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Spider silk thc strongcst known matcrial nanira man-Madc wcight hasis atua} cramincd thc mcchanical propcrtics ~iccr silk using 21 female colden Orb wcavcrs_ Nephil...

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Spider silk thc strongcst known matcrial nanira man-Madc wcight hasis atua} cramincd thc mcchanical propcrtics ~iccr silk using 21 female colden Orb wcavcrs_ Nephila clavipes_ Thc data on silk yicld stress represents the amount of force pcr unit arca needed rcach permancnt dcformation of thc silk strand Tric dara arc cxpresscd in mcgapascals (MPa)164.0 478.7 2513 351.7 173.0 448.9 300.6 362.0 272.4 740.2 329.0 327.2 27055 332.1 288.8 [76.1 282.2 236. 358.2 2705 290.7(a) Usc the snftware choice s

Spider silk thc strongcst known matcrial nanira man-Madc wcight hasis atua} cramincd thc mcchanical propcrtics ~iccr silk using 21 female colden Orb wcavcrs_ Nephila clavipes_ Thc data on silk yicld stress represents the amount of force pcr unit arca needed rcach permancnt dcformation of thc silk strand Tric dara arc cxpresscd in mcgapascals (MPa) 164.0 478.7 2513 351.7 173.0 448.9 300.6 362.0 272.4 740.2 329.0 327.2 27055 332.1 288.8 [76.1 282.2 236. 358.2 2705 290.7 (a) Usc the snftware choice spruu distribuliun: makc dntplot thcsc data Sclcct thc cnnect descriptinn sup centcr, and The distjbution unimodal ad essentially symmetric except for a high outlier The center is approximately 29- MPa. The Sea frort 164,0 740.,2 MPi. The distribuliur unimodal ad exlremely lelt-skewed excepl lur 2 high oullier. The center "pproximately 240 MPa The 473d Irom 164.0 740.2 MPi. Thc distribution unimodal and cxtrcmcly Iefi-skcwed exccpt for a high outlicr; Thc ccntcr approximatcly 350 MPa: The Sored from 164.0 478.7 MPa. The distribulion unimodal and essentiall; 5 " mi[[e Tc excepl jor bigh outlier The center approxitalel; 291 MPa The spread : [rom [6+.0 478.7 MPi. (b) Find the Tern Aro Tedian yield stess. (Enter the mean Tw0 dec: places and the median one decimal place ) Note: If you aree usitg CrunchIt YOu Iay adjust the delault precision urider Prelerences See the instruclional video 0n how adjusl EICCEE[UI settings. Compare thesc tWO valucs; Rcfcrring your plot, what gcncral fact docs comparison illustratc ! The large outlier; seem Lit dolplol causing Ue Mejn be ETeater than the mediwn_ The approximately syturnetric distibution_ the dotplot; cavsing JiC [ei be greater than the media: Inryc outlier; seen Eit dotplot causing te Mear De Iess than the median The approximately symmetric distribution, seen in the dorplo , causing the mean be about the same fnediali



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The nuclear pore complex (NPC) creates a barrier to the free exchange of molecules between the nucleus and cytosol, but in a way that remains mysterious. In yeast, for example, the central pore of the NPC has a diameter of 35 $\mathrm{nm}$ and is $30 \mathrm{nm}$ long, which is somewhat smaller than its vertebrate counterpart. Even so, it is large enough to accommodate virtually all components of the cytosol. Yet the pore allows passive diffusion of molecules only up to about 40 kd; entry of anything larger requires help from a nuclear import receptor. Selective permeability is controlled by protein components of the NPC that have unstructured, polar tails extending into the central pore. These tails are characterized by periodic repeats of the hydrophobic amino acids phenylalanine (F) and glycine (G). At high enough concentration $(\sim 50 \mathrm{mM})$, the FG-repeat domains of these proteins can form a gel, with a meshwork of interactions between the hydrophobic $\mathrm{FG}$ repeats (Figure $\mathrm{Q} 12-2 \mathrm{A}$ ). These gels allow passive diffusion of small molecules, but they prevent entry of larger proteins such as the fluorescent protein mCherry fused to maltose binding protein (MBP) (Figure Q12-2B). (The fusion to MBP makes mCherry too large to enter the nucleus by passive diffusion.) However, if the nuclear import receptor, importin, is fused to a similar protein, MBP-GFP, the importin-MBP-GFP fusion readily enters the gel (Figure $\mathrm{Q} 12-2 \mathrm{B}$ ). A. $\quad$ FG-repeats only form gels in vitro at relatively high concentration $(50 \mathrm{mM}) .$ Is this concentration reasonable for FG repeats in the NPC core? In yeast, there are about 5000 FG-repeats in each NPC. Given the dimensions of the yeast nuclear pore $(35 \mathrm{nm} \text { diameter and } 30 \mathrm{nm} \text { length })$ calculate the concentration of FG-repeats in the cylindrical volume of the pore. Is this concentration comparable to the one used in vitro? B. A second question is whether the diffusion of importin-MBP-GFP through the FG-repeat gel is fast enough to account for the efficient flow of materials between the nucleus and cytosol. From experiments of the type shown in Figure $\mathrm{Q} 12-2 \mathrm{B}$, the diffusion coefficient $(D)$ of importin-MBP-GFP through the FG-repeat gel was determined to be about $0.1 \mu \mathrm{m}^{2} / \mathrm{s}$. The equation for diffusion is $t=x^{2} / 2 D,$ where $t$ is time and $x$ is distance. Calculate the time it would take importin-MBP-GFP to diffuse through a yeast nuclear pore $(30 \mathrm{nm})$ if the pore consisted of a gel of FG-repeats. Does this time seem fast enough for the needs of a eukaryotic cell?

At soon by the given data. Yeah. When? Yeah, the land in credits. Mhm. The resistance. Yeah. Yeah. Mm. Yeah. The distance increases. Okay. 13 millimeter, then length decreases. Mhm, mhm. And our begins to decrease. What? So all it's directly was going to win? So correct choices, See? All right. Yeah.

This is a problem. # 29 We are given a set of data regarding regarding the per capita disposable income for each of the 50 States and District Columbia. First we will construct a frequency distribution Given that the lower bound of our class is 20,000 and our class with our 2500. We will get the following for our income. Mhm. I'll just round both of these classes to make it easier to fit. So we have 20- 25 K. 22.5. Mhm. 22 5-25, 25-27 5 27.5-30 30 to 32.5 32 5-35, 35 to 37.5 37 5 to 40 and finally 40- 42.5. Now these are not inclusive of the bounds. This is obviously this will be like 22499, I just ordered like this to make it easier to ride out for our frequencies. If we count each of these data points, we get the following three, 10, 14, 12, seven, two, two, zero and one. And when we calculate our relative frequency we get 5.9%,, 19.6%,, 27.5%,, 23.5%,, 13.7%,, 3.9%,, 3.9%,, 0% And 2.0%. So as we can see most of our data is in the top part of our data set. And when you construct your hissed a gram, it does seem to follow this so it is very slightly right skewed. If we are then to change our class sizes to be 4000 wide you will find that the data is significantly more skewed left as our relative frequencies will drop to 19.6%,, 43 0.1% 27.5%,, 5.9 And 2% for the last two classes that we would have. So as you can see, this data is significantly more right. Skewed. This set of data with these smaller classes is a much more precise way of representing this data.


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