5

Use the Law of Cosines to solve the triangle: Round your answers to two decimal places. B = 29.01 C= 75.99 a = 39.82b = 2075c =40B...

Question

Use the Law of Cosines to solve the triangle: Round your answers to two decimal places. B = 29.01 C= 75.99 a = 39.82b = 2075c =40B

Use the Law of Cosines to solve the triangle: Round your answers to two decimal places. B = 29.01 C= 75.99 a = 39.82 b = 20 75 c =40 B



Answers

Using the Law of Cosines, use
the Law of Cosines to solve the triangle. Round your
answers to two decimal places.
$$
B=75^{\circ} 20^{\prime}, \quad a=6.2, \quad c=9.5
$$

In this question, we have to use the law for science. So the triangle and also given this and then be mhm. 75 degrees contaminates and two thousands are given a equals to nine and Sequels to six. How? By using low of course science we can right B squared equals two a square just a square minus. Who is he? Was a and B. Now we will substitute the values here. Nine square the six squared minus two multiplied by nine, multiplied by six multiplied by co sign 25 degrees contaminants on solving this bigger. The square close to 39.65 bees nine point Helen. Now again, we will use no for science. We'll find angle it. So you're saying it was too b squared the ski squared minus a squared divided by UBC. Now we will substitute the values here. 9.47 square, just six square, minus nine square, divided by two multiplied by 9.47 multiplied by six. Consulting. This figured it was to consign inverse 43.60. Be worried by 113.64 Louise, 67.39 Greece now we will find Anglesey by using No, of course. Science and the inconsistency. Equal school B squared this case where Mayakovsky Square divided by will be. Now we will substitute the values there. 9.47 square last nine square, minus six square Invited by it two multiplied by 9.47 multiplied by nine. Consulting this regard equals to prison in West, 133.6 days. Invited by 170 point or six. So she is 28 points. If I'm degrees. Thank you.

In this question. We have to use the local science, hold the triangle and we have to Long beyond. Yeah, Lebanese. A right speed was 25 equals 72. No buy low of course. Science. Prior to signing postal B squared C squared minus a square divided by to be See now we will substitute. Developed there 25 square. Yes, and two squared minus 55 square Divided vice to multiple. 25. Medical sounded I was holding this. Be good. It was to resign in verse. Beautiful 77 33 is 39 point people in Greece again, we will apply laws for science to find angle be design vehicles is where does the squared minus B squared, divided by Who is now with the security will develop there 55 Screen Best time to do square minus 25 square He waited by two multiplied by 55 particular advice them to do installed in this regard equals 2% in verse. 0.9575 languages 10.76 Please no, we will find time to speak again. We reduced love for science for science equals two square That's B squared minus key square divided by Maybe now we will Subsidy will be values here If I squared. That's 25 square. Yes, down to two square, divided by two multiplied by. Good thing my department. Right on solving piece. Be good. He closed signing books. My nose little 0.5578 So speed is 1. 23 0.90 degrees. Thank you.

Okay, so I've given that a is 75.4. B is 52.5 and C is 52.5. So, um, to find the measure of anglet by, um, using the law of co signs Law of Coastlines says that co sign of a is going to be equal to well be squared plus c squared minus a squared divided by two times b times c. So just plugging in our values here we have that co sign of a is equal to well, 52.5 squared, um, plus 52 points. Five squared minus 75.4 squared. That's gonna give us negative. 172.66 divided by two times b times C. So that's two times 52.5 times 52.5. That should give us a 5512 0.5. Okay, that's co sign of a what's, um a Well, A is just the angle. Whose co sign is this? So therefore, a is equal to the inverse cosine off well of this off. Negative. 1. 72.66 over. 5512.5. Okay, So using a calculator here by the inverse coastline of this, we get that, um, a is gonna be equal to or approximately equal to, um because in degrees, we get up approximately equal to 91 0.79 degrees. Okay, um then defend the measure of angle be well, pretty much the same method. Here we have the the co sign off be again is going to be equal to a squared plus C squared minus B squared all over. Two times eight times. See So again, a squared plus C squared minus B squared all over two times a time. See, So therefore co sign a beep is equal to Well, if we put in 75.4 squared plus 52.5 squared minus 52.5 squared, we should get 5680 5.16. That's all divided by two times 75.4 times. That could get you 0.5, which should be 7917. So if that's co signer B B is the angle whose co sign is this? So again, Therefore be is equal to while the inverse cosine um, the inverse cosine of off this off put era off that, um, which should give us 44.10 degrees. So we have that be is equal to 44.10 degrees. Okay. And likewise defined the measure of angle. See, So we have the co sign of C is equal to B squared, plus a squared minus C squared all over two times B times a. So, um, same method here, plugging in our values. We get that co sign off C is equal to, uh, 5685.16, all over 7917. So therefore, C is equal to the inverse coastline of that, which gives us 44.10 degrees. So what are our solutions? Well, a, we found was equal to 91.79 degrees. We found that be, um, was equal to 44 0.10 degrees. And we just found that C was also equal to 44.10 degrees. So, um, it was approximately, but so C is approximately equal to 44 0.10 degrees. Yeah, and then we have it. Take care. Yeah,

