5

16. Consider the cell diagram below:Mgis) MgSOa (0.40 M) | | NiSOa (0.60 M) Nits)Calculate the cell potential at 25*CHow does the cell potential change when (a) the...

Question

16. Consider the cell diagram below:Mgis) MgSOa (0.40 M) | | NiSOa (0.60 M) Nits)Calculate the cell potential at 25*CHow does the cell potential change when (a) the Mg2+ concentration is decreased by a factor of 4 and (b) the Ni2+ concentration is decreased by a factor of 3?

16. Consider the cell diagram below: Mgis) MgSOa (0.40 M) | | NiSOa (0.60 M) Nits) Calculate the cell potential at 25*C How does the cell potential change when (a) the Mg2+ concentration is decreased by a factor of 4 and (b) the Ni2+ concentration is decreased by a factor of 3?



Answers

Consider the concentration cell shown below. Calculate the cell potential at $25^{\circ} \mathrm{C}$ when the concentration of $\mathrm{Ag}^{+}$ in the compartment on the right is the following.
a. 1.0 $M$
b. 2.0 $M$
c. 0.10 $M$
d. $4.0 \times 10^{-5} M$
e. Calculate the potential when both solutions are 0.10 $M$ in $\mathrm{Ag}^{+}$ .
For each case, also identify the cathode, the anode, and the direction in which electrons flow.

I ordered an Through all parts of this particular question, it's helpful to write the nursed equation for a concentration cell. That Ernst Equation for a concentration cell is always a this form where we hav e cell is equal t cell standard, which will always be zero minus 00.5916 divided by an log of we always have the an old concentration on in the numerator and the Catholic concentration in the denominator so that we get a positive E cell where the an old compartment concentration is always the lower one and the Catholic compartment concentration is always the higher one. That way this ratio will be less than one, giving us a lot of value that is negative. And then, with this negative right here, we're going to end up with a positively cell, which is what we need for the concentration. So so then it becomes relatively easy. He self, for the 1st 1 will be zero because thes two concentrations will be one and the log of 10 So everything ends up being zero, and then for B, we've got one side with one Moeller that will be the an ode, and that's a lower concentration divided by the cathode gives us in any celeb 0.18 the 2nd 1 We now have 0.1 Moeller and one Moeller. So the 10.1 Mueller goes on top. It's smaller, divided by the one Moeller, we get a positive 0.5916 Then we have a really small one. That one's gonna go on top and be the antidote. And then one Moeller for the other compartment will be the cathode 10.26 volts. And then, if both of them are 0.1 Moeller, same thing potential will be zero. And electrons always slow from whatever we define the Catholic. I'm sorry the animal to be to whatever we define the Catholic to be.

Follow reaction in which let oxidizes in tow pp two plus and it is present in the one Mahler solution, while the copper two plus iron present in one and two tenders for minus for model solutions reduces to see you and this reaction led oxidizes toe people two plus air. It released two electrons, so it's oxidation is 0.14 world while see you two plus can the electrons reduces to see you in? It's a cooperating. It's reduction potential is 0.34 world. Combining the two equations. We will get that PB react with C U two plus forming B B two plus and copper. He not off the cell is equal toe zero point 47 world No to write the e to determine e off the self, which is equal toe e not off the cell minus 0.592 Divide by N. Log Off you, we're log up. Q Is equal toe concentration off the product, which is the concentration of the Leadon divide. By concentration of the reaction which is the concentration of the copper, so s l will be equal toe energy were in art 0.47 Work minus dividing 0.592 divided by because here and is equal toe to 0.59 to divide by two and log up. You putting the value of the legs, which is equal toe. One. Moeller and the copper concentration is one and two. Tennis poor minus four Moeller. So it is equal to 0.47 world minus 0.0 296 When we divide 0.592 by two, it is equal to 0.296 We're log up one Moeller divide by one and two tennis par minus four is equal to four. Multiplying these two values and subtracting from the 0.47 world and we multiply these two value it is equal to 0.1184 When we subtract thes value, it will be equal toe Seattle applying 35 one six world This is he up the cell now. In the second case, we have given that he off the silly zero. So what will be the concentration off the copper iron we have to determine and the concentration of the lead iron we will not change. It will be equal toe one Moeller putting this condition in the equation so we can like that easily is equal toe in Not off the cell, minus 0.59 to where n is equal toe to and log up. Q. Is equal toe the PV two plus concentration divide by See you two plus concentration so easily. Zero. We're in our cells. Zero Applying 47 world minus 0.59 To divide by two is equal to 0.0 296 and we can write this in the farm up. Log up the lead concentration is one Moeller plus Log up the sea you to less concentration, taking this value to the right side. You can also write minus zero point 47 World is equal to minus zero point 296 0.0 296 Log up. One model is equal toe. Zero less. Log up. See you to less concentration. No, we can cancel the negative sign on either side. Zero point Paul say one word is equal toe. When we multiply this value, it will be equal to zero plus log up. See you two plus concentration. We can also write question and this form they'll see you took less. Concentration is equal to taking log to the second side we can write it is the former empty log up zero applying 47 What? So the concentration of the C U two plus I am is equal toe when we take anti log. So this is equal toe two point 95 model. This is the required solution to this part of question. If the concentration of the copper ion is 2.95 models, then Essel will be equal to zero. This is the answer to the past part where this is dance second part, yeah.

