5

The average marks of first term in Statistics test for group A is 75 and standard deviation is 0 5 and average marks of first term in Statistics test for group B is...

Question

The average marks of first term in Statistics test for group A is 75 and standard deviation is 0 5 and average marks of first term in Statistics test for group B is 85 and standard deviation IS 0,3 Use appropriale tool to compare the marks for WO group for identify the best group and conelude the FesultAge (inyears) Blood pressure103104By using the above data you found the estimate value of intercept (a) is 66.8 and slope (B)is 0,65 then interpret about intercept (a).What the measurement of corr

The average marks of first term in Statistics test for group A is 75 and standard deviation is 0 5 and average marks of first term in Statistics test for group B is 85 and standard deviation IS 0,3 Use appropriale tool to compare the marks for WO group for identify the best group and conelude the Fesult Age (inyears) Blood pressure 103 104 By using the above data you found the estimate value of intercept (a) is 66.8 and slope (B)is 0,65 then interpret about intercept (a). What the measurement of correlation analysis? discuss



Answers

The weight and systolic blood pressure of 26 randomly selected males in the age group 25 to 30 are shown below. Assume that weight and blood pressure are jointly normally distributed. a. Find a regression line relating systolic blood pressure to weight. b. Test for significance of regression using $\alpha=0.05$. c. Estimate the correlation coefficient. d. Test the hypothesis that $\rho=0,$ using $\alpha=0.05$. e. Test the hypothesis that $\rho=0,$ using $\alpha=0.05$. f. Construct a $95 \%$ confidence interval for the correlation coefficient.

Okay, So in this problem, we have to measure of blood pressure, which I'm not going to try to pronounce because I don't know how to pronounce correctly. We have the s measure and the D measure, and both of these measures are important when taking someone's blood pressure. And we're going to find some central measure central measures of these pressure. So if we want to find the mean So we're gonna noted X bar off eso for the s pressure, Uh, what do we do to finding me? We simply add everything. So 118 plus 128 plus 158 plus 96 plus 156 plus 122 plus 116 plus 136 plus 126 plus 120. So you add everything and you divide by the number of observation you have. So the number of, uh, number of numbers that you have How many observation do we have? We have 121234 56789 10 10. Observation. We divide by 10. And that will give us, um, 127.6. So 127.6. Now, if you found if you want to find the median, we need to work differently. So there's no calculation. We just need to sort everything. So what's the lowest s pressure? What's 96? I think so. We have 96. What's higher than 96? 118. Seems pretty. 116 is even lower. So 116. What's next? 118. And then 122. Followed by 126 followed by 128 followed by. Oh, I forgot one entry here. I forgot. 120. So here we have. I'm gonna rewrite this here. So 120. Uh, then 120 to 126. 128. And we left where we were before. So we have 136 156. And 158 have 56 1st and 158. So these are our sorted, uh, s pressure make sure we have 10. So 123456789 10. And the median is the value which will split that Siris in two into sets and half of our half of our values will be lower or equal to the media, and half of our values will be greater or equal to the media. So what are the first since it's a even number than a split into two sets of five and five Find the value in the center of those two centers. So 12345 So this is our first set of 512345 This is our second set of five. And what is in the middle of 120 2100 and 26. Well, if you want, you can compute it using your calculator. But the eye test is pretty easy on that one is gonna be 124. So we have the media, which is 124 and the mean, which is 127.6. Now we're going to do the same work for the D. A measure of pressure again. I don't We're not Pronounce it and I'm not gonna try. So X bar D. So for the deep pressure. And once again you just add everything up. So 80 plus 76 plus every measure until the last values 70 to 82 You divide by 10 which will give you a mean value of 73.6 73.6. Now you have the mean value for the the pressure. And once again, we need to sort in increasing or the increasing order. Uh, these value to get the second median. Eso What's the lowest pressure? I think it's 52 and once after 50 to 60. 58 followed by 64 I presume. Yes, 64. What's next? 72? Maybe? Yes. 72. Followed by 80. Oh, I forgot 76. So 70 to 76. 80 76 80. Once again, I forgot another value of Tried to go a bit too fast. Always be careful. 74 76 80. Here we go. 74 76 80. 82 88 in 90. So 82 88. 90 we have 10 value 1 10 values 123456789 10. And now we're just gonna simply divide. Our 10 are set of 10 values and two sets of five, like we did previously. So what are the first lowest value? So 12345 So 52 to 74 are the $5 value and 76 to 90 are the five great greatest values, highest values. So if you go right in the middle here, you can find the median, which is what for? Against Israel or any. But it's the middle between 74 76 which is 75 very easy to see. So here you have your measures of center 70 5 73.61 of whom, 24 127.6. And then we want to know, um, our didn't measures of center the best statistics to use with these data? What else might be better? Well, it's, um it's hard. It depends on Are you familiar with the with biology and blood pressure? I suppose I would say it's no use to compare those two measures so comparing 127 point cents and comparing 73.6 is Ah, kind of, uh, it's it doesn't make sense because they don't measure the same thing. Something as 124 and 75. They don't pretty measure the same thing. They come in pairs. So maybe you can say, like, the average blood pressure is 127.6 and 73.6 in that sample. Uh, but it would be interesting toe more interesting to see how the s pressure and the deep pressure relate to one another. So there's a low, deep pressure, uh, relate toe high or low s pressure and vice versa. So there are other tools, and the interpretation is a bit left up to you. But at first glance, you cannot use. You cannot measure. You cannot compare the two pressures using central measure because they don't represent the same thing

