5

KOH CH,CH CH Br(e-U)NHNHZH'HzPdNO?CH, Ag,0 WCH; 4g,0(-m)(n-ololno( CO,CH CH NH;(p-t)3,H0H'Chch Oh H" OCH;LAIHAH,o.H"(9-h)...

Question

KOH CH,CH CH Br(e-U)NHNHZH'HzPdNO?CH, Ag,0 WCH; 4g,0(-m)(n-ololno( CO,CH CH NH;(p-t)3,H0H'Chch Oh H" OCH;LAIHAH,o.H"(9-h)

KOH CH,CH CH Br (e-U) NHNHZ H'HzPd NO? CH, Ag,0 W CH; 4g,0 (-m) (n-ol olno( CO, CH CH NH; (p-t) 3,H0H' Chch Oh H" OCH; LAIHA H,o.H" (9-h)



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHI} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ $\stackrel{\text { alc } \mathrm{KOH} / \Delta}{\longrightarrow}(\mathrm{A})$. The product $(\mathrm{A})$ is (a) $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH} \mathrm{CH}_{3}$ (b) $\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ (d)

Hello. The question is this molecule on the election of Alcala chaos gifts. So we are going to discuss it what degree without major product. We know that when alkalinity is treated with alkali cute then we get said Jeff they So in alcoholic yards faster br and hydrogen gets eliminated hydrogen. What? But in the case of hydrogen and deuterium which will be eliminated hydrogen right? Because hydrogen has that low born energy gender deuterium so hydrogen can get easily eliminated. Then the tutorial correct. So we have compounded That is CS three CD too. The edge beyond CH two and the C B three alcoholic. Yes or so. From here we are gets eliminated and here welcome positive for the understanding but now we have option then which atom gets eliminated because carbo cotton because in this reaction at alpha carbon huh? Alpha carbon high doesn't get eliminated. So with respect to this carbon content we have two alpha carbon this one and also this one and both the carbon in the boat of carbon one have very um and other have hydrogen, so which will get eliminated hydrogen. This will get eliminated because of less bone strength. So this hydrogen gets eliminated and here will buy bonds for them. So what will we get? C. D. To C. H. Double? More CH CDT.

In this question here is equal to production and or its physical to hydroxide. So the name of the compound, these production my drug site.

Hello and welcome to this video solution of numerous. You have to calculate the concentration of the NH four plus. Again in a solution that is .2 Point to Mueller and H three and .01 Mueller College. So we are having European 02 Hello of NH three and we're having point one more off here we right. KB of energy is given. So What we do is in the solution of a solution in H3 exists exists, This exists as NH 40 a trade in solution and the dissociation of NH 40 Age is as follows, which is NH four plus plus ohh minus. Right. And we have got the equilibrium constant K B KB equal to NH four plus, which minus. And we have got the concentration of NH 40 H right? And the KB value is given as 1.8 times 10 to the power of minus vibrate And here we have an H4 iron which we have to calculate and which Okay, sorry And which? And he's given a zero 01 and an H four wage 0.02 Right. Switzerland S Pyszka is obtained from the ski, which I am Right this one. So now here we calculate the Among the concentration of NH four plus iron equal to If you evaluate you will have 3.6 times 10 to the power of -5 Mueller. Right? And if you check the options, you have it in option. See, I hope this is clear to you and have a very good rest of the day. Thank you.

Yeah The solution is zero 18 Muller Q eight. 0.18 moller Q. Age. We have to find out the concentration of hydro near Mayan and concentration of who H minus I am. Okay now concentration of oh it's minus ion is equal to concentration of kiwis carries a strong el curly and each molecule K. Which will produce one or it's minus ion. So concentration avoids mine asan is equal to concentration of Q eight which is 0.18 f. Now we have to find out the concentration of high dona marta. We know KW and for that constant of water is concentration of high Dona Mayan Times concentration of 08 -1'll therefore concentration of hydro knee. Um Iron is KW divided by concentration of O. H minus iron. No the velo for Kw is 1.0 times 10 to the power negative 14 and O H minus concentration is 0.18 So concentration of high Dona man will be 5.6 times 10 to the power negative 14. So concentration of OH- is 0.18 M and concentration of his trio plus I dona my arm is 5.6 times 10 to the power negative 14.


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