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CENC-C (arom )Question 208 ptsWhich peak in mass spectrometry is important when determining the presence of a chlorine atom?M+ peakM + 2 peakbase peakpareni peakQue...

Question

CENC-C (arom )Question 208 ptsWhich peak in mass spectrometry is important when determining the presence of a chlorine atom?M+ peakM + 2 peakbase peakpareni peakQuestlon 21pta

CEN C-C (arom ) Question 20 8 pts Which peak in mass spectrometry is important when determining the presence of a chlorine atom? M+ peak M + 2 peak base peak pareni peak Questlon 21 pta



Answers

In using a mass spectrometer, a chemist sees a peak at a mass of 30.0106 . Of the choices $^{12} \mathrm{C}_{2}^{1} \mathrm{H}_{6},^{12} \mathrm{C}^{1} \mathrm{H}_{2}^{16} \mathrm{O},$ and $^{14} \mathrm{N}^{16} \mathrm{O}$ which is responsible for this peak? Pertinent masses are $^{1} \mathrm{H}$ $1.007825 ; 16 \mathrm{O}, 15.994915 ;$ and $^{14} \mathrm{N}, 14.003074$

Good day in this question, we are given three compounds with a composition of carbon, hydrogen, oxygen and nitrogen. And we are also given the pertinent masses of hydrogen, oxygen and nitrogen. So I must spectrometry is a device that you use that measures the must of the compounds. So we will check Which of these compounds gave the big mass of 30.0106. Assure me the mass the president mass of carbon is 12. So we try to see to age 66. So based in this compound we can see the tide rogen is 66. So definitely it is not there. He is a it exceeds 30. So for the next is see age too. Oh So show me carbon is 12 and the pertinent mass of hydrogen Is 1.007825. People deployed. If I do since you have to hire regions here Last a pertinent mass of oxygen is 15.99 4915. This will give us an answer of 310106 and this compound is the exact compound that gave them beat must. But let's try also to check the last compound given so. And oh The pertinent mass of night urgent is 14.003074 Plus. The oxygen is 15.99 4915 Total of 29.9980. It's close to 30.016 that we have obtained The exact amount of 30.016 in the compound of CH two. Therefore Our answer is the CH20. Thank you.

In this problem. We have a peek from a mass spectrometer at 30.10 of six. Um, and we have three choices of compounds that could have been used in the mass spectrometer. Madonna. Figure out which one, um, is most likely responsible for this peak and were given the specific masses for hydrogen oxygen and nitrogen. Um, so we have three options. The 1st 1 is, uh, C h six, worth carbon 12 and hydrogen one. So we're gonna have 12.1 plus six times the 1.0 78 to 5, which gives us a value of 30 point 06695 Next one is C H 20 Whenever you have 12.1 plus two times 1.0 78 to 5 plus 15.994915 And that gives us a value of 30 point 020 five, 65 And then finally, we have the option of N O, which will be 14 point seriously there. 3074 plus our 15.99 4915 for a total of 29.99798 So when trying to figure out which one makes the most sense weaken knockoff be and know because it's too low, Um, and then we'll also want to knock off the CH six because that is a lot higher than our point. 01 So are correct. Answer here is going to be the C H 20 because it is the closest value to the peak of the next mass spectrometer.

So in this podcast were just predicting relative intensity values for the molecular. I am peak, the M plus to peak and the M Plus four peak, So the information that were provided with is that it contains two bromine atoms. So for a molecule that contains to bromine atoms, two peaks will be produced. So for the AM peak, there is only one way. Both br molecules must be the 79 isotope for M plus two. We have to arrangements. Three. The fast br is 81 the second is 89 isotope, or we have the reverse order M plus. For again. There is only one way to arrange this. Both BR molecules must be the 81 isotope to the ratio between the peaks is wanted 2 to 1. So here's a common spectrum. Why you would have the master charge ratio against the abundance on this just shows is all ratio of 1 to 2 to want

So here we're looking at on my spectrum for to me file plantain It's C six h 14. I'm just drawn out a rough sketch for a reference here. And so fastly we're looking at the first peak that represents and plus on our must. Here is about 86. So our final peak on our spectrum represents. And plus Secondly, we're looking for the base peak where our base people have a mass of about 43. Next, we're looking at fragments. So we have masses of 71 57 43 on 29 on they have the molecular formula off C five, h 11 plus C four h nine plus C 3 87 plus and C two h five plus, respectively. So lastly, we're just looking at Why does the base peak have the mass that it does? And so the base peak is a peak that the carb catalon with the molecular weight of 43 as this is the most stable Kabul cart on and off fragmentation process


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