We are going to be combining mixtures. Okay, so we'll start off with two different kinds of solutions of sodium hydroxide. Okay, so feel a stopped their concentrations involved. The first one has 0.17 moles And the second one is slightly higher at .4. Okay Then their volumes. 0.42 L with the other at 0.0 376 leaders. Now we can do the calculation of most is nope concentration times volume to figure out their malls And we will get zero 0071 for moles. And then this one would be 0.015 mi. Okay, so where you know the concentration of sodium will be equal to the concentration of hydroxide of it. And they're combining basically that we're combining the same Calyon and and I on. So well we have to do to get this constitution is trying to the total moles and we can do that by adding these two moles here. And that gives us 0.02-14 moles than to find the volume total concentration is for the total volume used and we'll add this second round here. What we get is 0.796 leaders. Okay. So then if we do that calculation, the final moles concentration of sodium and hydroxide Are equivalent and are 0.0278 multiple later. Yeah, that was just the first example. Next is a slightly bit more involved. Okay, so we'll take sodium sulfate with some salt, potassium. Quite okay. And if we mix come together, what will we do? Yes let's first. Right. Um Are givens. Okay, so here are the concentrations given followed by their volumes. Because up we converted that to leaders because that's actually what's most useful actually sort of this were over a bit to give us some room king. Now we need to calculate the malls simply by multiplying what's above. What we get is 0.0044 moles, sodium sulfate and 0.00375 moles of the potassium chlorate. Okay. Now for going to find concentration of the ions in this solution, we need the proper volume of this solution by adding a second role as we did above. And that gives us 0.069 leaders. Okay, so let's start off by isolating these concentrations. Okay, so we know that the concentration of potassium would be equivalent to that of the chloride. Okay. And we'll just take this these molds here and divided by the volume. Get the total volume like this. And what were ended up with a zero 05 43 moles per liter. Okay then that's going to be concentration for potassium and for the chloride as well. So following for the concentration of the sulfate, we'll take malls of the sulfate invited by The total. Okay, you get above in that will yield of 0.0 0.0637. That's per liter. Then the malls of Sudan will be double that. I think the final problem that we're going through, it's going to be an interesting one. We're going to take potassium chloride and mix it with some calcium chloride. So here we're going to have some additive additive properties as we saw in the very first example. So here, since we were given maths of 3.6 g, we're going to need to remember the molar mass. Okay. Which is that over there? 74 g per mole. Okay. And the malls will simply be mass over molar mass To give the serpent 0483 the walls of this salt. Okay, So then for the calcium chloride We had zero 24 We're sorry to five multiple causing quiet. Okay, so the only volume we had which will call vine total because here we just got a dry mass of the first cop out Will be 0.075 leaders. And the moles then will be fi multiple. What's above your europe 1875. All right. But actually moles of calcium chloride doesn't change. So we can use this to find the malls of the calcium. It will also be the exact same thing here because this one is actually not deluded at all because we're not adding any volume for the rest. We will need to do some work here. All right. So, if we try to calculate concentration of the potassium I am. What we need to do is take this smalls over here here .0483 And divide that by the total volume, which was 0.075 leaders. Okay. And what that gives us is you're 26 44 knows. Okay. So now for the calcium is going to be completely different case when we got in blue. So most of calcium will be the component from the hook passing for it As well as double the component from the calcium cord. Since it's going to associate into two and my arms. Okay. So if we do that addition, What we end up getting is zero 0858 months. Hey, So we would have added it that way and then malls of chloride will be you know that and the concentration Will be most over the total volume to lead 1.1 for four months. The leader. So that was tricky part. There was a need to remember that the chloride ion is coming from both components.