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A car is driving at a preserily unknown constant velocity while you are biking towards it at a constant speed 15.00 m/s relative to the stationary ground. Its speak...

Question

A car is driving at a preserily unknown constant velocity while you are biking towards it at a constant speed 15.00 m/s relative to the stationary ground. Its speakers are playing a favourite song of yours, Also sprach Zarathustra, which you know starts on a pitch of C ( 130.81 Hz) . However, you have perfect pitc and perceive the first note is f 145.23 Hz. You measure the sound to be 85.0 dB (decibels) , and the car is 20.00 m away from you_a) What is the speed of the car, and is it traveling t

A car is driving at a preserily unknown constant velocity while you are biking towards it at a constant speed 15.00 m/s relative to the stationary ground. Its speakers are playing a favourite song of yours, Also sprach Zarathustra, which you know starts on a pitch of C ( 130.81 Hz) . However, you have perfect pitc and perceive the first note is f 145.23 Hz. You measure the sound to be 85.0 dB (decibels) , and the car is 20.00 m away from you_ a) What is the speed of the car, and is it traveling towards you or away from you? b) What is the sound intensity, !, at your location? c) What is the power of the sound waves emitted from the speaker? Assume spherical sound waves and 208 C.



Answers

A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is standing nearby on the sidewalk but cannot hear the sound because the frequency is too high. When the car is moving, however, this person can hear the sound. (a) Is the car moving toward or away from the person? Why? (b) If the speed of sound is 343 m/s, what is the minimum speed of the moving car?

Solving party first taking east as positive direction, taking each test positive direction the value city off sound Web related toe you is given by velocity off sound minus your velocity. This is the formula. So I just put the value which are given in the question So this is our answer. So we can say that is speed off sound wave related to you I am just taking the magnitude three pipe 5 m per second, not solving part B. The time is given by this formula, so I just would devalue. So the wavelength off huge development off your location is given by speed off sound in air plus speed off police card in tow time. So I am just putting both the values here. So I get this value as answered. No solving party. The frequency detected by you is given by the pregnancy detected by you is given by the speed of sound wave related toe You buy, we land off, we blend at your location. So I'm just putting both the values here. These are the value and on solving. We get this as our final and

In this problem on the topic off waves and sound we're told that a car is parked given distance directly south of a railroad crossing. There is a train approaching the crossing directly from the west, headed directly east at a given speed. He trained them sounds its horn which has a given frequency when it reaches 20 m west of the crossing. We want to know the frequency that the car's driver cars drive over here when the horn blast reaches the car where given the speed of sound. And we have to assume that the only component of the trains velocity that is directed towards the car will affect the frequency heard by the driver. Now if the train were they headed directly towards the car, the frequency observed Oh would be given by Fo is equal to F s over one minus V Train of V where s the frequency of the source? The speed of sound and the train the speed of the train. However, the driver is 20 m south of the crossing and the train is 20 m where 20 m west of the crossing now the train would have to be here directly southeast in order to be moving directly towards the cards. Instant. So to calculate the Doppler shift in frequency of the horn, we have to only consider the southeast component off the trans Velocity V s E. Where the train velocity is being trained. Now, according to the drawing, we have done the scale a component of the S E off the trains, velocity is given as follows. So the component of the trains velocity to the southeast with cais park, the S E is equal to the speed of the train The chain times the call sign of 45 degrees this by trigonometry. So the observed frequency by the driver in the stationary car is equal to the frequency off the trains on F s into one over one minus the speed off the source The speed of the train towards the southeast, over the speed of sound V. So we can write this as the frequency off the sauce, which is the frequency off the train for the whole of the train s into one over one, minus the speed off the train. More times the co sign of 45 degrees. So we replace VSC Bye. the train co sign 45 degrees divided by the speed of sound V. Now all of these values are known so we can calculate the the frequency that the driver in the parked car will observe. So the frequency of the sauce is 289 huts and this is into one over one minus. The speed of the train is 55 m per second and multiplied by the coastline of 45 degrees, gives us the component towards the vodka divided by the speed of sound 343 m per second. So if we calculators, we get the frequency observed by hot car to be 326 cuts, yeah.

This problem give us the concept of the Doppler effect. From the Doppler fact, the frequency observed by the car equals the frequency emitted by the train. Into the speed of the sound upon the spirit of the sound, minus the speed of the source or the spirit of the train. With respect to I'm sorry, along the card. Well Let's substitute the value. So the frequency hard equal the frequency emitted is 289 heart, which into The frequency the speed of the sound that is 343 m/s Upon 343 m/s The speed of the train. That is 55 Middlesbrough second and its component along this line. So cost theater. And since uh, This distance is 20 m And this distance is also 20 m so we can see the angle theta is 45 degree. Therefore, because of 45 degrees. And by calculating we find the frequency absorb this 326 her church.

Mm. And this problem, we are going to find the speed of the car. That is you. By applying the Dublin's fact for the case where the source is approaching to the observer, we can wait here. Prime is equals to be divided by we minus you into F the subprime is the frequency received by the observer after the frequency emitted by the observed by the source. And this was the speed of the sound. This question can be written as a if prime divided by f is equal to we divided by D minus. You are the scum. Britain as f divided by a prime is equals two we minus you divided by we. So from here we can write this equation as f divided by a prime is equal to one minus u divided by week. Now we can write this question for you as you is equal to one minus f divided by prime into we we call it the question number one that's put the values into the square in. So it will be you into one minus, uh f, which is equals to 499 herds divided by prime, which is equals 2, 520 three herds into V, which is equal to 343 m per second. So from here, we can ride the value for this. You, as you as equals two 19.0 m per second. So the car spirit is a 19 m person. Good. Thank you. Yeah.


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