Question were given the output from many tab for a 99% confidence interval for the difference in mean blood pressure readings for males and females and were asked to verify these results by calculating them ourselves. So I've put the samples from the question into excel. And so the first step is to verify the means and standard deviations so we can use the average formula for the means that equals average. And then just like the seller INGE hit, okay, And for a standard deviation equals s t d e v dot s. So this is the standard deviation for a sample. Again slept the range of cells. So for males, we have 77.38 as the mean and a standard deviation of 8.35 You can verify that this is the same as the mini tab output. We can copy and paste these formulas over to the female column and these numbers air also correct for the female. So the third thing to do is to calculate the confidence interval. And so this is a 99% confidence interval on the mean blood pressure difference for males versus females. So we'll call that mu M minus mu F in the formula. For this is the difference of the sample averages, plus or minus the critical value times the following factor. So the standard deviation of sample standard deviation for males squared or the variance fight it by the size of the male sample and the same thing for females. And we have all of these values from Excel sheet except for the critical value, and the sample sizes are you could just count them. Males is 16 females is 13. So to calculate the critical value, we first need the degrees of freedom. And since we're doing this manually, we just take the smaller sample size minus one. So that's and F minus one, which it was 12 and now, So we have. We know it's 99% confidence and degrees of freedom or 12 so we can go to the tea table and look up our critical value. That gives us 3.55 So now we can substitute all these numbers into our equation for the confidence interval. So you get following. That's common is Interval, and I believe I have these calculated manly The sheet so minus 3.78 to 16.38

We're looking at a data set of 10 men whose ages and blood pressures were recorded. And what we'd like to do is first create a scatter plot of this data. So I've done this in Excel. I've imported the data and created a scatter plot there and it looks something similar to this. All right. And then in exile, I've also gone ahead and calculated this correlation coefficient using the function equals C. O R R E L. And then in parentheses I did the X values comma and highlighted the Y values. Doing that. We get a correlation coefficient which is equal to 0.7984 which is pretty high. So because it's both positive and fairly close to one, we can say that we have a strong positive linear correlation within this data set. All right. And then to interpret this, I think it helps to draw a little bit of a trend line which looks something like this. Because what we see here is that as these X. values are increasing, we also tend to see this increase in R. Y. Values, which tells us that there is a tendency for this blood pressure to increase as a judge increases or vice versa. Right, We could say that as a judge increases, we tend to see that increase in blood pressure and this is only this tendency. There's no causation implied here, it's only the tendency for blood pressure to increase as age increases.

So we're looking at the data and we can see that the data goes from 27 all the way up to 34. And if we look at the history, Graham Instagram, uh, looks to be, you know, pretty bell shape. So we would think that this is approximately a normal distribution. Then part B were to look at the normal Quanta will plot and remember, for a normal quantum plot, you're probably not ever asked to make one long hand. I never had my students do that. But you are looking at those values and you're hoping that you're seeing some linearity and so approximately linear. Therefore, the tendency is for the distribution to be approximately normal, not perfect, but not too bad. Then we want to look at on part, see what the inter quartile ranges and, uh, we need We have 50 numbers, so if you have them all listed down, um, if you put them all on your calculator, your calculator will give it all to you with 11 should put one variable stat. But if you have 50 numbers and then you need to count to find the 25th number 26 number, and that number will be your median and that number ends up coming out to be 30. And then we have 25 numbers who are below and so 25 numbers below. If I take 25 divide it by two, I get 12.5. So there are 12 numbers here, 12 numbers there. We need the 13th number in the list counting this way, and we also will need the 13th number counting this way, this one will be our Q one and Q one comes out to be 29 and therefore Q three counting comes out to be 31. And so our inner core tell range is the difference between Q three and Q one is two. And so, in order to find where those whether we have outliers or not, we want to take the Q one, and we want to subtract away 1.5 boxes. So 29 minus three anything below 26 is going to end up being an outlier, and there are none. No low outliers, and then we need to take Q three and add on 1.5 boxes, box wits or recurs. So 31 plus three is 34 anything higher than 34 is going to be an outlier. And our highest number is 34. So there are none. There are no outliers. Yeah, we don't count those that are right at that limit. And then we need to find the Pearson uh, index. And there are two methods for finding that one is the ski Eunice, where we take the mean and subtract away the mode and then divided by the standard deviation. And I have that the, uh I mean, when I calculated was this my mode most frequently occurring number was 30 and then dividing it by the standard deviation which I had had that day to put in my calculator. And I get this as the scariness. So it is positive it's pretty close to zero. So if it's skewed, it's just a little bit skewed to the right. And if we use the second index formula, that's three times we take the mean minus the median divided by the standard deviation. And in that case, it ends up that the median and the mode are the same. So I just finished writing here. So basically three times that quantity that we had up here and this Kunis number would be 30.265 So again, if there is Kunitz, it's skewed just a little bit to the right. And so it appears that this distribution is pretty close to being a normal distribution. Not too bad. You can tell that really from the 22 earlier plots that there's not too much skin this.


