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The heat = Yaporzation All curbon dinullide CS2) ' Is 26,74 LJluiol, Calculate the enonda entropy AjS" when 5I: E ot carpon disuillde condeser at 7855 *_B...

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The heat = Yaporzation All curbon dinullide CS2) ' Is 26,74 LJluiol, Calculate the enonda entropy AjS" when 5I: E ot carpon disuillde condeser at 7855 *_Basne Your wnswer containsunlt :4Iibol . Round var anster(0significant d gits:

The heat = Yaporzation All curbon dinullide CS2) ' Is 26,74 LJluiol, Calculate the enonda entropy AjS" when 5I: E ot carpon disuillde condeser at 7855 *_ Basne Your wnswer contains unlt :4Iibol . Round var anster(0 significant d gits:



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Nitrogen is compressed by an adiabatic compressor from $100 \mathrm{kPa}$ and $25^{\circ} \mathrm{C}$ to $600 \mathrm{kPa}$ and $290^{\circ} \mathrm{C}$. Calculate the entropy generation for this process, in $\mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}$.

In this problem. We have a heat engine which receives energy from our rock bed, which was described in the problem in chapter seven. Um, and we want to find the total work the heat engine can give out as it receives energy from that rock bread. So we have our better of rocks here that are hot or warm. And we have our transferring heat into our heat engine, which is, um, doing work out and is also expelling some heat. We have a Let's see, here we have. Let's see, we have. Okay, we got to temperatures. Okay of the rocks, the rocks started out at at 400. Calvin? Yeah. Cool. Down to 290. Calvin. We're going to assume that again because they asked for the most work. Um, that can be received. Find the total work that can be can give out. We're going to assume that there is no entropy generation so that it's reversible process. So we have. If we look at this control volume here with including the rocks and the heat engine, we have the change in internal energy in the rocks. Must be the hey transferred out at the low temperature to the environment and minus the work That's, um, done by the heat engine. And then we have our entropy equation for this. Andi have the change of entropy in the rocks, and then the entropy generated from this heat transfer across, um, a at a temperature and ambient temperature. Okay. And we can again weekend because these are rock solid. We can look up, we confined their mass, we can look up their heat capacity, and then we can get the, uh, and used the log of the temperature ratio to find this term here. Now we can. The mass of the rocks is 550 kg on. We can look up. The heat capacity is 0.89 killer jewels per kilogram. Calvin, which tells us that the heat, the change of entropy in the rocks this term here, um, using our temperatures here must be is minus 1574.1. Killer tools for Calvin. Now we could figure out. Let's see here the heat transfer, um, at the low temperature. Now, we can use from, um to the heat transfer at the low side. We can find from this equation Since we know t not is the ambient temperature. And we know this term now and again again, assuming no entropy generated. Um, so the heat transfer out of the heat engine is for 456,000 kg spoke. Now we have a c here we can we have. We have this term now. Okay, We can we can Let's look at the let's see here we can look at the control volume of the of the heat engine itself, and so we know. Well, we know that that the this look at the control volume here, I suppose. And we know that the heat transferred into here is the change in internal energy in the rocks. And and we can figure that out, using again using the heat capacity of the rocks and their mass and then there to temperatures. Eso that is or minus that term anyway, is about 538,000 killer jewels. And so the work out is then simply the the heat in minus the heat out eso we get that? That is about 82,000 killer jewels. So that's the amount of work we could get if we have a reversible cycle

So we need to find a snort. I had to 19 a to find 15 temperature. So for that it's not on. Uh, the temperature given is 1.53 which which converted to Calvin myself 200 74 when succeed. Yes, Delta is on decision less. It does. He can. So, uh, indulgent, as at 2 74 is given 67 21 site. Mhm. Plus Delta's vision is love cream by the temperature. That is, to 74 point success kind up. So I multiplied. The 12 points is collateral formals, my 1000 And the study debt says more fitting. That is a C de even is 97.78 They're the edge by D. The limited to 74.682 298.1 site. Do you think? Yeah, plus 10586 A little plane 586 into T minus two seventies 4.68 Mhm. Which, after calculation it becomes 1 21.3. Joel Barr, Calvin or more

In this problem, we have a two kilogram upper block which is taken from current five degrees Celsius. 200 researches. The excessive heat of cover is given and we won't find out two quantities for the first thing. It's heat no, that definition off specific. He is that the amount of heat required to change the temperature by BT is able to see m d T. It is to change the temperature off a copper block off mass M bye D key is simply CNDD now. By integrating this on, both sides will see that on the left hand side. Cue music will do because CMA cm are usually both constants in this the specific it is usually a concert over that temperature range. We can simply pull the model of integration on integrated 40 giving us cm gelati. This is the usual definition. We have so will simply use. This heat is simply 386 jewels for kg. Kelvin, remember that one degree change in searches is the same as 23 changing Kelvin. So the units are both the same mask is two kilograms on the change in temperature is 75 kelvin under degrees, minus 25 degrees and 75 cents. Yes, just the same as 75. Kelvin, change in temperature. So that is it. The cages canceled. The Kelvin's cancel on the number can tell to be 5179 times and part for Jules. No. Now that we have this, we want to find the change in entropy. Now, Delta s Now we know that instantaneous change in entropy is dick. You bitey So integrating on both sides we get on the left hand side till there s another I can't say we have integral off m CDT bitey and see the constant which gives us n c log he do by Cuba. Same place that this is The mask is two kilograms. C is 3 86 jewels for kilogram. Big Kelvin on large rhythm off. Remember the T T y t one? You need to convert them into Kelly. So t two is 3 73 kelvin anti one is trees to 73 plus 25 inches to 98. Karen and that is it. The units of Kelvin canceled on this. That's after we want 73 jewels. It's just that

Discussion will understand the basic concepts of the optics. So the question is there is a thermodynamic cycle given in the figures. We have to find the heat absorbed by the system. Right? So as we know that since it is a cycle so he'd absorbed would be equal to be well done because the change in the internal energy would be judo. And what then is equal to be area under the graph area another baby glove. Right? So since it is a circle, so it is equal to the area of the circle, right? So that would be equal to by uh the square. But they can change the units first. So buy into 100 into the next party because it is kill Abascal multiplayer by 100 into 10 x -6 because the volume is in C. C. Right? So when we simplify this, We get the area is 31.4 jewels. So the heat absorb would be equal to 31.4.


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