There were given essentially a cell and under nonstandard conditions Where essentially the concentration of acquis re agents is not equal to one Mueller. So for this nonstandard condition, we should essentially first find you not sell so on their standard conditions. So we have this reaction. So essentially we can break down our reaction in the two parts the oxidation and reduction reaction. So in this case this is our oxidation oxidation reaction at the an ode. And a reduction reaction is the reduction of DeCroce, thai chrome it. Yeah, And we have to add six electrons here Plus 7 H20. So this is a reduction reaction that occurs at the Catholic, essentially. We can check that our reactions are correct by century having essentially charge balance and mass basically the same number of atoms on both sides. And we can see that is, and we can determine. In order for this reaction to occur, we need six moles of electrons and essentially we can write down also our reaction quotient, which is more complicated in this case. So we can write down that our reaction questions is equivalent to essentially the concentration of products over the concentration reenactments. We don't have to include liquids or solids since their concentration doesn't change significantly. Yeah. And so then we have a concentration of sierra three plus squared Over the concentration of H Plus to the 14th tower. The concentration of I- to the six power and the concentration of dichotomy. Mhm. And we already given information for this. So let's first find the reaction question. So we're giving information that the concentration of chromium three plus is 30.4 concentration I died. His 0.15 molar concentration H plus Is 0.60 molars. All the concentration of dia chromite Is equivalent to 0.02 more years. So let's applaud everything that your calculator and essentially fine in terms of concentration mm And we can essentially see that Q is about 8.96 Times 10 to the 14th. And now essentially we have to find essentially the cell potential under standard conditions before finding the cell potential under nonstandard conditions. So essentially we have to find all our information on the table and we can find that essentially the not of essentially reduction for Dick Roma is 1.33V for the china, essentially for oxidation where we basically oxidized. I died too, I too. Is he not of oxidation Is -0.54V. And which means that we can find that the not sell mm It is equivalent to 1.33 -14 is equivalent to 0.79 volts. Then e sell, our nearest equation is equivalent to 80 knots, l minus R T over n F. Natural log of cuba. And we can plug everything in. Yeah. Where end is essentially six months of electrons as was defined before and F is paradise content after this Paradise constance. And substituting everything in as well as substituting in the reaction quotation. We can find that essentially are self potential For the cell is equivalent to 0.64 folds. Yeah, and that's it.

