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Mndasubsainition "saX ismade, thcn Ihc iniceral .e() 4Jt() f" du091#(D} a(H Noneonke...

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Mndasubsainition "saX ismade, thcn Ihc iniceral .e() 4Jt() f" du091#(D} a(H Noneonke

Mndasubsainition "saX ismade, thcn Ihc iniceral .e () 4Jt () f" du 091# (D} a (H Noneonke



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(a) $\mathrm{F}_{1}(\mathrm{a}) \mathrm{F}_{1}^{\prime}(\mathrm{a})+\mathrm{G}_{1}(\mathrm{a}) \mathrm{G}_{1}^{\prime}(\mathrm{a})$ (b) $\mathrm{H}_{1}(\mathrm{a}) \mathrm{H}_{2}(\mathrm{a}) \mathrm{H}_{3}(\mathrm{a})$ (c) $F_{r}(a) G_{r}(a) H_{r}(a)$ (d) 0

The order of the strength of hydrogen born order strength of hydrogen bond is and it and listen to it. Mm. Just listen efforts have Its strength is 13 kg julie Parmalee. It is 18 and it is 40 km from all closing mood. So as the difference in the electronic negativity increases, the hydrogen born will also increase. So we can write AS L. To IAN that is electronic activity difference increases. Then strength of it wasn't born will also increase. So we see that option. Option A option A is correct. Option is correct.

Hi, this is Claire. So Hi, this is Claire. So in number two of Stuart's my calculus book, So we have eight parts. This problem the 1st 1 It's on the dir votive of zero. So the two points are 00 As you can see here on 14 it could be estimated, and the derivative gives us So Ciro's 14 so derivative the rise of a run gives us four for be. The horizontal tangent can be drawn at, um, excess as X equals one. So the derivative acero for seeing your ex eagles to the graph goes down half half a unit for every 1/3 of a unit to the right. So the derivative is negative, 1/2 over one that gives us negative three House Ferdie near X equals three. The graph goes down, the graph goes down a unit and it goes one to the right. So the derivative gives this negative one Near X equals four. It's similar. So it goes down one unit and to the right. So it's also negative. One for X equals five. The graph goes down 1/10 of a unit right here, and then it goes um, 2/2 unit to the right. So rise over run gives us negative 1/5 and Fergie. It's similar to be so at ethical. Six. Ah, horizontal tension can be drawn, so it's gonna be through. And for a tsh at X equal seven, their approximate points are seven and negative. 1.8 then ate the negative 1.5. So the derivative is Syria 0.3. And when you plot all of these at 00 it's gonna be for going to do this and read so four and then at 10 at two. It's negative. Um, three house, the negative one. No good of one negative. 1/5. It's gonna be around here. Zero, then 0.3. So the grass gonna look something like this? What?

So looking at this graph, we want to determine the different values. Um, given thesis slope of the graph forgiven F But we want to find f at that private certain values. So at zero, we see that this is a pretty positive slope. Um, we see that by the time it covers x distance, it's gone about 1 to 2.5. So we're going to say that this slope is 2.5 at this 10.0. Then a time of one is going to be zero, because at this point, it's leveling off and then changing direction. Then f prime of to is going to be a negative slope, and we see that it would probably be negative. One half are very negative 1.5 based on the exchange in exchange, in wine after crime of three is going to be, um, 123 At this point, it appears that we have a slope of negative one. So starting to stabilize a bit as we see not only in the derivative function but in the graph to f of four, is going to give us about a slope of maybe negative 0.75 So once again, the negativity slope of our graphics slowing down then f of five we can expect to be even, um, higher, technically, some for dealing with negatives. So at five, we have very close to zero. Um, in fact, this would probably be about, um, negative point to maybe negative 0.0.25 perhaps even like closer to zero at six. It's pretty obvious that the slope is zero because we're changing direction. And then at seven, we start to get positive slope again. And based on the graph, it appears to be a very minor, so probably something like 0.25 again.

Is given to us in problem one here. And then we're going to estimate the value of the derivative at each point. So for part A, we're looking at we're X equals negative three. So we go to where X is equal to negative three on the graph, and then we take a look at our graft function. Now, we're sort of estimating the value of the derivatives. What is the slope look like here? Well, it's definitely negative, and it's not super negative, right? It's just a little bit. So we could maybe estimate that the derivative at negative three is equal to say negative 30.1. Okay, then. Part B wants us to look at negative where it's at his eagle. Native twos. We go to native to on the graph and take a look at it slope. Well, looks like the slope zero there to me. Um, well, estimate just from looking at the graph at the's slope at the dirt, that negative too, would be equal to zero. Okay, so then do the same thing for the point. Negative one. So you got a negative one and see what that looks like. And this time we have a positive slope and it looks to be, um maybe it is equal to one, so it's equally increasing as it is heading to the right. Uh, we're gonna take a look out where the derivative is equal to comes physical. Zero. In here, it looks it's even more positive than before. Eso will say half says equal to two. They were gonna take a look where our function is equal to one. So it's still positive. It's maybe a little less positive it was before. It's looking to be about the same slope, that negative one. So So that's equal to one. And in fact, in the whole ah, right size for seems to be a little bit of a mirror version said it to here. Looks like we have no slope again. And then at a positive three, we have just a very slight decrease. So I would guess that two it's gonna be equal to zero. And then for positive three, it will be equal to our negative three. Uh, which we'll just say is equal. Appoint one. Okay, so definitely not exact. But then when we draw a graph, uh, e derivative, you're always try use this chart. Even this guy. A little bit of race marks on it we're gonna see is at negative three. It is going to be just a little bit negative at two. It'll be that negative too. It'll be equal to zero at negative one. It will be equal to one at zero of equal to two. And then it's gonna mirror mirror the other side there in sewer graph of the derivative is gonna just look like a little humpback here.


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