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You Manmum Asca Lelerre getre 1 recianguliar piece 1 H thal lenglh can 33.3 b8 consanctceght y(juiodTne Jamoi tiynl cole( t0 be 1 1...

Question

You Manmum Asca Lelerre getre 1 recianguliar piece 1 H thal lenglh can 33.3 b8 consanctceght y(juiodTne Jamoi tiynl cole( t0 be 1 1

You Manmum Asca Lelerre getre 1 recianguliar piece 1 H thal lenglh can 33.3 b8 consanctceght y (juiod Tne Jamoi tiynl cole( t0 be 1 1



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$\mathrm{K}_{2} \mathrm{CrO}_{1}$ givcs a ycllow precipitare on rcaction with: (a) $C_{4}^{2}$ (b) $\mathrm{Fe}^{3}$ (c) $\mathrm{Ba}^{2}$ (d) $\mathrm{Pb}^{2}$

In the problem we have 56. And this is yeah it is gen X get works. Get three X. Get your necks. It's two weeks is tricks plus if one X after works three X gen X G networks. GTX H one X. HdX history X plus. If you're next afterwards after the X. And the one x. Networks G three X H one X H two x. and three x. No further. We have fds a. And this equals two. If one yeah. Have to wear after a year. Do you want to G two A. Gayatri? H one A. It's too good. Is three. Okay. And these are reputed To two times more studies if one A. Have to A F three given a and geeta, Geeta A 20 H two A. It was today glass if one after where have today do you want to? They were the tree H one A H two A is three. Now this equals to zero plus zero plus zero which is equal to zero. Since F R A Is equal to zero. G R A is equal to H R A. Is I mean this equals to 04. All the times that is if R0 gr hr is also zero For Article 1, 2 and three. So we have this as the answer to the problem

In order to find the inverse of this matrix, we will use the fact that it's non singular if it's real equivalent to the identity matrix. And at that point, once we transform this matrix into its row reduced echelon form, which will be the identity matrix. We can work backwards backwards to represent the identity matrix as a product of this matrix, the one that I'm pointing to here in the elementary matrices that we use to roll, reduce it. So let's jump in. The first thing we will do is take row three minus row one to replace Road three. Next we will take row three minus road to To replace Road three. Now we will take road to -2, row three to replace road to And then row 1- row three To replace for one. And then lastly, row one minus wrote to to replace Rohan, Which is the identity matrix, that three x 3 identity matrix. So now what we can do is used these row operations to represent the identity matrix as a product of our original matrix and these elementary matrices. So what we have is the following. So what this is. Well at least these matrices, these matrices are the row operations that we use to reduce our original matrix into it's row reduced national in form, which is the identity. And this matrix, of course, that's what we originally had. And this matrix is the identity. And in order to make sense of the left hand side, we can use the fact that this matrix here, this is represented by the last operation, the last row operation that we did here. So that states that row one minus wrote to To replace for one. So that's how we obtained these elementary matrices. So now all we have to do is find this product of elementary matrices, which happens to be the following matrix and we still have our original matrix, and we know that this product is equal to the identity. So finally, if we multiply both sides of this equation on the right by the inverse of our original matrix, we get that its inverse is equal to the product of the elementary matrices that represents the elementary row operations that we used to obtain the row reduced echelon form of our matrix, and that completes the problem.

In this problem, the yellow solution that is, I need to see a shadow for in pageants of as tours of four as well as as to will give orange solution we teach. I need to see our 247 and this is orange in color so this is orange solution. And according to the option option C. H, correct answer for this problem. Option C. Each correct and said for this problem, I hope you understand the reaction of this problem.

And this problem we are given that Matrix A. is the three x 2. Matrix six I get 1- zero. Now you have 34. Mhm. And Matrix B is the Matrix Uh huh. 31 And yet 1560. And we want to find first A plus B. Now to add to major cities, you just add the corresponding components together. So top left close, Top left Is what goes on. The top left search plus three is 9. Top ride was top ride, It was in the top right now give one postponement 0. And then we proceed in this matter. Two plus negative one is one, zero Plus 5 is five. They have three plus six is three Than 4.0. As for And so that is our Matrix A plus B. Now for the Matrix A minus B. Take our correspondent components again and subtract the light terms 6 -3 is three -1 -1 is -2. Two minus negative one is three, 0 -5 is -5. Then you have 3 -6 is -9. 4 0 is four. Now for two a. We take everything and a and multiply it by two. six times 2 is 12 in one times two is that you have to We have 40 -6 and eight. And then lastly we want the matrix negative three C. I'm sorry, 93 B. Three B. That means take everything and be and multiply it by negative three 789 Now you have three. Three may have 15 negative 18 zero.


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