5

Naoh, ThFDh(Producl )...

Question

Naoh, ThFDh(Producl )

Naoh, ThF Dh (Producl )



Answers

$\frac{\text { (i) } \mathrm{CCl}_{4} / \mathrm{NaOH}}{\text { (ii) } \mathrm{H}^{+}}$ (A)

In this question, We have to find the weight of the knowledge in its 60 mil equivalent. Therefore the midi equivalent, we can diet as M E Q, which is Formula W by E. Into 1000. Therefore, Male equivalent is close to 60 and have to find a bit of any wage. By 40 into 1000. Therefore, 1000 W was to 60 to 40 W. It was 260 into 14 By 1000. We can cancel, Then we get the blue equals two, 2, 4 x 10, And we can buy because 2.4. Ground. Thank you.

So hi everyone. So in problem 56 of Chapter eight in community of heavier elements metallurgy. So in this question, Lunar Caustic is, so the chemical formula of lunar caustic is silver nitrate, which is a G N. 03. Okay, so, silver nitrate caustic chemical compound important as an antiseptic in the industrial preparation of other silver salt and as a region in analytical chemistry. So it's formula is A G. And 03, and it is uh silver nitrate is used either in stick form as lunar, sarcastic Or in solution of uh .01% to 10% silver nitrate in water. So it's formula is a G. N. 03, so which is given in the option number three.

In this problem, we need to write out the reaction of the pontification of a zero die, only eight mono commentate, and we need to react it with an a o. H. We can start by drawing out the structure of glass. Zero Dy Oli eight Mono pal Meditate using the structures of visceral Dominic acid and Oleic acid we know from the name that die corresponds to two equivalents of Oleic acid. Reacting at two of the O. H sites from glycerol in the remaining O. H from glycerol is where we formed a bond with mono, one equivalent of paramedic acid, and that would correspond to imitate and only eight in each case. Because after we form those bonds with the O. H groups from the carb oxalic acid portion of on the nick and Oleic acid, the condensation reaction removes water and that ball that bond forms and therefore makes this the structures of each one of these acids, an anti on which corresponds to only eight and pal imitate in each case. So when we begin by forming those bonds at those three sites on cholesterol, we can draw out visceral in the way in the back bone structure of having ch two group bonded to a CH group on it to another CH two group. And then all of those air bonded to and Oh, and the H has been removed as part of water and condensation reaction. And it's joined with the other each that that was removed, that the remaining oxygen is where that bond forms. So we can begin by drawing out the structure of the Ciro Di Oli eight mono pal imitate in that way, starting with the backbone structure of visceral, we have ch two ch ch two and now each one of these are bonded to. And oh, and then a carbon Neil see double bond. Oh, and then two of these are going to have the only eight, and I on and the other one will have the commentate and ion attached to the rest of that portion of the glycerol backbone. After that, condensation reaction occurs to form this molecule that we're going to react with nao each in the PSA pontification reaction. So starting with two oly aids moving to the left of where this bond forms from this carbon, Neil, see that we have 12 34 567 ch. Two groups. So we can begin by drawing that condensed structure of ch 27 And then we have a C H double bonded to another ch. So we can include that ch double bond ch. And then we have after that end of that double bond, we have 1234567 more ch two groups and then a terminal methyl group. So ch two seven ch three and remember that it's die only eight. So we have to of those structures on the ends of this molecule. So again, we draw this seem condensed formula or to only eighths. And then we have on the remaining site a mono So one pal imitate ion. So going to the left of where that bond form from the curb. Neil, we have one, 23456789 10 11 12 13 14 ch. Two groups attached to a terminal methyl group. So the mono pal imitate portion, of course, zero DiIulio mono pal imitate can be drawn a ch two 14 ch three And now we react this with three equivalents of any O h in the electoral negative oxygen is going to attack that Kurban Neil Carbon and the electrons will go up to this oxygen which will then kick out the leaving group, which are the and ions in each case. So when that happens, we form. We reform that alcohol, you regenerate glycerol, which is what we started with. And then we will also have to of the only eight and ions and one of the palm it eight and ions that air booth in a combined with the positive charge from the n A plus cat ion. So we can write that all out because this so each group we know we'll attack that carbon Neil to form that bond and so that will produce cholesterol. So that's one of the products so glycerol. And we can draw that structure as ch two o h ch. I wanted to know each and another ch two wanted to an o. H. So that's one of the products foreign from this reaction. And then after this leaving group of this only eight and I on leaves with a minus one charge, it will pair up with the positive one charge from the sodium ion to form that compound twice since we have two of these old yate and ions present in the starting structure. So we have to sodium only eight. And so we can draw out what one of those would look like with a coefficient of two. We could say we have two of these on pounds where we have ch three c h 27 c h double bond, ch C H 27 and then we were going to have a c 02 because it is in an ion, in this case, over on this. And now, since this is a leaving group and that hydrogen is gone, So this is a deep resonated and I, on form of only eight, with a minus charge combined with sodium with a positive charge to make this too sodium only eight. And so those are three of the products that are formed, and the last one will be that one, that one equivalent of sodium imitate so we can draw that out. And again, we just have one of these kids mono pal imitate in the original structure, and you see it's ch three ch 2 14 And then again, C o to minus is again. That is the anti on that's pal imitate. We dio from the rate to the left we we end up with to Oxygen's and that one carbon corresponding to that co two minus and I on or PAL imitate. And then again, that's combined with an A plus to make this a sodium pal imitate compound, and so those are the products of this reaction.

