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StdOrder RunOrder PtTypeBlocksCutting DepSpindle SpeFeedrate Temperature rising 0.0oi 525 0.001 '778 0.00I 525 0.005 12.664 001 525 0.01 17.824 00[ 950 0.001 6...

Question

StdOrder RunOrder PtTypeBlocksCutting DepSpindle SpeFeedrate Temperature rising 0.0oi 525 0.001 '778 0.00I 525 0.005 12.664 001 525 0.01 17.824 00[ 950 0.001 6.006 0.001 950 0.005 14,07 (01 950 J01 23.505 I550 .001 8.078 0.001 1550 0.005 15.09 00i 1550 54,958 0u5 525 J0oi 9.248 0.0us 525 0.0us 12.242 005 525 33.003 (Os 950 J00| 8,176 (Os 950 .005 29,665 (Os 9S0 56,028 Oos ISS0 J001 21,66 00s I550 .005 22.106 Uus I550 0.uI 44.645 525 00i 12.12[ 525 .OOS 17.623 525 0.0I 47.457 950 001 17.262

StdOrder RunOrder PtType Blocks Cutting DepSpindle SpeFeedrate Temperature rising 0.0oi 525 0.001 '778 0.00I 525 0.005 12.664 001 525 0.01 17.824 00[ 950 0.001 6.006 0.001 950 0.005 14,07 (01 950 J01 23.505 I550 .001 8.078 0.001 1550 0.005 15.09 00i 1550 54,958 0u5 525 J0oi 9.248 0.0us 525 0.0us 12.242 005 525 33.003 (Os 950 J00| 8,176 (Os 950 .005 29,665 (Os 9S0 56,028 Oos ISS0 J001 21,66 00s I550 .005 22.106 Uus I550 0.uI 44.645 525 00i 12.12[ 525 .OOS 17.623 525 0.0I 47.457 950 001 17.262 950 0.005 14.328 950 0.0I 48.119 1550 001 22.749 1550 0.005 33.55 0.0I [550 0.01 53.486 1 E 20 13 N



Answers

The table gives the average temperature in Wallingford, Connecticut, for the first 10 days in March. (a) Over which intervals was the average temperature increasing? Decreasing? (b) Find a pair of consecutive intervals over which the average temperature was increasing at a decreasing rate. Find another pair of consecutive intervals over which the average temperature was increasing at an increasing rate. $$\begin{array}{c|c|c|c|c|c|c|c|c|c|c} \hline \text { Day } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline{ }^{\circ} \mathrm{F} & 42^{\circ} & 42^{\circ} & 34^{\circ} & 25^{\circ} & 22^{\circ} & 34^{\circ} & 38^{\circ} & 40^{\circ} & 49^{\circ} & 49^{\circ} \\ \hline \end{array}$$

We're given the table over here and were asked to find the left handed Riemann sums and the right hand agreement subs for it. So the left handed Raymond Sums is going to start at 12 and go all the way to nine o'clock to make a blur tingle. So elevate is we're going to start calculating that by finding the base and height and of each of these rectangles and mounting them together. So for a strict tingle, the base is going to be three, since we're looking at the with from 12 o'clock three o'clock on the X axis and on the Y axis or height is going to be 46 since we're looking at 12 o'clock as the starting point for a rectangle and the indicator of our height. Now for the next one, the base is gonna be three again. Since we're looking at three o'clock to six o'clock, the height is going to be 44 since three is are starting point of the rectangle and were, well, we're looking at F of X again. Our base is going to be three, as it is going to be for all of these are tingles And now our height is 52. Since we're looking, uh, f of six oclock again the basis three And now the height is 70. Since we look in nine oclock basis three heart is 82 since we're looking at 12 o'clock basis three heard is 86 as well. He had three o'clock basis three Harden's 80 as we're looking Ah, six o'clock the basis three the height is 72 as we're looking at nine o'clock So now if we add all this together we end up getting 15 96. So that is the answer for love tended Riemann Cem. Now, for the right handed one, we know that we're starting at three o'clock instead of 12 o'clock that the rectangles are gonna go from 12 to 3. But three clock is going to be our indicator of the hyper tingle. So again, for a first rectangle, the base will be three. But this time the height will be 44 for an extra on the basis three the highest 52 now the basis, three height This 70 bases three high is 82 basis three high ISS 86 business three high iss Really basis, three, highest 72 and basis three and height is 56. So now when we at all of these together, our answer is 16 26. So this stance serve our right handed agreements. Um, now we're asked why one of them is larger than the other and why the estimates are different instead of the same number. So in this case, as you can see from the graph I'm going to put, as you can see from this graph, this function is increasing more of the time than it's decreasing because it decreases over here, increases over here and then decreases again. But it's increasing for most of the function, And when a function is increasing more than it's decreasing, then the right handed Riemann some is going to be greater than the left hander driven some estimate. And this is because in increasing functions, right 100 Riemann sums always are greater than the left handed or even some X estimate. And since this function is increasing more of the time than it's decreasing, that's going to be the case here is low. So the reason the right handed Freeman sum is greater than the left hander dream in some is because of the way the graph is increasing more of the 10 than it's decreasing. So this is the answer for this problem.

In this question, we have to use technology to find the inverse of the Cuban metrics. The result given metrics. Now we will use metrics are general today in order to find the inverse of these metrics. So here is our tool, every type of given metrics. So we have type Hey metrics. Now we will enter formula here, which is in verse. No. They will present compute mhm. So this is a value of inverse. Thank you.

Mm. So from the given data we can find the incremental changing energy. So that's delta Q. Second column. And the incremental change in temperatures a tentative. So we plant delta Q and delta. So delta Q. On the Y axis delta T. On the X axis we get a straight line With this point show the slope of the straight line is 46.07. So from this lobe we're going to find the specific. All right, So using the slope, let's go the next part here. So we are given a mass of two kg. Okay, And we have the question for the change in here. Delta P equals mass times C times delta T. So she is the specific it and delta Q. Is on the Y axis. So let's replace it by Y and delta T. Is on the X axis. So let's replace it by X. So equation becomes Y equals M. C. Times delta X. And this also tells us the slope of the line should be the same as EMC because of the form of the equation. So we get slow because EMC and that's also equal to 46.07. What number that we got from the graph. Okay, So we re arrange cell for c. equals 46.07 over mass. That gives us uh to 30.4 kg per juice per kg Kelvin. Okay, so remember the math is given a 0.2 to the maps. So we compare with the table um 14.3. And we see that the specific heat of silver is 230 Jews package helping, so almost the same as what we calculated. So this metal is most likely silver.

Okay, so this time a temperature rises to T degrees Celsius, which means that the temperature rise can be written as T minus 10 degrees Celsius and says each degree decreases the gap by 0.37 millimeters. We can say that the decrease is equal to 0.37 times team on his 10 millimeters and then finally the width of the new gap will be equal to 16.8 degrees in six starts, 16.8 millimeters minus this distance. The decrease 0.37 times t minus 10 millimeters.


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