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A bag contains six red marbles and seven white marbles_ If a sample of four marbles contains at least one white marble, what is the probability that all the marbles...

Question

A bag contains six red marbles and seven white marbles_ If a sample of four marbles contains at least one white marble, what is the probability that all the marbles in the sample are white?The probability that all the marbles in a sample of four marbles are white given that at least one of the marbles is white is (Round to four decimal places as needed )

A bag contains six red marbles and seven white marbles_ If a sample of four marbles contains at least one white marble, what is the probability that all the marbles in the sample are white? The probability that all the marbles in a sample of four marbles are white given that at least one of the marbles is white is (Round to four decimal places as needed )



Answers

Five marbles are selected at random from a bag of seven white and six red marbles. Find the probability of each event.
Three are white and two are red.

In this problem we have seven white chips, six Red ships and will choose five of them at random. The question is, what's the probability of getting two white and three green? Well here we see that it's impossible to choose the green because there is no green chips in the urn to begin with. If you want, you can write 0G. Here, so that will be zero and the numerator, the denominator, 13 Chips and You're Choosing five. But regardless of the denominator, um it's a non zero number, the numerator zero, so your final answer will be zero.

And this problem you have seven white marbles, six red marbles all in the bag, and we'll choose five. And then the question is, what's the probability that all five our weight. There's two main ways to do this. You could You this is five individual choices without replacement. Or the way we'll proceed here is we'll just choose all five at the same time. Now if we look in the numerator We have seven white and we want to see How many ways we could choose five. But in our denominator We have 13 marbles total And that's the number of to waste to choose five. So again, the numerator is the number of Success is this is the number of ways to choose five of the seven whites, whereas the denominators The total number of ways to choose five from the entire jar. So at this point you can just go ahead and go to a calculator and crunch these out.

In this problem, we have to find the probability off selecting a red marble or yellow marble from a jar containing some colored marbles. Yeah. Uh, 16 marbles, didn't he? Just Gaza. Seven. Lumumba's this price. Redmond boots less four green marbles That this the same press Space press 60 Really makes bidder Feist Red. Marvelous. Spread your gloom on Chris. So the probability of selecting is like mom, but only yellow marble. Mrs. G rep says number off. Read my bus. Less number off yellow. Marber's you write it by number of any banks. Every cent fronts base. We have bacon numbers, red mambas, less number of yellow marbles. As we have to find the probability of selecting exact Marva are a yellow marble. So this is it. Quite do fries? Yes. Seven. We brigade by 16 re Chrissy would do right. We writing by 16. So Mississippi, quite to G Be right, baby Breath. Full break. This probability of selecting a red marble or yellow Marvan is three divided by thought, which is over required probability

We have a number off Yellow marbles in jar is equal to seven and number of red marbles in jar is equal to three. And the number off green marbles in Czar is equal to six and the total number of marbles is equal to 16. So we need to find the probe. Lt off selecting or red marble. So the probability off selecting that marble is equal to a number of Fred Marbles upon number off total marbles. So the probability is equal to three upon 16 4 Selecting a red marble, this is


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