In this problem, this compound cl Here it is double gone in pageants of B, s, t D and then, and a oh edge Or H202 will produce the final product Bad this compound. So according to the option in this problem, option B. It correct answer. Option B is correct answer about this problem. I hope you understand the reaction of this problem.


Similar Solved Questions

4 answers
Clear AllThe pentose phosphate pathway starting from fructose-6-phosphateAerobic metabolismGlycolysis leading ` lactate productionAnaerobic metabolismGlycolysis leading t0 thc citric acid cycleBothi aerobic and anuerobic netabolismThe pentose phosphate pathway starting from glucose-6-phosphateSubmit AnsworTry Another Vornlon Itam attempts remalnlng3035250AcracPto
Clear All The pentose phosphate pathway starting from fructose-6-phosphate Aerobic metabolism Glycolysis leading ` lactate production Anaerobic metabolism Glycolysis leading t0 thc citric acid cycle Bothi aerobic and anuerobic netabolism The pentose phosphate pathway starting from glucose-6-phosphat...
5 answers
Based upon the information below, determine the variance between the actual and the simple budget for each line item in both dollar and percentages_Simple 28,500ActualVariancePercentageNumber of Patient Visits30,582 2,446,560Patient Revenue Variable Costs Contribuation Margin Fixed Costs Total Costs Prolits2,137,500641,250856,2961,496,2501,647,8521,282,500389,5421131,923,7502,245,838114 115 116213,750200,722
Based upon the information below, determine the variance between the actual and the simple budget for each line item in both dollar and percentages_ Simple 28,500 Actual Variance Percentage Number of Patient Visits 30,582 2,446,560 Patient Revenue Variable Costs Contribuation Margin Fixed Costs Tota...
5 answers
50 Evaluate the following sum: 2 (4i2 -3i + 20) =20
50 Evaluate the following sum: 2 (4i2 -3i + 20) =20...
5 answers
Suppose biologist studying gene locus in American Bison discovers that there are two alleles at the locus and E) and that they show incomplete dominance When the biologist surveys genotypes within deme; she finds that there are 10 bison with the TT genotype, 60 with the TE genotype, and 30 with the EE genotype (6 points):
Suppose biologist studying gene locus in American Bison discovers that there are two alleles at the locus and E) and that they show incomplete dominance When the biologist surveys genotypes within deme; she finds that there are 10 bison with the TT genotype, 60 with the TE genotype, and 30 with the ...
5 answers
Point) Use the parametric equations of an ellipse X= 4cos 0 y = S sin 0 0 < 0 < 2t to find the area that it encloses
point) Use the parametric equations of an ellipse X= 4cos 0 y = S sin 0 0 < 0 < 2t to find the area that it encloses...
5 answers
Let x > 0 and consider the 4th order ODE(2x + 1)2y(4 (2) + 8(22 + 1)y" (2) + 8y" (2) = 0. Show that with the appropriate substitution(s), equation (4.1) is equivalent to(4.1)t20" (t) + 4tv' (t) + 2vlt) = 0.(4.2)for t > 0.(b) Find the genera solution of equation (4.2) for t > 0.(c) Using your result in (b); find the general solution of (4.1).
Let x > 0 and consider the 4th order ODE (2x + 1)2y(4 (2) + 8(22 + 1)y" (2) + 8y" (2) = 0. Show that with the appropriate substitution(s), equation (4.1) is equivalent to (4.1) t20" (t) + 4tv' (t) + 2vlt) = 0. (4.2) for t > 0. (b) Find the genera solution of equation (4.2) ...
1 answers
Find the derivative of the function. $$ f(x)=e^{\cot x} $$
Find the derivative of the function. $$ f(x)=e^{\cot x} $$...
5 answers
Question 41 ptsWhat type of interaction does DNA ligase create between adjacent nucleotides?hydrogen bondingionic bondingphosphodiester bondinghydrophilic interactionhydrophobic interaction