Similar Solved Questions

5 answers
7. If the sample in this experiment was not totally decomposed, how would the calculated value of R be affected?
7. If the sample in this experiment was not totally decomposed, how would the calculated value of R be affected?...
5 answers
A hawk is flying horizontally Southward at an altitude of 152.0 m and at a speed of 2.40 m when he spots a slow-flying finch ahead of his current location and below his current path: At time zero, the hawk starts a dive by controlling the contact forces on him by the air so as to produce an acceleration of 5.20 m s2 in a direction 69.0 degrees below horizontally Southward for a time of 0.950 seconds.
A hawk is flying horizontally Southward at an altitude of 152.0 m and at a speed of 2.40 m when he spots a slow-flying finch ahead of his current location and below his current path: At time zero, the hawk starts a dive by controlling the contact forces on him by the air so as to produce an accelera...
5 answers
An electrochemica cell (e . voltaic cell) has two chambers connected by salt bridge. In each chamber is metal electrode (A and B) that is an active component of the electrochemical reaction, During the course of the rcaction, metal . increases in mass while melal B decreases in mass Which metal is the anode and which metal is the cathode? Which metal is positive and which negative?
An electrochemica cell (e . voltaic cell) has two chambers connected by salt bridge. In each chamber is metal electrode (A and B) that is an active component of the electrochemical reaction, During the course of the rcaction, metal . increases in mass while melal B decreases in mass Which metal is t...
5 answers
Two disks spin opposite directions shown; Without exerting any external torques_ the two objects collide together so that afterwards they spin as single object;6.00 200 emrevfsMz = 8.O0 kg Rz = 250cm 14.0 rev/sHow fast (in rev/s) will the objects be spinning after they stick together?
Two disks spin opposite directions shown; Without exerting any external torques_ the two objects collide together so that afterwards they spin as single object; 6.00 200 em revfs Mz = 8.O0 kg Rz = 250cm 14.0 rev/s How fast (in rev/s) will the objects be spinning after they stick together?...
5 answers
Los puntos crfticos de (6) EncuentreF(x,Y)BAJO CONDICIONZ25
los puntos crfticos de (6) Encuentre F(x,Y) BAJO CONDICIONZ 25...
5 answers
The ratio of the speed of sound in nitrogen gas to that in helium gas, at $300 mathrm{~K}$ is:(a) $frac{sqrt{3}}{5}$(b) $frac{sqrt{7}}{5}$(c) $frac{sqrt{3}}{7}$(d) $frac{sqrt{7}}{3}$
The ratio of the speed of sound in nitrogen gas to that in helium gas, at $300 mathrm{~K}$ is: (a) $frac{sqrt{3}}{5}$ (b) $frac{sqrt{7}}{5}$ (c) $frac{sqrt{3}}{7}$ (d) $frac{sqrt{7}}{3}$...
5 answers
Ican be shoan thatUse thbs Iacl (and I04 operatons) = Ind *, and "z Ihal satisty Ihe equation'Shoon AnsIro51n6CnereinsuiknClneclicck Nisatr
Ican be shoan that Use thbs Iacl (and I04 operatons) = Ind *, and "z Ihal satisty Ihe equation 'Sho on Ans Iro51n6 Cnereinsuikn Clne clicck Nisatr...
5 answers
F(z) 8x2 3)" (52? 3)13 f' (2)
f(z) 8x2 3)" (52? 3)13 f' (2)...
1 answers
A family ice show is held in an cnclosed arcna. The skaters perform to music with a sound level of $80.0 \mathrm{~dB}$. This is too loud for your baby, who consequently yells at a level of $75.0 \mathrm{~dB}$. (a) What total sound intensity engulfs you? (b) What is the combined sound level?
