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Find the norm of the partition P = {0.60.9 1.5 18 3.2 3.7}IPI(Type an integer or a decimal )...

Question

Find the norm of the partition P = {0.60.9 1.5 18 3.2 3.7}IPI(Type an integer or a decimal )

Find the norm of the partition P = {0.60.9 1.5 18 3.2 3.7} IPI (Type an integer or a decimal )



Answers

Find the norm of the partition $P=\{0,1.2,1.5,2.3,2.6,3\}$

It in this problem, we are given a partition, which we call p, and we have to find the norm of this partition. Now, if you don't know what a partition is, I would probably look up that definition. Um, if you're learning this and calculus, um, you'll learn about partitions later on in future math classes when you talk about sets. But for this problem were given a partition p of the set that contains 1.21 point 52.32 point six and three and we need the norm of this partition. So essentially what we're doing right now is we're going to be, um, finding the width of sub intervals and they should look like something You're learning an integral calculus where you're finding the sub intervals like in a rhyme and some. And that's essentially what we're doing here. We'll take 1.2 minus zero to get 1.2 1.5 minus 1.2 to get 0.3 2.3, minus 1.5 to get 0.8 2.6, minus 2.3 to get 0.3 and finally three minus 2.6 to get 0.4 so you can see where I got these numbers. I'm just fund the difference between the various components of our partition. P So what we conceive from these calculations calculations? Pardon me? Is that the norm of our partition? P is 1.2. So I hope that this problem helped you understand how we can find the norm of a partition, Given what we know right now about norms and partitions, and you'll be learning more about both of these concepts in future math classes if you decide to take them.

Hello. We are doing a partition as a sort of points month to minus 1.6 Martin, verify zero. Your point on one. And we need to find the norm off peak, that is. This is so what is the room of P? This is a subdivision off the interval from minus 2 to 1, in which in which, uh, we had minus two than the first and interval. Is that minus 1.6? The next one is at minus 0.5. The next one is a zero. The excellent 0.8 on the left one is that one. Okay, so what is the norm? Oh, this taken to be eggs. Eero X. Well x two x three x for eggs. Five, where we take exert to be a the left endpoint of the original interval expired. Be the right in point of the original intrude. The norm of P is the length, uh, length off the longest. Something terrible. All right, So the first suburbs where we have is from minus two to ah Marner, 1.6 lengths off the first sub interval from egg zero to x Well is the minus 1.6, uh, Amarnath money to which is plus 0.4. What is the length of the second of interval From minus 1.6 to 0.5. So x 261 is, uh, 0.5 minus minus 1.6, which is 1.1 the width of this intervals. One point. Well, then we have x three months, six to the with free zero this central here from zero Monets minus five, which is the next interval of 63 X four months, 63 from here to here, which is we conceive it, they and last interval from 1.81 and, uh, no point. So we see that the largest the interview with the largest with is way 1.1 on that is the norm off the part. Then through one more important there. I hope it will, but

To pokes me in the area with the information given you're going to calculate 34.25 times one minus zero is not this the area of this first rectangle that's the height of the rectangle. The base is one minus zero or one. You'll answer that 20 which is the height of your next train. Wow rectangle. And the base of that rectangle is 2.5 minus one. Add to that eight times 3.2 minus 2.5. These are just the basis of those rectangles. And then we have one more rectangle high 15 so we'll add 15 times five minutes, 3.2. And once you do that in just type in chav calculator, you will end up with 96.85 as your approximate area under the curve.

So for this problem were given the function and we're told that we're looking at the interval are 0.1 for X It's going to be 0 to 1.5 for why it's going to be 0.5 to 2. The first thing I want to dio as I want to calculate my delta x delta y So my Delta X is going to be my interval. So 1.5 minus zero. And if we look at the table, it goes up in increments off three amongst that interval. So if we go back and look at our ex, we have zero to 1.5, which means on this table I don't need the two values. So I'm gonna go ahead and scribble these out. So then, if I go down toe, why, Actually, this will be 0.5. So then the same thing with Delta why I'm going from They covered it up, going from 22.5 and dividing by three. And this is also going to be 30.5. Um, because if we go up here there, even though there's four of these, we don't need the zero. So this one we can actually scribble out. And so now we have, what, 16 values that we're going to take a look at. So what I want to do is I want to look at as to be my delta x times, my delta y and then I want to take the sum of all of the values in the table for this Epsilon. This biggie is a some. Okay, So if I go back up to this table and I were toe add up, all of these, I would get 25.37 so I'm gonna have 0.5 times 0.5 times 25. We put parentheses instead. 25.37 As a result, I get six point 34


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