5

CH,-0-C (CH,hg CH;EALOH CH - 0- C - (CHzh CH =CH CH;CH,-0- € - (CH,)uz CHa...

Question

CH,-0-C (CH,hg CH;EALOH CH - 0- C - (CHzh CH =CH CH;CH,-0- € - (CH,)uz CHa

CH,-0-C (CH,hg CH; EALOH CH - 0- C - (CHzh CH =CH CH; CH,-0- € - (CH,)uz CHa



Answers

(a) RCHO (b) $\mathrm{RCH}_{2} \mathrm{OH}$ (c) $\mathrm{RCOOH}$ (d) $\mathrm{R}-\mathrm{C} \equiv \mathrm{CH}$

In this problem did yet then it happened something like this. CS three CH 2 C 00 quiet In presence of Sierra two. They fast for us at media reaction will take place and product for me. CS three CS SEAL c o H on further reaction with alcoholic a witch. It will give final product ID C. H to the well born c h c cocoa page according to the option Yes. Obscenity is correct answer option B. Each correct answer for this problem.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.

In this problem, I can write DDX in it see http CH two C 00 H. This compound in pageants of Cl two A red P. That to be dad reaction. It will give the compound edge, see http C h C L C. O AT and this compound in perchance of alcoholic kO edge. The hydro chlorination happened here and the compound formed the CH two double 1 C h c o egg. Therefore, according to the option of indeed correct option, the is correct answer. I hope you understand the solution.

In this problem, I can write D. D. Jackson ad CH three CO at in Belgian cell associate to in Potenza as so Cl two will give the compounded see http c o c n and this compound in pageants. So see http all too. An image will give the compounded c h t c 00 N CF three old too. And according to the option of indeed correct here. Therefore, of Sandy of 70 each correct answer option indeed, correct answer for this problem.


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