A family ice show is held in an cnclosed arcna. The skaters perform to music with a sound level of $80.0 \mathrm{~dB}$. This is too loud for your baby, who consequently yells at a level of $75.0 \mathrm{~dB}$. (a) What total sound intensity engulfs you? (b) What is the combined sound level?...
1 answers
Using the VSEPR model, predict which atoms pointed by an arrow have $\mathrm{SP}^{2}$ hybridisation. (Note: not all the lone pair electrons are displayed) (a) $\mathrm{i}, \mathrm{ii}, \mathrm{iv}$, viii (b) $\mathrm{i}, \mathrm{i} \mathrm{i}, \mathrm{v}, \mathrm{vii}$ (c) ii, iii, $\mathrm{v}, \mathrm{vii}$ (d) ii, $\mathrm{iv}, \mathrm{v}$, viii
Using the VSEPR model, predict which atoms pointed by an arrow have $\mathrm{SP}^{2}$ hybridisation. (Note: not all the lone pair electrons are displayed) (a) $\mathrm{i}, \mathrm{ii}, \mathrm{iv}$, viii (b) $\mathrm{i}, \mathrm{i} \mathrm{i}, \mathrm{v}, \mathrm{vii}$ (c) ii, iii, $\mathrm{v}, \mat...
4 answers
2. (28pts) Identify the_critical values which define the rejection regions for these alternate hypotheses, which may or may not have two tails (2 decimal places):Use t~-distribution: (Zpts) Ha: p # 150,n=80, 0-0.10 b. (Zpts) Ha: / < 40, n=10,0-0.01left tail: left tail:right tail: right tail:Use Z-distribution: (Zpts) Ha: 4 >-0.10,n-20,&-0.20 d. (Zpts) Ha: H # 6.5, n-40,0-0.04left tail: left tail:right tail: right tail:
2. (28pts) Identify the_critical values which define the rejection regions for these alternate hypotheses, which may or may not have two tails (2 decimal places): Use t~-distribution: (Zpts) Ha: p # 150,n=80, 0-0.10 b. (Zpts) Ha: / < 40, n=10,0-0.01 left tail: left tail: right tail: right tail: U...
5 answers
Which reagents_ when combined with an acyl chloride, form an alcohol? Select all that apply.CrOz H,SO4 H,oDIBAL H, tbcu H,oNaBH, & MeOHLiAlHy, tbe H,o
Which reagents_ when combined with an acyl chloride, form an alcohol? Select all that apply. CrOz H,SO4 H,o DIBAL H, tbcu H,o NaBH, & MeOH LiAlHy, tbe H,o...
5 answers
A vector has an X component of 10.6 units and y component of 55.1 units. Find the magnitudeof this vector:Answer:Answer
A vector has an X component of 10.6 units and y component of 55.1 units. Find the magnitudeof this vector: Answer: Answer...
1 answers
Divide, and then simplify, if possible. See Example 8. $$ (y+4) \div \frac{y^{2}+8 y+16}{a b} $$
Divide, and then simplify, if possible. See Example 8. $$ (y+4) \div \frac{y^{2}+8 y+16}{a b} $$...
5 answers
Design a reasonable synthesis for the following:HO"Note:can use onlyinorganic reagentsYour Answer:please answer the following question based on pericyclic, radical, or polymerization principles Design an appropriate synthesis (a series of steps with respective reagents to go from the reactants to the products )
Design a reasonable synthesis for the following: HO" Note:can use onlyinorganic reagents Your Answer: please answer the following question based on pericyclic, radical, or polymerization principles Design an appropriate synthesis (a series of steps with respective reagents to go from the reacta...
1 answers
Find the limits in Exercises $51-66$ $$ \lim _{x \rightarrow 0^{+}} x(\ln x)^{2} $$
Find the limits in Exercises $51-66$ $$ \lim _{x \rightarrow 0^{+}} x(\ln x)^{2} $$...
1 answers
Use a graphing utility to graph the rotated conic. $r=\frac{6}{2+\sin (\theta+\pi / 6)} \quad$ (See Exercise 21.)
Use a graphing utility to graph the rotated conic. $r=\frac{6}{2+\sin (\theta+\pi / 6)} \quad$ (See Exercise 21.)...
5 answers
11 Arrange conformations A-D in order of decreasing stability, starting with most stable:
11 Arrange conformations A-D in order of decreasing stability, starting with most stable:...

-- 0.019728--