5

(a} f(c) = 3V2+ 3(b} s(&} C02 & 5&in & + &esgec2 (c} f(} = 3e" + 5...

Question

(a} f(c) = 3V2+ 3(b} s(&} C02 & 5&in & + &esgec2 (c} f(} = 3e" + 5

(a} f(c) = 3V2+ 3 (b} s(&} C02 & 5&in & + &es gec2 (c} f(} = 3e" + 5



Answers

If g^{\prime}(5)=12$ and $h^{\prime}(5)=-3,$ find $f^{\prime}(5) for
$f(x)=3 g(x)-2 h(x)+3$

Hello students. In this question we have the triple point of the carbon dioxide is 216.2 double five Calvin. And we have to determine this corresponding value in the degrees integrate and in the referral. So in the degrees integrate this value will be equals 2 to 16 point double five minus 2 73. So this is equals two minus or 56.45 degrees integrated. Okay and in the degree ferret, this temperature in the degree fairer will be equals to the nine by five. More. Popular by T plus 32. Okay so this will be equals to the nine by five March blurb temperature. This is in the degrees centigrade. Okay so this is minus 56.45 plus 32. So after solving this temperature in the degree ferret will be equals two minus of 69.61 degree Farrah. Okay so from the given options we can find that both are negatives option B is answered here. Thank you.

Okay, So for this question, we're asked to find F time at five. So let's start by taking on irritable s threats of time of accessible to three times G prime of X minus two times each time of X. So that's able to do three times Jeep time at five, when it's two times each time at five. So we have what g prime of five is. That's 12. So that's three times 12 minus two times three. So it gives me and 36 minus six, which is good too dirty.

Okay, So for part eight, this is going to be a two by two matrix or he is going to be a three by three matrix parts. He's like to be an undefined on defined because it's simply not possible harpies going to be a two by three Matrix party's going to be three by two Matrix Heart F is going to be a three by three matrix, part G. The party's also going to be undefined, but it's simply not possible. Undefined on party. I don't know howto do off its top party. Her H is going to be a three by two matrix.

We need to simplify and C five Let's do in two and c. four Plus n. c. three. We can write this expression as and c. three Plus n. c. four plus N. C. Four plus N. C. Fight Now there is a very important form line, binomial Kiram, normal corruptions the phone like this. It's er less N C. R plus one is equal to M plus one C. R. Plus one. They use this phone. So what will be n. c. three less n. c. four. It will be N plus one C three plus one which is four Because our is three. Likewise what will be n. c. four Plus NC. five. It will be N plus one C 4% which is five. So that means this bracket These and plus one c. 4 and the second bracket is N plus one C five. Now again we can apply the same formula but instead of N it's N plus one. So that means this becomes impossible because when you represent with them, plus one in the above formula becomes, and plus once we are plus endless one, C r plus one is going to end plus to see our plus one, So they should become in place to see 4 1st 1, which is fun. So the answer is and plus to c. five.


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