Question
3. Design counter that counts from 0 to 3. The user should be able to have this counter count forward, backwards, and to be paused. The counter should also have indicators showing what state the counter is in; forward, backwards and paused_ It is required that yoU use minimum of one JK flip flop. Lastly, the counter should have parallel load s0 that the device_ when started, starts at either 1 or 0 or randomly at 1 or 0.a. Provide your state diagram_ Provide your state tableProvide your K-mapsPr
3. Design counter that counts from 0 to 3. The user should be able to have this counter count forward, backwards, and to be paused. The counter should also have indicators showing what state the counter is in; forward, backwards and paused_ It is required that yoU use minimum of one JK flip flop. Lastly, the counter should have parallel load s0 that the device_ when started, starts at either 1 or 0 or randomly at 1 or 0. a. Provide your state diagram_ Provide your state table Provide your K-maps Provide your characteristic equations (i.e Boolean expressions). Provide your logic diagram. Use logic gates and blocks to represent your flip flops Don't forget to indicate if it' $ counting up or if it is paused or if it is counting backwards (Hint: LED(s)):
Answers
Write the truth table for the circuits given in Fig. $14.48$ consisting of NOR gates only. Identify the logic operations (OR, AND, NOT) performed by the two circuits.
Here. We have two nuggets and we have to identify the logic operation. So in the first target for a zero and B. Zero we get Are of A&B. zero. So there nor will be one. So I'll put the first target is one, So both input of second target will be one and one and 1 has are equal to one. So their output will be zero because it's north. No for Second, combination of input has a zero and b. one Or of A&B will be one. And so there nor will be zero. So both input will be zero for second target and zero and zero has are equal to zero. So the nor will be one. So why will be one Similarly for the combination of equal to one and be equal to zero there? Or will be 1? So nor will be zero again. It is same as the previous month. So the output will be one for third output. Sorry, thought input combination A&B. Both one. So their output will be, sorry? There are will be one so that not of one and 1 is zero, which means it is the same as the previous one. We're both and put to the second target zero and there are zero. So the north, which is the output, y is one. So we can see that in the table whenever the One of the inputs is one. The output is one. This means that this is a truth table with of an or gate. So this logic operation represents our get. This is a required solution. Thank you.
We want to construct a truth table for the logical operator. NAM, which is written in this farm man, is true when he is true and q's fault or a cure, True and peaceful are if both p and cure fall. Otherwise it's fault. So we have. Peace and cure are variable in P Man Q. So let's write all the possible true value. Combinations of pain kill well here he incur both true subpoena and Q is full because only one of them can be true. Here he is called The True Killer Told was true and they're both being careful. Therefore this is true and that is the truth taken.