So this problem You're with the galvanic celery extenders you're given for this government. Still, ion concentrations of the standards Still part of your astral signed on the cellphone and shell at 25 degrees C for this calorie cell. Soldiers first right down the Garland Cooper toe Cooper to place an equation involves copper in solid state Waking Wait and Plus Ireland. Three plays gender separation for and very Cooper two plus toe every two plus in Akwa State. And if we sum this to values and iron to the valve for this one is minus zero point 34 and now on the value for the cell potentially 25 degrees one applies down seven. Artistic warren, which is and this will give us available plus syrup warrant is equal to 4 to 4. So this is the standard sell foreign shell for it Still Now, we were just planning this value in this reaction equation. Five are in this Formula nine to warn if we do that, the number of difference transfer are Look you 25 years. So here this is not is the standard supper and feel because you can calculate for Hadi from the standard oxidation griffin potential values off this company cell. And then the killer is basically the ratio off the iron concentration point on the product side over that really inside to hold over the number of electrons transferred in between, um from the reactors and borders. And you can see that from here we can easily see that Cooper was converted to copper to plus let Miss Cooper have copper has donated two electrons and the story veteran sir on. Taken up by this, every three plus two off this every three plus took those three electrons to become two, if it to play sand. So that means the number of electrons that were transferred in the process is to. And that's why our value for in is also to Seoul place to a developer rent. And now we have to. I don't the log off the broader concentrations over the reactant concentrations. And here are brutes. Our goal for to place. And if you do plus And since we have to, every two players will have a Squire there for this to and and the bottom we'll have if you three bless. And since we have to every three Plus, we'll put a Squire for this one too. And since corporation solid form, it will not be included in the ratio here. So that's all we I need to plan in the formula. And if we calculate these values, will there 0.43 fold miners? We can't go despite it will be Is it a planned 17 84? And the answer will be, Is there a plan to fight to vote? So this is the sell foreign shell at 25 degrees C for the government itself, keep it.


