 0.68 So the P. T. V. 13 point cartoon point 32 For the next solution It is 0.004 zeros then 7 1 Mueller barium hydroxide here concentration of which minas Ia will be twice the concentration of that base. The strong based purely on my drug side. Why we're multiplying by two because each formula you need will produce 20 H minus I am. That's why the concentration of O. H minus ions will be too Times 0.0000 71 aim so it will be 0.000142 Moller. Then puree julie B negative law which are concentration This venue Liga 3.85. Now ph plus pio ages 14 So ph will be 40 minus spirits which is 3.85 It's a big 10.15. The last solution is two point five Mueller strong based QH. Okay here concentration of which minus I will be equal to concentration of key weight which is 21 fight. And so people do. It Will be negative log. I always minus concentration. That is 2.5 become negative 0.4. So P. A. Too big 14 minus B. OID means minus zero. Wonderful. So be it will be 14

Hello, everyone. My name is Mohammed Ali in this question, the first are the concentration off. The upside is equal the concentration off a strong base dyin spies and number off all edge in the strong base. So here we have one each so the concentration will be equal to the concentration off the strong days. Now we can calculate the B O. H, which is equal negative logs of concentration. So it will be all buoyant. Ono in three and the B H is equal 40 negative to the value off peor it so it will be certain. Boy 907 Here's a concentration off hydroxide is equal the concentration off the strong days times by the number of eyedrops side in a in a strong breeze which is too so it will be over going for four muehler. Now we can calculate the value off people edge, which is a negative logs of concentrations. So it will be all Boeing 356 Now we can calculate the value of B H, which is 14 negative to the value off jahrige. So it will be 13.644 That's number B number C. It will be the concentration off my group side is equal the concentration off a strong base and the space is containing only one way. So the concentration of our side will be equal to the concentration of a strong raise. So now we can calculate the value off P O. H, which is equal negative, long the value off the concentration or itchy negatives. So it will be 1.7 Last thing. The calculation on the B age the D H. Is equal 14 Negative too. The value of pure. So it will be 12 boring minds three. Thank you.

We're to calculate the pH and PCO each of the following solutions for a stomach acid. Each CEO polarity is equal to 2.155 Moeller. Since this is a strong asset, H 30 plus is equal to the Maradi of the HCL, which is also 300.155 Mueller. We can calculate the pH negative log of H 30 plus, which is equal to negative log 155 which is equal to you. 0.8 10 p. O. H. Sick with a 14 minus 140.810 which is equal to 13.190 for be. We have e angularity of a Channel three, which is equal to 0.500 Mueller strong acids, So each through a plus is 1 to 1 more ratio. 100500 Moeller pH It's negative. Log 00500 to yield 2.301 p o. H. 14 minus. That's to yield 11.69 night for C. We have a 2 to 1 mixture. It's seal uh is equal to point 1.125 Moeller and the any, which is equal to also 0.125 Mueller We every 2 to 1 ratio there from my each three or plus concentration here would be 30.0 to +50 Moeller, which minus here would be 0.125 Mueller The beach three or plus is an excess, so the age three or plus in excess will be 0.0 to 50 Moeller minus 0.125 Mueller Theo 0.125 Moeller of the East three or plus, therefore the pH is negative log 0.125 to yield 1.903 in my P o. H 14 minus 1.903 which yields 12.97 party. We have a 3 to 1 mixture, so you got polarity of age to us. So for it 0.125 Mueller ability of any which also a 0.125 Moeller. We were 3 to 1 ratio. The effective concentration of each three. Plus it would be 0.375 Mueller ineffective concentration of which minus is 0.125 Mueller, the clarity of the age 30 plus president in excess. After neutralization and mixing 0.375 Mueller minus 0.125 Mueller will be called the 0.0 to 50 Moeller. From here we can calculate the pH, which is negative. Log 0.0 to 50 This will be the 1.6 year two and are, um good. Check that. Sorry. I'm gonna go backwards. Uh, this will be each to this value here is incorrect. This value here, we're going to remove this value here needs to actually be doubled because each to a So far as to moles of hydrogen, this would make this 0.750 Moeller minus points or 1 to 5.0. This number is gonna change. Droop with 0625 Moeller 0.6 to 5, which will change this number here. Negative log 0.0 65. 1.204 Sounds better than R P, which before thine minus 1.204 for a peerage of 12 point 796


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