In discussion. We have to use the love for science to solve the triangle and also around the answer to the similar cases. Given his angle, be 10 degree, 35 minutes and to service had given a rose to 40 and the 1st 2 30. Now, by using love for science, we can die B squared equals to a square that C Square minus policy was kind. Now we will subsequently value there. 40 square that's 30 square minus two, multiplied by 40. My prepared by heartache. But the product design 10 degrees, 25 minutes for solving this figure, 139.5 to Side B is 11.87 Now. Again, we will use low, of course, science to find and early. We'll sign imposed, too D squared. Plus, he square minus a squared, divided by two busy. Now we will substitute the Volusia 11.87 square plus 30 square minus quote is square, divided by two multiplied by 11.87 multiplied by 40 in solving this weekend. Okay, close to co sign in with minus 0.5. Rated Ganguly's 141.141 degrees and 45 minute. Now we will find angle see by using the of course science. So called science equals two. A squared plus B squared minus the square divided by webby. Now we will substitute the balance here. 40 square plus 11.87 square, minus 30 square divided by it. Two multiplied by 11.87 multiplied by 40 On solving this video equals two we'll find and worse finest 0.62 So these 27 degrees 40 minutes. Thank you.


Similar Solved Questions

5 answers
Usepi in place of T when you state your answers. From the options below, circle the values/functions that represent the trigonometric graph provided. Radius/Amplitude35Period2T234Functiony =-3,5c0s (6x)y = 3.5coSy = 3.5cos(6x)y = 6cos(x) + 3.5"
Use pi in place of T when you state your answers. From the options below, circle the values/functions that represent the trigonometric graph provided. Radius/Amplitude 35 Period 2T 2 3 4 Function y =-3,5c0s (6x) y = 3.5coS y = 3.5cos(6x) y = 6cos(x) + 3.5 "...
5 answers
Gatou methane (CH;) reacts with Qaseous axygen cus (0 ) produce Dase0u5 carbon dioxloc (Co ) and gaseous water (1,0) I 5.65 of Neter $ produzed from the reaclion cl 3.66 methane end 124 g 0 axyqen g48 calculate the percent ylelu MatcrRound You anstesAonilicart 1 gures,
Gatou methane (CH;) reacts with Qaseous axygen cus (0 ) produce Dase0u5 carbon dioxloc (Co ) and gaseous water (1,0) I 5.65 of Neter $ produzed from the reaclion cl 3.66 methane end 124 g 0 axyqen g48 calculate the percent ylelu Matcr Round You anstes Aonilicart 1 gures,...
5 answers
One of the amino acids in Table $27.1$ is the biological precursor to $gamma$ -aminobutyric acid (4-aminobutanoic acid), which it forms by a decarboxylation reaction. Which amino acid is this?
One of the amino acids in Table $27.1$ is the biological precursor to $gamma$ -aminobutyric acid (4-aminobutanoic acid), which it forms by a decarboxylation reaction. Which amino acid is this?...
5 answers
Enter your answer in the provided box:What is the osmotic pressure (in atm) ofa 2.83 M aqueous solution of urea [(NHzhco ] at 27.s%c?atm
Enter your answer in the provided box: What is the osmotic pressure (in atm) ofa 2.83 M aqueous solution of urea [(NHzhco ] at 27.s%c? atm...
5 answers
H03?(HO)HJHOHoSCHo)ho{OOneuLOJSuEJ SuLMOIIO J41 YSIduo3Je 0} &sn nof PInOAt sla3ea1 QPI4M
H03?(HO)HJ HOHoSCHo)ho {OOneuLOJSuEJ SuLMOIIO J41 YSIduo3Je 0} &sn nof PInOAt sla3ea1 QPI4M...
5 answers
