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What volume of 02(g) at 840. mmHg pressure rcquircd Tczcu completely with SOg xmple of C(s) a 7535C? (Jsf) 2C(9) = 02(g) co(g)...

Question

What volume of 02(g) at 840. mmHg pressure rcquircd Tczcu completely with SOg xmple of C(s) a 7535C? (Jsf) 2C(9) = 02(g) co(g)

What volume of 02(g) at 840. mmHg pressure rcquircd Tczcu completely with SOg xmple of C(s) a 7535C? (Jsf) 2C(9) = 02(g) co(g)



Answers

A mole of gas at $0^{\circ} \mathrm{C}$ and $760 \mathrm{mmHg}$ occupies $22.41 \mathrm{~L}$. What is the volume at $20^{\circ} \mathrm{C}$ and $760 \mathrm{mmHg}$ ?

Okay, so we will be using that I don't. Gasol PV equals in our tea Pressure is what we're trying to find. We know the volume 12.8 leaders to find number animals were going to do grams that it gave us, which is 35.8 grams of 02 looking divided by its natural gas, which is 32 clams for more go to now for our which is the constant it is 0.8 to 1 leaders times a team over mold tons, Kelvin. So they gave us a temperature in 46 degrees Celsius. So Dio 46 plus 2 73 you're going to get 319 Kelvin, which is the unit that we need. So once we plug all this in, we're going to get pressure equals 2.29 eighteens. But we want it and kill it. Pascal's. So we're gonna need to Finberg 2.29 you teens into Kill Pascal's. The conversions that one a team is 101.3 to 5 k p I. So we multiply those and we get 232 killing Pascal's for our answer

And this question. We're asked to find the pressure and millimeters of mercury of the gas inside the apparatus of the barometric pressure is 740 millimeters of Mercury H one is 30 millimeters and H two is 40 millimeters, so we take a little bit up apparatus. There's one important thing to remember, and it's that we see that the gas pressure is greater than the barometric pressure. So because of this, our pressure of gas is going to be the barometric pressure. Plus Delta P. Now, if we take a look at the apparatus, we see that the liquid on the gas side is lower than the liquid on the atmospheric side. And we can also see that the difference between these levels is actually H one. So this is the this is Delta Peak. So the pressure of the gas is rather simple, too. Calculate. Then it'll be 740 was 81. So 740 plus 30 for the pressure of the gas

Solution for the given partner. Okay, Sorry for the number of moles. First with this all for the number of moles and is equal to 2.4 grand. Divided by 4.3 grand for more is he went to 0.510 more. The idea of this equation is given by Yeah, baby is equal to N. R. G. So solving for the volume by using ideal guest questions. Yeah, not be easy to n rt. Divided by t is equal to 0.510 mold you do 0.8 to 06 later into standard atmospheric pressure divided by more into kelvin 200 plus 2 73 curving divided by 785 millimeter of one kitty into one standard. It was very pressure. Directed by 7. 60 millimeter of mercury is equal to 15.1. Later

Good day. In this question we will be solving the volume of the ideal gas. So for the idea of us we have the idea of gas equation of busy equals and R. D. Where N. Is most is equal to the mass divided by the mother mass. Therefore substituting the value and into the ideal gas equation we have PV equals M. R. D. Over them. Rearranging to fight the volume. We will get volume equals M. R. D. Over B. Um Where the mass given in the question is 1.216 g. And the idea of us constant that we will use is White serial 8-06 leader atmosphere for more Calvin multiplied by the temperature given she's 80 ending result is Last 2 73 to convert in Galvin divided by the pressure given In 755 mm h.g. Where we need to convert it into atmosphere to cancel at the atmosphere in the ideal gas gone stunt, which is what A. T. M. Is 760 m. M. H. G, well deployed by the mother must given of 64.1 kilograms. Particular mold is also equal to 64.1 in grams per mole, solving for the volume we have, volume is equal to point 456 leaders. Thank you.


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