Similar Solved Questions

5 answers
Point) Represent the function f(x) = x".8 as a power series:Cn(x - 6)" n=0
point) Represent the function f(x) = x".8 as a power series: Cn(x - 6)" n=0...
5 answers
Determine constants 4, b, €,d,eand f that will produce a quadrature formula of degree 5 where Esk) dx ag(-1)+bg(0) +cg(1)+dg(-1)+eg (0)+f &(1).
Determine constants 4, b, €,d,eand f that will produce a quadrature formula of degree 5 where Esk) dx ag(-1)+bg(0) +cg(1)+dg(-1)+eg (0)+f &(1)....
5 answers
41045149 Shete the formula confidence and interval computations rouscditg three computing decimals_ the confidenceState cotetaiaeest .018 the liters two estimate and simple random critical L values_ 5 of 17 deviation .008 liters_ containers of the M all for the 90% mean yons volume confidence
41045149 Shete the formula confidence and interval computations rouscditg three computing decimals_ the confidence State cotetaiaeest .018 the liters two estimate and simple random critical L values_ 5 of 17 deviation .008 liters_ containers of the M all for the 90% mean yons volume confidence...
5 answers
10. Question 33. peinssf let A = [xeN:* =12k + Lke N}arB = (en:x=3+1,0 € N}: Decide Wheahar / € 8 r B € A and Provz I2:06 podrs] Provte %hz? Vie € N,8 divices 9" + 2en - 1
10. Question 33. peinssf let A = [xeN:* =12k + Lke N}arB = (en:x=3+1,0 € N}: Decide Wheahar / € 8 r B € A and Provz I2: 06 podrs] Provte %hz? Vie € N,8 divices 9" + 2en - 1...
5 answers
QUESTIONpointsSavedWhich of these plants has the fastest growth rate? a. 12.0 centimeters of growth over 66 days b. 15,0 centimeters growth over 75 days 20.0 centimeters of growth over 102 days d,25.,C centimeters of growth over 130 daysQUESTION 8pointsSave AnswerFor question #6, please explain why you chose your answer: For the toolbar, press ALT+F1O (PC) or ALT+FN+FIO (Mac):ParagraphArial14px4 v 2y I * @ @ QWORDS POWERED BY TINY
QUESTION points Saved Which of these plants has the fastest growth rate? a. 12.0 centimeters of growth over 66 days b. 15,0 centimeters growth over 75 days 20.0 centimeters of growth over 102 days d,25.,C centimeters of growth over 130 days QUESTION 8 points Save Answer For question #6, please expla...
1 answers
Let. $B_{1} . B_{2}, \ldots . B_{k}$ les quarry matrices with entries in the same firld, and let $A=B_{1} \oslash B_{2}, \quad ; \dots, \quad B_{k},$ Prove that the characteristic polynomial of $A$ is the product of the characteristic polynomials of the $B_{i}$ 's.
Let. $B_{1} . B_{2}, \ldots . B_{k}$ les quarry matrices with entries in the same firld, and let $A=B_{1} \oslash B_{2}, \quad ; \dots, \quad B_{k},$ Prove that the characteristic polynomial of $A$ is the product of the characteristic polynomials of the $B_{i}$ 's....
1 answers
No respiration. Glucose is normally completely oxidized to $\mathrm{CO}_{2}$ in the mitochondria. In what circumstance can glucose be completely oxidized to $\mathrm{CO}_{2}$ in the cytoplasm?
No respiration. Glucose is normally completely oxidized to $\mathrm{CO}_{2}$ in the mitochondria. In what circumstance can glucose be completely oxidized to $\mathrm{CO}_{2}$ in the cytoplasm?...
4 answers
Find the intercepts and asymptotes, and then sketch a graph of the rational function and state the domain and range. Use a graphing device to confirm your answer.$$r(x)= rac{5 x^{2}+5}{x^{2}+4 x+4}$$
Find the intercepts and asymptotes, and then sketch a graph of the rational function and state the domain and range. Use a graphing device to confirm your answer. $$r(x)=\frac{5 x^{2}+5}{x^{2}+4 x+4}$$...
1 answers
In Exercises 13 and $14,$ complete the statement of congruence from the information given. Remember to write the statement so that corresponding parts are in order. $\triangle H N \cong \triangle\underline{?}$ (IMAGE CAN'T COPY)
In Exercises 13 and $14,$ complete the statement of congruence from the information given. Remember to write the statement so that corresponding parts are in order. $\triangle H N \cong \triangle\underline{?}$ (IMAGE CAN'T COPY)...
5 answers
7jooa7ed; 4 Adub or &,red card face card or a heart
7jooa7ed; 4 Adub or &,red card face card or a heart...
5 answers
QUESTION 24Consider the following regression model with an interaction term: 4.18 - 2.91 bc 0.015 educ 0.049 bc educ loglincome) dummy variable that takes on the value of for blue collar workers and 0 for white collar where bc is workers; educ is continuous variable of education: workers; i.e: bc-0, derive the relationship between loglincome) and educ For white collar 0 ( %& Arlal (12p0)
QUESTION 24 Consider the following regression model with an interaction term: 4.18 - 2.91 bc 0.015 educ 0.049 bc educ loglincome) dummy variable that takes on the value of for blue collar workers and 0 for white collar where bc is workers; educ is continuous variable of education: workers; i.e: bc-0...
5 answers
Solve the given initial-value problem and describe its behavior for increasingAy" - 4y' - 3y = 0,y(o) = 1,y'(0) = 5
Solve the given initial-value problem and describe its behavior for increasing Ay" - 4y' - 3y = 0, y(o) = 1, y'(0) = 5...
5 answers
Determine the molarity of a solution made by diluting 12.5 grams of fructose (C6O6H12) in enough pure water for 250 mL of solution.
Determine the molarity of a solution made by diluting 12.5 grams of fructose (C6O6H12) in enough pure water for 250 mL of solution....
5 answers
The graph of an exponential function f(r) Po a" is given, find the base value of a.(0,1.5)(3,12)0 + + ; . , +(a) a = 2(b) a =1.5(c) a = 5.25(d) a = 2.667
The graph of an exponential function f(r) Po a" is given, find the base value of a. (0,1.5) (3,12) 0 + + ; . , + (a) a = 2 (b) a =1.5 (c) a = 5.25 (d) a = 2.667...
5 answers
Question 2. Find the singularities of the function f(z) 2 (e? _ 1)-1 in the complex plane: Describe at least one nontrivial property of this set of singularities. What are the first three non-zero terms of the Laurent approximation of f(2) about 2 = 0
Question 2. Find the singularities of the function f(z) 2 (e? _ 1)-1 in the complex plane: Describe at least one nontrivial property of this set of singularities. What are the first three non-zero terms of the Laurent approximation of f(2) about 2 = 0...
5 answers
Name the IWo kinds of electric charges: State the methods of E 'electrification; Distinguish between conductors and insulators_ Distinguish between Coulomb' Law of Electrostaties and the Law of Electric Name the types of capacitors. Charges:
Name the IWo kinds of electric charges: State the methods of E 'electrification; Distinguish between conductors and insulators_ Distinguish between Coulomb' Law of Electrostaties and the Law of Electric Name the types of capacitors. Charges:...

-- 0.019476--