5

Iff(x) = In (3x? + 4x2 + x + 4), findf' (x).Select the correct answer below:In (9x2 +8x + [)9x2+8x+1 3r+r++49+8t4 In (2+4-WtrttWtllut 9r-+8+|...

Question

Iff(x) = In (3x? + 4x2 + x + 4), findf' (x).Select the correct answer below:In (9x2 +8x + [)9x2+8x+1 3r+r++49+8t4 In (2+4-WtrttWtllut 9r-+8+|

Iff(x) = In (3x? + 4x2 + x + 4), findf' (x). Select the correct answer below: In (9x2 +8x + [) 9x2+8x+1 3r+r++4 9+8t4 In (2+4- Wtrtt Wtllut 9r-+8+|



Answers

Subtract the polynomials. $$\begin{array}{rr}4.5 x^{4}-3.1 x^{2} -6.7 \\-\left(2.1 x^{4}\right. +4.4 x+1.2) \\\hline\end{array}$$

We're being asked to simplify the given expression. So the first thing we need to remove is this innermost Prem facie. And we can do that by distributing now we can at the same time also distribute to get rid of this first set of parentheses. So it's distribute that three well, three times x is three x and three times two is positive six. So then we're gonna bring down the positive four bracket X. Now let's distribute the negative three. Well, negative. Three times two is negative. Six and negative, three times negative. X is positive. Three X Now we can look for, like, terms inside that bracket. Well, we have X plus three x. Remember, the coefficient of X is one. Well, one plus three is four. So that will give us for X. So we have three x plus six plus four bracket and we have four X minus six. Now to get rid of the bracket weaken, distribute the positive for so I'm first gonna bring down three X plus six and Ellis distribute well four times for X is positive 16 x and four times negative. Six is negative. 24. So the last thing we need to do is combine any pairs of like terms. Well, the first pair of late terms we have are three x and 16 x well, three post 16 is 19 so that will give us 19 necks. Our next parallel terms are the constants positive. Six in negative 24 Well six minus 24 is negative. 18. Now that look simplified or not, it would combine our took like terms are answers fully simplified, So our final answer is 19 x minus 18.

We are adding to final meals together. So to do this, we're gonna reorganize it, were in a group, are like terms. So I got a negative three x squared that we're gonna, um, here with our positive for X squared in the second by normal, and we will group our exes together. So in the 1st 1 we've got one x second. We've got a positive eight X and then we'll do something called Combining Like Terms So negative three x where x four explored his one x wear that you can just say it's expired plus X plus eight X is nine accidents, so x squared, plus nine x.

Let's start by distributing the four x squared into the parentheses to multiply the this mano meal times this polynomial so four X squared times three x four times three is 12 and x squared times X is X to the third power. Now let's do plus endless multi the four X squared times the to four times to his aides, we get eight X squared.

We are adding the trying a meal of degree three with a binomial of degree Teoh. When adding Connell meals together, we want at least think about grouping like terms together so that we can combine them. The highest degree term is three. So starting with our X, the third's I got four X to the third in the first final meal, but no extra the thirds in the second down to X squares. Would you not have any X rays in the first polynomial? But we have a negative for expert in the second. The X is we have a five x in the first, but no axes in the second and finally are constants. We have a positive 13 in the first polynomial in a positive 22 in the second, so we can combine those I know cancer would be four x to the third minus four X squared. That's busted negative plus five x and then combine our 13 and 22 to get 35 four x cubed minus four Experts five exposed. 35


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