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SpontaneousTAS onspontaneous AH= TASthe follornng diagram on theSVL5TemperatureHV...

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SpontaneousTAS onspontaneous AH= TASthe follornng diagram on theSVL5TemperatureHV

Spontaneous TAS onspontaneous AH= TAS the follornng diagram on the SVL 5 Temperature HV



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(A): $\mathrm{CF}_{4}$ and $\mathrm{NF}_{5}$ carnot be hydrolyzed. (R): Carhon and nirrogcn borh do nor have vacanr si-orbiral.

So the question wants us to produce the conditions under which, dear, it's reaction. Spontaneous city's expense. It's a high temperature, Low temperature. Oh, hot. Uh, no. Santa chair. What's hot temperatures? So this reaction way comes in the number off gas molecules. Some reactions. I convinced a number of gas pickers. So we're going from one Thio CEO. So the entropy change here is negative. Thio, uh, this reaction is, uh, it's gonna be spontaneous that no attempt to care. So this this punching yourself in boats in Joe, guess what? No, Jim, especially when you're going from gas to liquid darkness, you condense, and so you need low temperature being green from so leads to gas that this is going from there to one. So this will be spontaneous. That's high temperature, I guess. In Hampshire, nights in jail, you're going from, uh, from each to gas. Thio, I did you not to guess that this is from 1 to 1. So, uh, it's gonna respond to us. That's high temperature. I guess It's an end. Atomic reaction. Say that's a chair in the last one. Um, we're also on end atomic reaction. So on, then. Look at entropy. Change. This is one one. Once every girl wants it too. This is spontaneous of high temperature. Here

Here we are just giving a series of rate constants. And then again, thes have been calculated about five different temperatures. So we are calculating several different values based on the information provided to us. We're calculating our activation energy. RK constant Delta, H, Delta, G and Delta rest. So for the benefit of our lining, I've included all of the definitions. So if you are unsure of any of thes values and what they mean exactly, then you can pause. Note them down. However, I'll just run through the values as we have calculated them. So dealt E A, which is the activation energy. We have 76.43 killer jewels per mole. Don't forget, that unit is very important to recall. R K values 1.93 times 10 to the minus five seconds to the minus one Delta H is 73.7 killer jewels per mole Delta G, which is our change in Gibbs Energy is 1 to 2.76 killer jewels Permal Last league Delta rest, which is our change in disorder is negative. North 0.15 Villagers Permal per Calvin. So if we have a negative dot asset, You can see that we are not increasing the disorder. We are in fact decreasing the disorder due to our negative delta ass. And so the process is considered unfavorable.

In this problem. We want to determine what the relationship is between the temperature and the spontaneity of a chemical reaction. Remember that when a reaction is spontaneous, there is a negative value for the change in Gibbs Free Energy, Delta G. We went to determine what happens when we change the temperature. That is when we increase or decrease it. With that lead to the reaction being more or less spontaneous, we start by examining the product of the temperature in the entropy. Delta s recall that the general trend is that as temperature increases, this leads to an increase in entropy. Delta s because remember that entropy corresponds to the amount of disorder in a system. So, for example, if we were heating solid water were ice, you become a liquid water state of change. We know that we have to increase the temperature to melt the ice. But when water is ice, the solid particles are packed very tightly and organized and have a very high amount of order in their structure. Where is liquid water as its particles moving around more freely and therefore there is less order in there the way that they are organized So as we increase the temperature, we go from MAWR order in a solid two less order in and a liquid. And so we increased disorder. And that means that we have an increase an entropy since we have more disorder in that system. So that's how we know that this relationship holds well. Now we can use that information to help us determine how changing the temperature effects that change and gives free energy. We assume that the change in entropy of the reaction system Delta H is going to be a constant value. So whether it's positive or negative, it will not. It will not change with temperature like Delta s will we? So from this relationship, we can say that increasing the temperature will also lead to an increase in Delta s. So as the temperature increases, the product of temperature and Delta s also increases. We're subtracting this large positive value because we're mount playing a large positive temperature by a positive value for Delta S, which results in a large positive value. If the temperature is high enough to make the product of the temperature in the entropy very high compared to Delta H, it will not matter whether the Delta H is positive or negative, since that is always a constant value. So therefore, when we subtract this this large positive value from a constant Delta H value. If that temperature is high enough, regardless of whether Delta ages positive or negative than Delta G, we'll always come out to be negative. And so therefore, in general, as we increase the temperature, this leads to a decrease in the change in Gibbs Free Energy. And when that when that change in temperature is high enough to make that delta G value less than zero, then it becomes spontaneous. So as we increase the temperature, we increase the likelihood of the reaction. You be spontaneous, and that is a general relationship between temperature and spontaneity of a chemical reaction.

So the standard free energy is calculated using the Gibbs handholds equation. Delta gina is equal to delta H, not minus T, delta S, not. And so our equilibrium equilibrium Delta Gino is equal to zero. Then we can solve for the temperature. So with the fast example, we sold for a temperature of 1157°C. And so for And above reaction to be spontaneous, the temperature needs to be above 1157°C. With the next example, we do the same thing. Use our gives him halt equation, sold for temperature under the assumption that Gibbs Free Energy is zero and equilibrium, We got negative 142 .5° C. Where the temperature needs to be above one negative 142.5 degrees seat for a spontaneous reaction In part C. Now we get to 666°C. And so this reaction will be spontaneous at all temperatures.


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