Question 4 1 pts What type of interaction does DNA ligase create between adjacent nucleotides? hydrogen bonding ionic bonding phosphodiester bonding hydrophilic interaction hydrophobic interaction...
5 answers
6+ S)v" Iv +V =0 Kemuma Isolton ddi hurin y 1e #dr Iat dmetenbat o7teon conutono abit oBrehebzm) sinoueur Danes otI duleunnlil #OLLCA Ininttne Ls5)14 Suesicuiing _ 5 m m(5+ Sv"Vidnl UWeecnpl 61u (4 Mcraalng NJmban 0} In 0o1e 0 Ei culnot novo An IceUl} onnu Iemit! Ia1In Inie #opw El 04} From0t Eenslo Jove Webrox InalErnmakicanticr"0 Gumvnlounpra ~ouulion (I+Sv" (4nu
6+ S)v" Iv +V =0 Kemuma Isolton ddi hurin y 1e #dr Iat dmetenbat o7teon conutono abit o Brehebzm) sinoueur Danes otI duleunnlil #OLLCA Ininttne Ls5) 14 Suesicuiing _ 5 m m(5+ Sv" Vidnl U Weecnpl 61u (4 Mcraalng NJmban 0} In 0o1e 0 Ei culnot novo An IceUl} onnu Iemit! Ia1In Inie #opw El 04}...
5 answers
Queatior 12Find the derivative of cach of the following: y-8r 31+4 V =. 2x(+2 _ 21* )(Zx + 3)r+1)727 3x66r' 32y-7r'-7+7ye3r2+215Ogoertisn j33For the greph shown, sketch the graph cf the gradient functicn:"aX_Z'_
Queatior 12 Find the derivative of cach of the following: y-8r 31+4 V =. 2x(+2 _ 21* ) (Zx + 3)r+1) 727 3x6 6r' 32 y-7r'-7+7 ye3r2+215 Ogoertisn j33 For the greph shown, sketch the graph cf the gradient functicn: "aX_Z'_...
4 answers
Polnt) Sorne college prolessors and stucents exarined 160 Canazlan guesu culyni schislosomc the yuar Iney nalchud_ Of inese 160 blrds; Ve Mlected The prolessors Jnd students WCIL utereset estimating the proportion of infected blrds tnts type.ulur sludiys dulerinine Ine sample &20 s that thu esunale 0l p Wilmin 0.07 of tne unknown conlidencu_95%Sample size required
polnt) Sorne college prolessors and stucents exarined 160 Canazlan guesu culyni schislosomc the yuar Iney nalchud_ Of inese 160 blrds; Ve Mlected The prolessors Jnd students WCIL utereset estimating the proportion of infected blrds tnts type. ulur sludiys dulerinine Ine sample &20 s that thu esu...
5 answers
Quesbicm 12Actrtaln gas occuples 53,2Lat 237atm What pressure inkPa wlllcause t0 expatkl 696,947 (assume temperaturc remalns constant)
Quesbicm 12 Actrtaln gas occuples 53,2Lat 237atm What pressure inkPa wlllcause t0 expatkl 696,947 (assume temperaturc remalns constant)...
1 answers
Let Z1, Zn be an iid sample from a standard normal distribution, that is a normal distri- bution with mean 0 and variance 1_ Let Y CiZi and Ry(t) = In(My (t))lim Mx (t) nF00lim Mz(Ya)" nF00Taking the natural logarithm, and setting C =lim = lim Rz(ct) nRz(_n) n=00 c-0Show thatRz(ct) t2 lim c-+0 2
Let Z1, Zn be an iid sample from a standard normal distribution, that is a normal distri- bution with mean 0 and variance 1_ Let Y CiZi and Ry(t) = In(My (t)) lim Mx (t) nF00 lim Mz(Ya)" nF00 Taking the natural logarithm, and setting C = lim = lim Rz(ct) nRz(_n) n=00 c-0 Show that Rz(ct) t2 lim...
5 answers
QuestionFind the interval of convergence I for the power series '(-1)"z2n. Give your answer in interval notation: n_0Provide your answer below:FEEDBACKMORE INSTRUCTIONSUBMITContent attrlbutlon
Question Find the interval of convergence I for the power series '(-1)"z2n. Give your answer in interval notation: n_0 Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attrlbutlon...
3 answers
10) (15 points) Predict the product of the following reactionsI)LDA1) Brz/PBr_21+oNaOE:EtoHNaOMe' MaOH1) NaOev EtOH3) H;o'CuLli3)H,oNaOMeCHO (CHOH)z CHzOHHNO;MeOHCHO 1) BrzHzo CHOHX CHzOH 2)HOz. Fez(SO IaCHO KCN HCN (CHOH) CH_OH 2) Hz, PdrBaSo4 3)H;ot1) Brz/PBrz2)H;o 3)NH;NHz pl = 5.7PH 5,7 buller
10) (15 points) Predict the product of the following reactions I)LDA 1) Brz/PBr_ 21+o NaOE: EtoH NaOMe' MaOH 1) NaOev EtOH 3) H;o' CuLli 3)H,o NaOMe CHO (CHOH)z CHzOH HNO; MeOH CHO 1) BrzHzo CHOHX CHzOH 2)HOz. Fez(SO Ia CHO KCN HCN (CHOH) CH_OH 2) Hz, PdrBaSo4 3)H;ot 1) Brz/PBrz 2)H;o 3)NH...

-- 0.018881--