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A sample of gas originally at 25 %C and 1.00 atm of pressure in a 2.5 L container is compressed and cooled to 0.85 atm and 15 %C. What is the final volume of the ga...

Question

A sample of gas originally at 25 %C and 1.00 atm of pressure in a 2.5 L container is compressed and cooled to 0.85 atm and 15 %C. What is the final volume of the gas?3.02.8 L2.6 L2.1L0.38 L

A sample of gas originally at 25 %C and 1.00 atm of pressure in a 2.5 L container is compressed and cooled to 0.85 atm and 15 %C. What is the final volume of the gas? 3.0 2.8 L 2.6 L 2.1L 0.38 L



Answers

The volume of a quantity of gas at 1.00 atm is compressed from $3.25 \mathrm{L}$ to $2.24 \mathrm{L} .$ What is the final pressure of the gas if there is no change in temperature?

Hi everyone. So in this question, a sample of gas has initial volume of so you went down. Mm. We won 26.8 l At a pressure .86 atmosphere. So B one right blind 86 atmosphere. If the gas is compressed to pressure of two point fire atmosphere, the two Yeah, two point for you atmosphere. What is its volume? That is We do now we know that. Yeah. According to Boyle's law. According to Okay. Boyle's law. P one Ribbon is equal to be to return and therefore we do is equal to we won. We won upon. Me too. Sofia needs 0.86 In 2 26.8 divided by mhm two point for you and therefore We too. That is equal to 9.2 192 leader. Yeah. Yeah. Okay. Leave that. Yeah. Okay.

For this question, you have to use the formula. P won t one equals two p t t t. Angie are given the gas is initially asked TP This information gives you pressure. It's one a t m and the temperature p one ace to 73 Calvin. So from this information, you should be able to generate days to information. So the second step is by substitution P one, It's one over to 70 equals two p two is what you are finding and divided by the temperature is 2 50 last 2 73 So P T s equals two 1.98 PM roughly on the night.

Okay, so we have the initial pressure. Initial pressure off too. It's got a P abi is equal to 5.25 a. M. The volume and this show is also equal to one leader. And our temperature in the show is equal to 26 Celsius which is 299 Calvin. Now the initial volume of event too of 02 we've got at the two, is it five liters? It temperature abstain. Temperatures of T I and P. If I not the chocolate. The total pressure in a volume of 12.5 liters at temperature 20 Celsius which is equal to 293 Calvin will be transferable with gases and two and two in it. You see that he won the one because n of into of r and D I we have end of into is a p i c I over Artie. I plug me in our given information, we see that this is equal to 0.21 for more and we know that p i and the two people to end 02 r of t i Oh, and a p I. The two over our a c I fucking in are given bearable. You see that this is equal to 1.7 So the total number of more is equal to the balls off Oh, to an end to that 1.7 plus 0.214 which gives us a total of 1.284 fold. Now let's calculate the total pressure in a music player so seldom repeat, we have an arty over. Be using our malls and R R T and B. We get 2.47

Hi there. Chemistry students in this example were given a sample helium gas. Initially, the volume of this helium gas is at 125 milliliters. It has an initial temperature of 100 degrees Celsius and an initial pressure of 0.981 atmospheres. Well, we want to do, though, is to figure out what's going to happen to the volume of this stable of helium gas if we decrease the temperature to 25 degree Celsius and increase the pressure to 1.15 atmospheres. So again, our job is to solve for what will the final volume of our helium gas be when we change these parameters, said a cell for this type of problem will have to use the combined gas law. This combines boils Gas law, which shows us the inverse relationship between pressure and volume as well was Charles Law, which shows us the direct proportionality between volume and temperature as always, gay loose sex law, which shows us the direct relationship between pressure and temperature. So in order to solve for this to combine these all together, since we have variables of pressure, temperature and volume, we're going to combine each of these equations here in order to get her overall combined gas law equation. This equation becomes P one, the one over T one for initial pressure, volume and temperature of our substance equals P two V two over T to our final pressure volume and temperature of the substance. Now this combined gas law works with most of the units that we have about, but it's important that we consider the humans of temperature while volume is okay and no leaders as long as it's the same on both sides of the equation and pressures. Okay and atmospheres as long as it's on both sides of the equation. Temperatures one that we have to change temperature in this case cannot be in degrees Celsius. But it must be in Kelvin. And this is used in gas law problems, because the pressure and the volume of a gas actually depend upon the kinetic energy of our particles or the motion, our movement of them. So in order for us to self currently, we have to convert her temperature from degree Celsius into Calvin and to do so is very simple up here about for our initial temperature at 100 degrees Celsius. To convert this into Kelvin always simply have to do based on the scale is to add 273. This gives us our new temperature in Kelvin as 373 Kelvin. We must also do so for the other side of the equation. For our second temperature, the second temperature drops to 25 degree Celsius. But to convert that into Kelvin will add 200 who had 273 which is going to give us a total of 298 Calvin. And now the next step simply just requires us to plugger information into our equation. So our first pressure here was given to us initially that the pressure of our helium gas is P one or zero point 981 atmospheres and we're gonna multiply that by V one, which here we can see is given to us as 125 milliliters and one of places all over a temperature. Our temperature was 100 degrees Celsius. But remember, this must be intelligent, and we just added to 73 to determine that this initial temperature is 373 covet. So that's all of our initial parameters of pressure, volume and temperature for helium. But now we want to figure out Well, what happens if we change the pressure? Let's say now we increase or pressure for P two here toe 1.15 atmospheres. And then we also are trying to sell for that second volume. Remember this here V two were trying to figure out what happens to the volume when we change your parameters of helium. They were in a place that over a new temperature, we just found t to here to be equal to 298. Kelvin, lastly, is tending user calculators to solve her V two in your calculator. If you look at this left hand side of the equation and plug it in, take 0.981 tends 1 25/3 73 This is going to give you a value after three significant figures has shown is the least number and the problem here with multiplication and division as zero 0.3 to 9, then this is equal to still 1.15 times V two, which were trying to solve for over 298. So to get V to all alone by itself or in after, multiply both sides by the denominator here to 98. So it cancels. We'll also multiplied this year by 2 98 a swell this. Then side comes down still with three sig figs to 98 point up. That then equals 1.15 times of you to which we're trying to get by itself. So if we divide both sides by 1.15 this cancels and 98.0, divided by 1.15 gives us her final answer. V two out of three significant figures gives us 80 of 5.2 and our units for volume. Here are milliliters. So right here we have our final answer. Just


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