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Which of the following ketones, aldehydes and esters can undergo self condensation reaction in the presence of appropriate base and which one cant?2,2-dimethyl 3-pe...

Question

Which of the following ketones, aldehydes and esters can undergo self condensation reaction in the presence of appropriate base and which one cant?2,2-dimethyl 3-pentanoneChoose__ethyl propanoateChoose_ethyl propenoateChoose_.diethyl oxalateChoose_diphenyl ketoneChoose__acetaldehydeChooseiso-propyl acetateChoose_butanoneChoose_methanalChoose_.

Which of the following ketones, aldehydes and esters can undergo self condensation reaction in the presence of appropriate base and which one cant? 2,2-dimethyl 3-pentanone Choose__ ethyl propanoate Choose_ ethyl propenoate Choose_. diethyl oxalate Choose_ diphenyl ketone Choose__ acetaldehyde Choose iso-propyl acetate Choose_ butanone Choose_ methanal Choose_.



Answers

What ketones or aldehydes might the following enones have been prepared from by aldol reaction?

Yeah, yeah. Protection involved a very similar mechanism. Mmh. The group is first programming making me right carbon in carbon. More in a conflict. No, they is mhm. Okay. Yeah. Okay. Nuclear file. Excuse you. Explain them. Take this. A nuclear file. Can you take this? Common it. Oh, it's okay. Yes. Whoa. Mhm this bomb. So no, don't. It's obstructive. And that girls. Well, it's Yes, it hadn. Oh, again, this is, uh so it doesn't hit me. How has he done? Yeah, I owe depositary. Yeah. Next two digits. Again. Broken aged. It's too. Oh, it's blue base again. Coordinator giving. Making the well. It's a good living loop. Yeah, for extra bloods. And, uh, okay. The self for with facilitate the removal of this as a living group. Double bond. Yes, the Baltic entrance. Now here again, the second market up aiding Taiwan. But that's which form coyote door. This speech. What you do A minus. We'll expect the program now giving the pain in college. Yeah,

As we all know that a little condenses, an easy reaction that can occur between two worlds hide and I'll be hide in the keystone to Britain. But and all condensed sensation at all. Condensation cannot be cannot occur between, and I'll be hide and already hide and an easter. So all the options are give you adult condenses, and all the options are give adult condenses and accept option D. Therefore, according to the question. Abs indeed, correct here, optionally, is correct.

Until four part A without developing anti hiding Kitona Sullivan in water. So Andy, hide in ketone containing four carbon atoms are soluble in water while containing five. Carbon atoms are slightly syllable, but more than five carbon atom containing L d. Hide in Katonah. Not solution in water. So here. So here in part A. There are three carbon atoms, so salute Bill in water. All right. Okay. Right, right. Right. Pain for part B on there are three carbon Aito in two tone group, so salute in water, right? Uh huh. Uh huh. Uh huh, Uh huh, Uh huh. Mhm. Okay. Silver. Well, the hide the ink tone containing four carbon atoms are soluble in water while containing five. Carbon atoms are slightly syllable, but more five carbon atom containing al de hiding Kitona Not soluble in water. So here three carbon atoms into tone groups are soluble in water. Uh huh. Okay. Yeah, right. What next? We am Parsi. There are six carbon atoms in ketone group. Uh huh. Credible. So insoluble in water. Oh, right. Oh, Uh huh. Uh huh.

Okay. This problem was asking us Which of the following are algal condensation products? Okay, So in order to determine whether it is an elder conversation product, we first have to draw out the molecules in which were given to the 1st 1 is two hydroxy to metal fentanyl. So whenever I am given the name of a molecule like this, the very first thing I looked is I look towards the very end of my molecule name. So in this case, I would look at Penta now. So Pantanal specifically the a l corresponds to an Alba hide. So it doesn't matter where in my Melco my overhead is because I know that's going to have a hydrogen on the very end. So I know that with my behind is going to be at the end. Okay, So the pent of my Penton l corresponds to the, um five carbon nature of it. So one position one And in 2345 So that is a five carbon compound. Okay, so as for the two metal at position two right here, I would have the addition of a metal group, so I'm going to write that down. I have a method group at position two and then episode into as well. I have a hydroxy group. So alcohol. Okay, so the question is asking, Is this an album conversation product? And the answer is no. Simply because an elbow conversation product would have the elimination of the hydroxy group. And to, uh, add to this that hydroxy group is not even in the correct position. You need to have to be here or here. It can't be at the actual outfit position, So that is definitely not an album conversation product. Okay, The next one is, um five Ethel five vessel or metal for help, then 30 okay. So same exactly in his before. Whenever I'm given a name, I always look to the end. So I see own so own correspondence to a key tone. So I know that when my functional groups is going to look like this, in which I have a cardinal and the corresponding carbons on either side. Okay, But the question is, where is that? He tone that keystone is located at the third most carbon. Okay, but how many carpets don't have? Well, I have for I'm sorry. I have seven because of helped. So I'm gonna draw up seven carbons. So like this. 123456123456 seven Pickett have seven right now. So the key tone portion is on the third most carbon. So 1234567 at the third Carbon is where I have my Carbonell. Because that is the own portion. Okay, what about the four? What does that mean? Well, if we see within my molecule, we have the and so n if we look back to the previous one, we see, um, and an means the just single buns, whereas n means double bond. There's a double blind in there somewhere. And that double bond is that position for so 12345 So between four and five is my AL Keen. My double bond. It's right there. Okay, Someone Every job that in red in red. I have my Elke. Okay. And next up is the, um, left side. So every time I'm dealing with these naming conventions, I will just pretty much go from right to left. Okay, So next up is a method group. That method group is that position for the same thing? I have four at position four. I have a metal group, and the next over is my five. Felt that five. Ethel is right here. Just two carbons connected to carbon number five. The question is, what did this Malky look like before? Was it a key tone was an Alba hide. We don't know yet, but my trick is essentially to figure out the location of my double blind. Some of the one is right here. Okay, So, um, in reality, when we're dealing with Albert Kahn station reactions, we have two molecules are acting with each other. We have our nuclear file. So if the medicus Okay, that is one nickel fell, and then my Electra file is either the same compound or another compound that would be given to us. So in this case, um, the answer would be this. It looked like this. And the reason is because my trick is to find out where this double bond is located right there. And that used to be the carbonell portion of a compound. Okay, so if I were to draw and, uh, my auction right there this for here which I'm going to circle corresponds to this right here. So this which my arrows pointing to is my Electra file. And then this portion, which all highlights in green Never mind that auction is this molecule nuclear file. So what we do is we figure out the nuclear Philip portion, my molecule right here. And then we figure out the Electra file. In this case, it's this entire molecule, specifically this nuclear files going to attack that Carbonell, and then we. So once we figure out the electric file, then we highlight it or redrawn. If we're going on paper, put it on to our nuclear Philip position. So right here and then subtract that oxygen. And by subtracting the auction, we should end up with our final product. So this corresponds to that, Will redraw that. Okay, so that the semi like thing is just the location of the double bond. It might be Sister Trans, but our years e But this is the same molecules that okay. And the reason we do that is because we have that trick. We can identify the nuclear Philip position and then attack our Electra file and then just remove the oxygen. Okay, so that would be our trick. So the answer is just, um three Penta note which looks like this I would have to of those and they would react with each other.


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