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Find the area under the slandard normal curve that lies betwcen Eci and z = 23. 0.8536 0.1464 8 0.4893 0.5107...

Question

Find the area under the slandard normal curve that lies betwcen Eci and z = 23. 0.8536 0.1464 8 0.4893 0.5107

Find the area under the slandard normal curve that lies betwcen Eci and z = 23. 0.8536 0.1464 8 0.4893 0.5107



Answers

Find the indicated area under the standard normal curve. If convenient, use technology to find the area. Between $z=0$ and $z=2.86$

This time I want the area to the left off minus 2.575 The area to the left, off the area to the left. Off my last 2.5 75 Okay, this is the area that I want. This is nothing but the P value for minus two. Sorry. Yeah. The value for minus 2.575 Let me use a calculator for this. I get minus 2.575 on this P value turns out to be 0.5 This area or people who turns out to be 0.5 This is my answer.

I want to find the area between minus 2.33 and 2.33 that is equal to minus 2.33 and that is equal to 2.33 We are going to do this in a similar way as to what we did in the previous question. This is going to be 0.5 minus the area to the right off 2.33 So what is the P value for 2.33? Let's use a calculator to find the P value for 2.33 which turns out to the 0.0 nine or I can write. This is 0.1 This is 0101 approximately 0.1 Now, this is going to be this area, this shaded region. And since it is symmetrical, the normal solution is symmetrical. This reason will be equal to this reason. So I have this Multiply this by two and this I get as zero point 49 multiplied by two. Or this I get a 0.98 This is my answer

Now. This time I want the idea to the right off. Dead is equal to minus 0.355 So over here somewhere, over here somewhere I have minus 0.355 and to the right means I want this entire area. So what can I do is I know the total area is one. So I will do one minus this area that is to the left. And this is nothing with a P value and the value for minus 0.355 minus. Ditto, 0.355 is people zero point 3612013612 0, 00.3612 And this actually turns out to be 0.6388 And this is my answer.

We were asked to find the area to the left of the values that equals 2.13 To do this, we use our sand table recalling that does that table shows the area to the left of the set Score. First we scroll down and we find 2.1, and then we line up with the column that corresponds with 2.13 So this column. So when we line up these two, we get 0.98341


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