Question
ACTRESSES 22 37 28 63 32 26 31 27 27 28 30 26 29 24 38 25 29 41 30 35 35 33 29 38 54ACTORS 24 41 28 35 33 3 %; 1 40 50 39 38 1 29 27 4 32 31 L 38 26 38 29 80 34 25 35 22 60 33 ; 43 35 35 45 39 39 34 1 1 26 25 1 33 35 G8 3540 42 36 76 39 55 36 62 1 52 38 8 46 40 36 47 291
ACTRESSES 22 37 28 63 32 26 31 27 27 28 30 26 29 24 38 25 29 41 30 35 35 33 29 38 54 ACTORS 24 41 28 35 33 3 %; 1 40 50 39 38 1 29 27 4 32 31 L 38 26 38 29 80 34 25 35 22 60 33 ; 43 35 35 45 39 39 34 1 1 26 25 1 33 35 G8 35 40 42 36 76 39 55 36 62 1 52 38 8 46 40 36 47 29 1


Answers
Listed are 32 ages for Academy Award winning best actors in order from smallest to largest.
18; 18; 21; 22; 25; 26; 27; 29; 30; 31; 31; 33; 36; 37; 37; 41; 42; 47; 52; 55; 57; 58; 62; 64; 67; 69; 71; 72; 73; 74; 76; 77
a. Find the percentile of 37.
b. Find the percentile of 72.
So, um, were given 32 ages for the Academy Award winning best actors from the smallest to largest age, and we want to find the percentile of 37 year olds. So to do this, we go through and count how many of them are 37. And since it's an order, it's fairly easy. We see that there are 2 37 year olds, and then we divide this by the 32 um, people that there are. But we have to make sure that there's actually 32 people and not just 32 ages. So if we count, we see there are 1234 56789 10, 11, 12, 13, 14, 15, 16, 18 1920 21 22 23 24 25 26 27 28 29 30 31 32. Yeah, so they give us 32 and we have Uh huh, 37 37. So that's two out of 32 and then the percentile of 72. We see that there's only 1 72 year old, so that's one divided by the 32 people, and those will give you your answers
Okay what we're gonna do is walk through on being able to share one to do when given a percentile to determine that value that is on that percentile. So we have a list of numbers um I guess they represent ages of people. Um And one of the things you need to remember is that when you're working with percentiles also finding medians and so forth is to always have your data listed in order. Um An increasing order. So that's the first thing if it's not already listed in order to go ahead and listed in increasing order. And so now what we want to do is we want to determine um the Age that is the 40th percentile. Okay so these are 123 I think we have 25 numbers maybe um were 29 8 25. 1 8910 12 1314. Yeah 2 23 24 25 26 27 28 29. So these are 29 numbers. So we have a total of 29 numbers. So what I needed to do in order to find um that value is I take point four And multiply it by 29. And so when I do that we should get 11.6. So since this is not a whole number, we always round up. So this is the 12th. So the 40th percentile number is going to be that 12th number in this series. So 123456789 10, 11 12. So that would be 37 years of age. So the person that is on the 40th%ile is the person that has 37 years of age. Okay, so now we want to find the 78 percentile. So what we do is take the .78 multiply it by 29. So .78 times 29 gives us 22.62. So we round up you always round up. This will be 23rd position. So this would deserve 12 13 14 15 16 17 18 1920, 21, 22, 23. So that would be the person that is 69 years old. I hope this helped.
So we're going to be looking at frequency tables. And in these tables in these questions we're only going to be looking at the classes of the tables. So for this problem we're looking at verbal I. Q. Scores And our classes are going to be 50-59, 60-69, 70 to 79 82 89 90 99. 100 To 109. 110 To 119 And 120- 129. And so the first thing we want to look at is mrs that's good is the class with and the class with is found by taking the difference between subsequent lower class limits. So in this case It would be 60 -50 Which would give us 10 Or we could say 70 -60 was 10 and that's going to be the same for all of the classes. They're all going to have the same, right? That's gonna be important to us. So the next then we're asked to find are the class mid points and in order to find the midpoint. What we need to do is we need to take the average of the ends of the classes. So we have 50 plus 59 divided by two Is going to give us 54.5. If we look at 60 69 Divided by two that's going to give us 64 five. And if you notice the difference between these two is 10 IQ points. And so we can take advantage of recognizing that pattern And realizing that the next midpoint is going to be 74.5, 84.5. Thanks. 104.5 114.5 And 120. And you can do those calculations to check just to make sure that you've done it correctly. And so then we want to find the class boundaries and the class boundaries are the boundaries that give us classes with no gaps. So what we need to do is we need to take the average of the upper class limit of class below and take the average of that with the lower class limit of the class were interested in. So the first one is a little tricky because you're not given Class below, but we can assume that the upper limit of the class below would be 49. So we want 49 plus 50 divided by two. And that's going to give us 49.5. That's the lower limit Of our 1st class. And The next one then would be 59 Plus 60 divided by two. And that's going to give us 59.5 and that's the upper limit of our first class. And notice that these limits are 10 IQ points apart. And so we can take advantage again of that pattern. And the next limit will be 69.5 79.5 right, 99. Really? 109 fine. And 100 and 19. All right, And then the last one is going to be 129.
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