An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. (a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of6000 cars. (b) The Poisson distribution can be used to approximate the binomial distribution for large values of $n$ and small values of $p .$ Repeat part (a) using a Poisson distribution and compare the results.
An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. (a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 6000 cars. (b) The Poisson distribution can be used to approximate the bin...
1 answers
A circular wire loop of radius 15.0 $\mathrm{cm}$ carries a current of 2.60 $\mathrm{A}$ . It is placed so that the normal to its plane makes an angle of $41.0^{\circ}$ with a uniform magnetic field of magnitude 12.0 $\mathrm{T}$ (a) Calculate the magnitude of the magnetic dipole moment of the loop. (b) What is the magnitude of the torque acting on the loop?
A circular wire loop of radius 15.0 $\mathrm{cm}$ carries a current of 2.60 $\mathrm{A}$ . It is placed so that the normal to its plane makes an angle of $41.0^{\circ}$ with a uniform magnetic field of magnitude 12.0 $\mathrm{T}$ (a) Calculate the magnitude of the magnetic dipole moment of the loo...
5 answers
Constants Perodic TableIn the figure, long straight wire carries current out of the page toward the vlewer (Figure 1)Part AIndicate , with appropriate arrows the direction of B at each the points Cand E in the plane ol the page _FiqureNo elements selected1of 1PE
Constants Perodic Table In the figure, long straight wire carries current out of the page toward the vlewer (Figure 1) Part A Indicate , with appropriate arrows the direction of B at each the points C and E in the plane ol the page _ Fiqure No elements selected 1of 1 PE...
5 answers
How many significant figures will the answer have in thefollowing question?"Calculate the freezing point of a solution containing 9.0 gramsof KCl and 381.0 grams of water. Themolal-freezing-point-depression constant (Kf) for water is1.86°C/m."
How many significant figures will the answer have in the following question? "Calculate the freezing point of a solution containing 9.0 grams of KCl and 381.0 grams of water. The molal-freezing-point-depression constant (Kf) for water is 1.86°C/m."...
5 answers
2. (a) It tor the reaction in Equation (1), NH; (g} 1 Cr-(g) 22 NH Cllaq) (Eq. 1) we tind that LA = 159.3 kcal mol-' find 4H for the reaction in Equation (21:NH.Cl(s)NH; Ig) t Cr(g).(Eq: 21
2. (a) It tor the reaction in Equation (1), NH; (g} 1 Cr-(g) 22 NH Cllaq) (Eq. 1) we tind that LA = 159.3 kcal mol-' find 4H for the reaction in Equation (21: NH.Cl(s) NH; Ig) t Cr(g). (Eq: 21...
5 answers
Given: BANK is an isosceles trapezoid. D, I, M and E are the respective midpoints of [AB], [AN]; [NK] and [BK]DShow that: DIME is a rhombus.M
Given: BANK is an isosceles trapezoid. D, I, M and E are the respective midpoints of [AB], [AN]; [NK] and [BK] D Show that: DIME is a rhombus. M...
4 answers
How much mass (in grams) ofaluminum initiallyat150 Cmust be added to 3o0 g ofwater initially atzo.0 "Cto makethe final equilibrium temperature 77*C? specific E heat ofaluminum = 0.215 callg K and specific heat ofwater =1callg K (from Table19.3 ofthe book)Answer:Previous pageNexi pageD ADALL
How much mass (in grams) ofaluminum initiallyat150 Cmust be added to 3o0 g ofwater initially atzo.0 "Cto makethe final equilibrium temperature 77*C? specific E heat ofaluminum = 0.215 callg K and specific heat ofwater =1callg K (from Table19.3 ofthe book) Answer: Previous page Nexi page D A DA...

-- 0.025669--