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Magnetic Fiell Excrcisc: Magnctic force livc conductor: For thc following current Joop find and evaluate ,Mfl= 400m4, 1-Ocol,6.0T' 2nd. It 15 to theVcctors for...

Question

Magnetic Fiell Excrcisc: Magnctic force livc conductor: For thc following current Joop find and evaluate ,Mfl= 400m4, 1-Ocol,6.0T' 2nd. It 15 to theVcctors forcc litrral foitt , tagnitude and direction 0n e1ch slde of the spiral drzw the forces_Torquc the coLL litcrally Thc sprral magnctic dipole moment mazmltudc and durcction ltcrallyEvaluatc thc numerical valucs fozces; Jofqwemignetc Cipole moment

Magnetic Fiell Excrcisc: Magnctic force livc conductor: For thc following current Joop find and evaluate , Mfl= 400m4, 1- Ocol, 6.0T' 2nd. It 15 to the Vcctors forcc litrral foitt , tagnitude and direction 0n e1ch slde of the spiral drzw the forces_ Torquc the coLL litcrally Thc sprral magnctic dipole moment mazmltudc and durcction ltcrally Evaluatc thc numerical valucs fozces; Jofqwe mignetc Cipole moment



Answers

The L-shaped conductor in AGURE CP34.83 moves at 10 m/s across a stationary L-shaped conductor in a $0.10 \mathrm{T}$ magnetic field. The two vertices overlap, so that the enclosed area is zero, at $t=0 \mathrm{s}$. The conductor has a resistance of 0.010 ohms per $r$ meter. a. What is the direction of the induced current? b. Find expressions for the induced emf and the induced current as functions of time. c. Evaluate $\mathcal{E}$ and $I$ at $t=0.10 \mathrm{s}$

Head. First of all, we're going to draw the diagram which is given. So this is the diagram like this one, this is the same circular type of thing. Okay. And current following through them. Is I Okay so this is like uh this is like uh this one and this one okay current going like this one and going like this one okay that that can't happen to die. Okay. And okay so similarly simply will follow from this. So this is I. And what more what more influence and this is Erdogan. And are you okay? So this age, this radius age Internal Radio City are one and the other correctional agencies are too right. Are we like? Yeah so basically we're to find the center of the moment. You feel at the center see okay so we know that due to the small circle this this part the moment if you do this one will be inside and order will be outside to do this one, this will be inside and this will this one be outside. So let's stay inside its project. Okay. So the moment it will be natives even do nothing but you know I upon and do this the small person of where when we do because they are passing through center and we know that well, which is passing through any point will dramatically due to that while at that point when we do, you know, I want to our to our means to our one into alpha, alpha, which is what the angle that is making on that, there is pi upon two pipes that wins 1.2. So that is we were upon four R one and minus because we are taking inside politics also negative, you know, I upon what are too, So this will be the main field in this case. Okay.

Hello students in this question we have raised conducting wire which is bent as shown shape and it is released to fall freely through height edge. Okay so we have to calculate the E. M. F. Induced between point A. And C. So when it is it has followed the height edge. The velocity will be given by under root of the tooth. G. H. Okay. And the distance between terminal A. And C. That is hell effective Will be given by early square plus Ellis Square. And this understood because both are at the 90 Angle so this is equal to undergo to help. So E. M. F. Can be written as be more popular baby. Molecular be effective length between terminal A. And C. Okay. So be manipulated baby which is on the route of two G. Edge and L. Effective. Which is on the route to help. Mhm. So I am from here will be equals two B. L. And a new route of G. H. Okay, so this becomes answer of this problem. So from the given options option C is answer here. Okay thank you.

Given the length of the road is 25 centimeter. Resistance given is 2.5 or ah, speed of the road is 1.3 m per second and strength of the magnetic field. Is there a 0.35? That's long. No, For the second one that induced EMF is e his B l b. We have these 3.35 Tesla l is 25 centimeter. There is 25 to 10 to the power 10 people minus two and we is 1.3. So in Tuesday MF 0.11375 voice Now the registrants are one after U shaped Rod is 25 homes plus 2.5 home 27.5 on Now the induced current I is e upon our one. So he is 0.11375 balls and are one is 27 point five or so Induced current is, um 0.413 and fear no, they the external current needed to keep the roads velocity constant at that instant of time is ethical to be square elsewhere upon our B That is I l b. So I e 0.413 at least 25 into 10 to depart minus two and B s 20.35 30 30 six into 10 to depart minus five Newton.

All right. So we need to calculate the magnetic field strength, which is h um, the magnetism nation off the object is 0.88 times 10 to the sixth amps per meter. That is M. And the magnetic field is 440 Tesla's, um, for this object, um, using the magnetic field strength and the magnets ization of the object. When we add those together and multiplied by mu zero, we will get the magnetic field caused by are the magnetic field of the object eso We have that in Tesla's. So that's good. So we will divide by mu zero, which is the four pi times 10 to the negative seven. Um, And then we will subtract, Get rid of that will sign. There we go. I want to subtract that divided by that. Then we're going to subtract, um the, um and that should give us the H value the 0.8 times 10 to the sixth. Okay, so then when I do that, I get on H value of 2.62 times 10 to the six current divided by amps divided by meters. It would be the same units as the magnetism ation the field strength would be because we're adding those together, so it is a current per length there that is causing the magnetic field.


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